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Island Recharge Problem

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Presentation on theme: "Island Recharge Problem"— Presentation transcript:

1 Island Recharge Problem
Analytical Solutions (with R = ft/day) Solution Type Head at center of island (ft) 1D confined* 1D unconfined 2D confined 20.00 21.96 *1D confined inverse solution with h(0)= 20, gives R = ft/day.

2 Unconfined version of the Island Recharge Problem
groundwater divide h ocean ocean b datum x = - L x = 0 x = L Let b = 100 ft & K = 100 ft/d so that at x=L, Kb= 10,000 ft2/day Can define an unconfined “transmissivity”: Tu = Kh

3 grid spacing decreases. x,  y IN 4000 6710E 2 1000 8243E 2
L y/2 For full area (L x 2L) IN = 8784E 2 ft3/day x/2 2L IN increases as grid spacing decreases. x,  y IN E 2 E 2 E 2 E 2

4 Let v = h2 Solve the finite difference equations for v and then solve for h as  v

5 Spreadsheets

6 Water Balance of the Unconfined Problem
Outflow terms for the Water Balance of the Unconfined Problem Qx = -K v /2 Qy = -K v /2

7 h (x) = [R (L2 - x2 )/K] + (hL)2
1D approximation for unconfined case Governing Eqn. Let v = h2 at x =0 Boundary conditions h(L) = hL = 100 100 Analytical solution for 1D “unconfined” version of the problem h2(x) = R (L2 - x2 )/K + (hL)2 h (x) = [R (L2 - x2 )/K] + (hL)2

8 h (x) = [R (L2 - x2 )/K] + (hL)2
Analytical solution for 1D “confined” version of the problem h(x) = R (L2 – x2) / 2T Analytical solution for 1D “unconfined” version of the problem h (x) = [R (L2 - x2 )/K] + (hL)2

9 h (x) = [R (L2 - x2 )/K] + (hL)2
h(x) = R (L2 – x2) / 2T “confined” h = ho at x = 0 ho = R L2 / 2T R = 2 Kb ho / L2 h (x) = [R (L2 - x2 )/K] + (hL)2 “unconfined” at x = 0; h = b + ho & hL = b  (b + ho)2 = [R L2 /K] + b2 R = (2 Kb ho / L2) + (ho2 K / L2)  To maintain the same head (ho) at the groundwater divide as in the confined system, the 1D unconfined system requires that recharge rate, R, be augmented by the term shown in blue.

10 Bottom 4 rows Assume pumping from the well where: Qwell = 0.1 IN
& IN is the inflow to the top right hand quadrant. Well -R = Qwell / {(x  y)/4} = Qwell / (a2/4) = 4 Qwell / a2

11 Q R x y y x Point source (L3/T) Distributed source (L3/T) Finite difference models simulate all sources as distributed sources; finite element models simulate all sources as point sources.

12 Gauss-Seidel Formula for Laplace Equation
SOR Formula Relaxation factor = 1 Gauss-Seidel < 1 under-relaxation >1 over-relaxation


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