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CE 230-Engineering Fluid Mechanics Lecture # 22-24 MOMENTUM EQUATION.

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Presentation on theme: "CE 230-Engineering Fluid Mechanics Lecture # 22-24 MOMENTUM EQUATION."— Presentation transcript:

1 CE 230-Engineering Fluid Mechanics Lecture # 22-24 MOMENTUM EQUATION

2 Time rate of change of a system extensive property = time rate of change of that property in CV + Net outflow rate of that property across CS

3 Time rate of change of system L.M.= TROC of L.M. in C.V+Net outflow of L.M.C.S. Momentum equation Select B=linear momentum=m V Therefore b = V

4 Special case: steady flow the momentum equation is Note that these are three equation LHS = all forces acting on fluid in c.v. Including body, surface and external forces

5 Applications of ME to be examined Forces on nozzles Forces on bends Forces from jets Forces on sluice gates

6 Problem 6.39 Determine the components of the force needed to hold the bend nozzle in place. V=130 ft/s Nozzle weight = 100lb

7 Problem 6.53 What if we have double nozzle? Given V’s and sizes. Q= 0.5m 3 /s Va=Vb Ra=5cm Rb=6cm

8 Forces on bends Example 6.7 z x

9 Forces resulting from jets Determine the force created by the steam jet on the blade. What if the blade was moving along x with a velocity of 100m/s

10 Force on a sluice gate

11

12 6.3 Jet dia and v are given so is weight of tank and water Need forces needed to hold tank V = 20m/s D=30mm


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