1. Artificial Intelligence and Lisp Lecture 5 LiU Course TDDC65 Autumn Semester, 2010 http://www.ida.liu.se/ext/TDDC65/

2. Today's lecture Decision Trees Message-passing between agents: Searle speech-act theory Discuss lab 2c

3. Uses of Decision Trees Making a choice of action (final or tentative) Classifying a given situation Identifying the likely effects of a given situation or action (Using inverse operation) Identifying possible causes of a given situation

4. A simple example ccc bb a c redgreen blue white redgreenblue

5. A simple example ccc bb a c redgreen blue white redgreenblue outcomes terms, features

6. Evaluation of the decision tree ccc bb a c redgreen blue white redgreenblue true false true There will be five variations on this simple theme

7. Notation for the decision tree ccc bb a c redgreen blue white redgreenblue [a? [b? [c? red green] [c? blue white]] [b? [c? white red] [c? green blue]]] {[: a true][: b false][: c true]}

8. Notation for the decision tree [a? [b? [c? red green] [c? blue white]] [b? [c? white red] [c? green blue]]] {[: a true][: b false][: c true]} R Range of a is, for b and c similarly. Range ordering may be specified explicitly like here, or implicitly e.g. if the range is a finite set of integers, but it must be specified somehow. Different terms may have different range. It is not necessary that decision elements on the same level use the same term. Continuous range is also possible (but little covered here).

9. 1. Probabilities in term assignments [a? [b? [c? red green] [c? green white]] [b? [c? white red] [c? green blue]]] {[: a ] [: b ] [: c true]} -- same as R Range of a is, for b and c similarly. Evaluation: 0.65 * 0.90 red, 0.65 * 0.10 green, 0.35 * 0.90 white, 0.35 * 0.10 green 0.585 red 0.315 white 0.100 green

10. 2. Expected outcome [a? [b? [c? red green] [c? green white]] [b? [c? white red] [c? green blue]]] {[: a ] [: b ] [: c true]} -- same as R Range of a is, for b and c similarly. Evaluation: 0.65 * 0.90 red, 0.65 * 0.10 green, 0.35 * 0.90 white, 0.35 * 0.10 green 0.585 red 0.315 white 0.100 green Assign values to outcomes: red 10.000, white 4.000, green 25.000 (or put these values directly into the tree instead of the colors) Expected outcome: 5.850 + 1.260 + 2.500 = 9.610

11. 3. Probabilities in terminal elements [a? [b? [c? red green] [c? green white]] [b? [c? red] [c? green blue]]] {[: a ] [: b ] [: c true]} -- same as R Range of a is, for b and c similarly. Eval: 0.65 * 0.90 red, 0.65 * 0.10 green, 0.35 * 0.90 * 0.35 * 0.10 green 0.62280 red 0.00630 white 0.12835 green 0.24255 blue Ordering of value domain is

12. 4. Hierarchical decision trees ccc bgrey subtree a c red greenblue white redgreenblue b ed true false true

13. Notation for hierarchical dec. trees [?[a? [b? [c? red blue] [c? blue white]] [b? [c? white red] [c? red blue] ]] [d? red-rose poppy pelargonia] [d? bluebell forget-me-not violet] [d? waterlily lily-of-the-valley white-rose] :range ] specifies range order for subtree

14. Expansion of hierarchical dec. trees [?[a? [b? [c? red blue] [c? blue white]] [b? [c? white red] [c? red blue] ]] [d? red-rose poppy pelargonia] [d? bluebell forget-me-not violet] [d? waterlily lily-of-the-valley white-rose] :range ] [?[a? [b? [c? [d? red-rose poppy pelargonia] blue] [c? blue white]] [b? [c? white [d? red-rose poppy pelargonia]] [c? [d? red-rose poppy pelargonia] blue] ]] [d? red-rose poppy pelargonia] [d? bluebell forget-me-not violet] [d? waterlily lily-of-the-valley white-rose] :range ]

15. 5. Partial evaluation of decision tree [a? [b? [c? red green] [c? blue white]] [b? [c? white red] [c? green blue]]] {[: a true][: c true]} R Range of a is, for b and c similarly. Value of b is not available -- partial evaluation is a way out: [b? red blue]

16. Combo: Partial evaluation of decision tree with term probabilities and expected outcome [a? [b? [c? red green] [c? blue white]] [b? [c? white red] [c? green blue]]] {[: a ][: c true]} R Range of a is, for b and c similarly Value of b is not available -- partial evaluation is a way out: [b? :order ] Assign values to outcomes: red 10.000, white 4.000, green 25.000, blue 14.000 obtaining [b? 7.900 17.850]

17. Summary of variations Basic decision tree with definite (no probabilities) assignments of values Probabilistic assignments to terms (features) Continuous-valued outcome, expected outcome Probabilistic assignments to terminal nodes Hierarchical decision trees Incomplete assignments to terms, suggesting partial evaluation Combinations of these are also possible!

