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Pendulums Physics 202 Professor Lee Carkner Lecture 4 “The sweep of the pendulum had increased … As a natural consequence its velocity was also much greater.”

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Presentation on theme: "Pendulums Physics 202 Professor Lee Carkner Lecture 4 “The sweep of the pendulum had increased … As a natural consequence its velocity was also much greater.”"— Presentation transcript:

1 Pendulums Physics 202 Professor Lee Carkner Lecture 4 “The sweep of the pendulum had increased … As a natural consequence its velocity was also much greater.” --Edgar Allan Poe, “The Pit and the Pendulum”

2 PAL #3 SHM  Equation of motion for SHM, pulled 10m from rest, takes 2 seconds to get back to rest  x m = 10 meters, T = (4)(2) = 8 seconds   = 2  /T = 0.79   How long to get ½ back?  x = 5m  5 = 10 cos (0.79t) 

3 Consider SHM with no phase shift, when the mass is moving fastest, a)It is at the end (x m ) and acceleration is maximum (a m ) b)It is at the end (x m ) and acceleration is zero c)It is at the middle (x=0) and acceleration is maximum (a m ) d)It is at the middle (x=0) and acceleration is zero e)It is half way between the end and the middle and the acceleration is zero

4 Consider SHM with no phase shift, when the mass has the most acceleration, a)It is at the end (x m ) and velocity is maximum (v m ) b)It is at the end (x m ) and velocity is zero c)It is at the middle (x=0) and velocity is maximum (v m ) d)It is at the middle (x=0) and velocity is zero e)It is half way between the end and the middle and the velocity is zero

5 Consider SHM with no phase shift, when t=0, a)x=0, v=0, a=0 b)x=x m, v=v m, a=a m c)x=0, v=v m, a=-a m d)x=x m, v=0, a=-a m e)x=-x m, v=0, a=a m

6 Consider SHM with no phase shift, when t=(1/2)T, a)x=0, v=0, a=0 b)x=x m, v=v m, a=a m c)x=0, v=v m, a=-a m d)x=x m, v=0, a=-a m e)x=-x m, v=0, a=a m

7 Simple Harmonic Motion  x=x m cos(  t +  ) v=-  x m sin(  t +  ) a=-  2 x m cos(  t +  )  The force is represented as:  where k=spring constant= m  2

8 SHM and Energy  A linear oscillator has a total energy E, which is the sum of the potential and kinetic energies (E=U+K)   As one goes up the other goes down 

9 SHM Energy Conservation

10 Potential Energy   U=½kx m 2 cos 2 (  t+  )

11 Kinetic Energy  K=½mv 2 = ½m  2 x m 2 sin 2 (  t+  )  K = ½kx m 2 sin 2 (  t+  )  The total energy E=U+K which will give: E= ½kx m 2

12 Types of SHM   There are three types of systems that we will discuss:    Torsion Pendulum (torsion in a wire)  Each system has an equivalent for k

13 Pendulums  A mass suspended from a string and set swinging will oscillate with SHM   Consider a simple pendulum of mass m and length L displaced an angle  from the vertical, which moves it a linear distance s from the equilibrium point

14 The Period of a Pendulum  The the restoring force is:  For small angles sin   We can replace  with s/L  Compare to Hooke’s law F=-kx  k for a pendulum is (mg/L)  T=2  (L/g) ½

15 Pendulum and Gravity   A heavier mass requires more force to move, but is acted on by a larger gravitational force   Friction and air resistance need to be taken into account

16 Application of a Pendulum: Clocks  Since a pendulum has a regular period it can be used to move a clock hand   The gear is attached to weights that try to turn it   The mechanism disengages when the pendulum is in the equilibrium position and so allows the second hand to move twice per cycle 

17 Physical Pendulum   Properties of a physical pendulum depend on its moment of inertia (I) and the distance between the pivot point and the center of mass (h), specifically: T=2  (I/mgh) ½

18 Non-Simple Pendulum

19 Torsion Pendulum

20   If the disk is twisted a torque is exerted to move it back due to the torsion in the wire:    We can use this to derive the expression for the period: T=2  (I/  ) ½ 

21 Next Time  Read: 15.7-15.9  Homework: Ch 15, P: 35, 57, 89 (+1 extra not in book)


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