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IEEM 3201 One and Two-Sample Estimation Problems
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IEEM 320IEEM151 Notes 17, Page 2 Outline background point estimate: unbiased; most efficient interval estimate of mean for known and unknown variance prediction interval for known and unknown variance
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IEEM 320IEEM151 Notes 17, Page 3 Statistical Inference sample values x 1,..., x n : realizations of i.i.d. r.v.’s X 1, …, X n drawn from the population distribution of X i characterized by parameter ? (23.51,..., 47.39) from Normal ( , 2 ) ? statistical inference on parameters ? estimation (e.g., values of , , 2 ) ? hypothesis testing (e.g., H 0 : = 0.5 vs. H 1 : 0.5)
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IEEM 320IEEM151 Notes 17, Page 4 Arrangement of Material Chapter 9: parameter estimation ? Chapter 10: hypothesis testing ? underlying theory: normal distribution and 2, t, F distributions
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IEEM 320IEEM151 Notes 17, Page 5 Unbiased estimator: statistic is an unbiased estimator of parameter if Point Estimation Point estimate of a population parameter : a single value of a statistic that estimates is the sample value of statistic that estimates mean
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IEEM 320IEEM151 Notes 17, Page 6 Point Estimation Example: E(S 2 ) = 2, where V(X i ) = 2 and E(X i ) =
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IEEM 320IEEM151 Notes 17, Page 7 Point Estimation there can be many point estimators of a statistic the most efficient estimator of a parameter: an unbiased estimator of a parameter that has the smallest variance among all possible ones
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IEEM 320IEEM151 Notes 17, Page 8 Interval Estimation ? interval estimates are useful in real life ? compare two statements: “The mean life of our TVs is 5 years” and “The lives of our TVs are between 4 to 6 years”. ? want to find an interval ( L, U ) from x 1,..., x n such that L U ? a matter of believe ? e.g., Is 0.4 < P(head) < 0.6 if you get all heads on 10 flips? ? always bear statistical risk, making wrong estimation, accepting a wrong “believe”, or rejecting a true “believe”
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IEEM 320IEEM151 Notes 17, Page 9 Procedure for Interval Estimation ? determine , “the among of risk that we want to bear”, usually being 0.05 or 0.01 ? letbe two r.v.’s (statistics) such that : (1- )100% confidence interval are the lower and upper confidence limits. ? the sample values of
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IEEM 320IEEM151 Notes 17, Page 10 Known Results z 0 z /2 -z /2 1 – /2 ~ standard normal if X i ~ normal, and, by CLT, approximately so for any distribution
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IEEM 320IEEM151 Notes 17, Page 11 Known Results ~ t-distribution of n-1 degrees of freedom if X i ~ normal; and is approximately so for any distribution
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IEEM 320IEEM151 Notes 17, Page 12 where z /2 is the z-value leaving an area of /2 to the right ? a (1- )100% confidence interval of ; known Single Sample: Estimating the Mean for known
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IEEM 320IEEM151 Notes 17, Page 13 Example: n = 36; population standard deviation = 0.3; sample mean = 2.6; 95% c.i. for the population mean = ? Solution: n = 36, = 0.3 For 95% confidence interval, 1- = 0.95, = 0.05, /2 = 0.025, z /2 = z 0.025 =1.96. The 95% c.i. is Single Sample: Estimating the Mean
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IEEM 320IEEM151 Notes 17, Page 14 Single Sample: Estimating the Mean for unknown ? a (1- )100% confidence interval of ; unknown where t /2 is the t-value of v = n-1 degrees of freedom, leaving an area of /2 to the right
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IEEM 320IEEM151 Notes 17, Page 15 Solution: Example: The contents of 7 similar containers of sulfuric acid are 9.8,10.2,10.4,9.8,10.0,10.2, and 9.6 liters. Find a 95% confidence interval for the mean, assuming an normal distribution? Single Sample: Estimating the Mean Form Table A.4 for
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IEEM 320IEEM151 Notes 17, Page 16 ? Prediction Interval: the confidence interval for a new observation x 0 Prediction Interval ? X 0 independent of ? variance of X 0 - = 2 (n+1)/n
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IEEM 320IEEM151 Notes 17, Page 17 (1- )100% prediction interval of a future observation, x 0 Prediction Interval: known
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IEEM 320IEEM151 Notes 17, Page 18 Prediction Interval: unknown (1- )100% prediction interval of a future observation, x 0
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