18. Operations on decision trees Plain evaluation Partial evaluation Inverse evaluation Reorganization (for more efficient interpretation) Acquisition: obtaining the discrete structure from reliable sources Learning: using a training set of expected outcomes to adjust probabilities in the tree Combining with other techniques, e.g. logic- based ones

19. Decision trees in real life In user manuals: error identification in cars, household machines, etc. 'User help' in software systems Telephone exchanges Botanic schemata Commercial decision making: insurance, finance

20. Decision trees in A.I. and robotics Current situation described as features/values From current situation to suggested action(s) (for immediate execution, or to be checked out) From current situation to extension of it (i.e., additional features/values) From current situation to predicted future situation (causal reasoning) From current situation to inferred earlier situation (reverse causal reasoning)(direct or inverse evaluation) From inferred future or past situation, to action(s) Learning is important for artificial intelligence

21. Decision trees and logic ccc bb a c redgreen blue white redgreenblue (a  b  c  red) ... (  a   b   c  red) ... (and (or -a -b -c red)(or -a -b c green)(or -a b -c blue)...)

22. Causal Nets A causal net consists of: A set of independent terms A partially ordered set of dependent terms An assignment of a dependency expression to each dependent term. (These may be decision trees) The dependency expression for a term may use independent terms, and also dependent terms that are lower than the term at hand. This means the dependency graph is not cyclic.

23. An example (due to Eugene Charniak) When my wife leaves home, she often (not always) turns on the outside light She may also turn it on when she expects a guest When nobody is home, the dog is often outside If the dog has stomach troubles, it is also often left outside If the dog is outside, I will probably hear it barking when I approach home However, possibly it does not bark, and possibly I hear another dog and think it's mine Problem: given the information I obtain when I approach the house, what is the likelyhood of my wife being at home?

24. Decision trees for dependent terms lights-are-on [noone-home? ] dog-outside [noone-home? [dog-sick? ] [dog-sick? ] ] I-hear-dog [dog-outside? ] Independent terms: noone-home, dog-sick Dependent terms: ligths-are-on, dog-outside < I-hear-dog Notation: integers represent percentages, 70 ~ 0.70 Interpretation: if no-one is home, then 70% chance that outside lights are on, 30% that they are not. If someone is home then 20% and 80% chance, respectively.

25. Decision trees, concise notation lights-are-on [noone-home? ] dog-outside [noone-home? [dog-sick? ] [dog-sick? ] ] I-hear-dog [dog-outside? ] lights-are-on [noone-home? 70% 20%] dog-outside [noone-home? [dog-sick? 80% 70%] [dog-sick? 70% 30%] ] I-hear-dog [dog-outside? 80% 10%]

26. Causal net using decision trees lights-are-on [noone-home? 70% 20%] dog-outside [noone-home? [dog-sick? 80% 70%] [dog-sick? 70% 30%] ] I-hear-dog [dog-outside? 80% 10%] This is simply a hierarchical causal net with probabilities in the terminal nodes! If the value assignments for noone-home and dog-sick are given, we can calculate the probabilities for the dependent variables. However, it is the inverse operation that we want.

27. Inverse operation Consider this simple case first: lights-are-on [noone-home? ] If it is known that lights-are-on is true, what is the probability for noone-home ? Possible combinations: lights-are-on noone-home 0.70 0.30 false 0.20 0.80 Suppose noone-home is true in 20% of overall cases, obtain: lights-are-on noone-home 0.14 0.06 false 0.16 0.64 Given lights-are-on, noone-home has 14/30 = 46.7% probability.

28. Inverse operation This will be continued at the next lecture Read these slides (from the course webpage) and the associated lecture note before that lecture (especially if you are not so familiar with probability theory)