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Lecture 1(c) Marginal Analysis and Optimization. Why is it important to understand the mathematics of optimization in order to understand microeconomics?

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Presentation on theme: "Lecture 1(c) Marginal Analysis and Optimization. Why is it important to understand the mathematics of optimization in order to understand microeconomics?"— Presentation transcript:

1 Lecture 1(c) Marginal Analysis and Optimization

2 Why is it important to understand the mathematics of optimization in order to understand microeconomics? The “economic way of thinking” assumes that individuals behave as if they are “rational”. The “economic way of thinking” assumes that individuals behave as if they are “rational”. Question for the class: What does it mean to say that behavior is “rational”? Question for the class: What does it mean to say that behavior is “rational”?

3 Any Optimization problem has three elements. What do you you want? That is, what is your Objective: What do you you want? That is, what is your Objective: To become Master of the Universe (and still have a life) To become Master of the Universe (and still have a life) Control Variables: Control Variables: Hours studying economics (since econ is the key to happiness and wisdom) Hours studying economics (since econ is the key to happiness and wisdom) Constraints: Constraints: Time, energy, tolerance of mind-numbing tedium Time, energy, tolerance of mind-numbing tedium

4 The magic word: “marginal” MARGINAL ____ : The change in ____ when something else changes. MARGINAL ____ : The change in ____ when something else changes. Approximate Formula: The marginal contribution of x to y=(change in y)/(change in x) Approximate Formula: The marginal contribution of x to y=(change in y)/(change in x) Exact Formally (calculus): If y=f(x), the marginal contribution of x to y is dy/dx. Exact Formally (calculus): If y=f(x), the marginal contribution of x to y is dy/dx.

5 Example: The Benefits Studying

6 Benefits and Costs Hours Studying per Week Total Benefit (Increase in Average Annual Wage) Approx. Marginal Benefit Total CostApprox. Marginal Cost 0 $ -0 1$11.00 1$1.00 2$20.00$9.004$3.00 3$27.00$7.009$5.00 4$32.00$5.0016$7.00 5$35.00$3.0025$9.00

7 Interesting Observation Marginal Benefits decrease and marginal benefits increase. Marginal Benefits decrease and marginal benefits increase. Questions for the class Questions for the class Is this sensible? Is this sensible? Is there a certain similarity between costs and benefits? Is there a certain similarity between costs and benefits?

8 Net Benefits Hours Studying per Week Total Ben efit Approx. Margina l Benefit Total Cost Approx. Marg inal Cost Net Benefit (Total Benefit - Total Cost) 0 $ - 1$11.00 $1.00 $10.00 2$20.00$9.00$4.00$3.00$16.00 3$27.00$7.00$9.00$5.00$18.00 4$32.00$5.00$16.00$7.00$16.00 5$35.00$3.00$25.00$9.00$10.00

9 Net Benefits Hours Studying per Week Total Benefit Approx. Marginal Benefit Total CostApprox. Marginal Cost Net Benefit (Total Benefit -Total Cost) 0 $ - 1$11.00 $1.00 $10.00 2$20.00$9.00$4.00$3.00$16.00 3$27.00$7.00$9.00$5.00$18.00 4$32.00$5.00$16.00$7.00$16.00 5$35.00$3.00$25.00$9.00$10.00 3 hours is the best

10 Think About Optimization as a Sequence of Steps Hours Studying per Week Total Benefit Approx. Marginal Benefit Total CostApprox. Marginal Cost Net Benefit (Total Benefit -Total Cost) 0 $ - 1$11.00 $1.00 $10.00 2$20.00$9.00$4.00$3.00$16.00 3$27.00$7.00$9.00$5.00$18.00 4$32.00$5.00$16.00$7.00$16.00 5$35.00$3.00$25.00$9.00$10.00 If Here, Do More If Here, Do Less

11 Common Sense Conclusion If marginal benefits are greater than marginal costs, then do more. If marginal benefits are greater than marginal costs, then do more. If marginal benefits are less than marginal costs, then do less. If marginal benefits are less than marginal costs, then do less. To optimize, find the level of activity where marginal benefits with marginal costs To optimize, find the level of activity where marginal benefits with marginal costs

12 Optimal Decision Making In the Firm: A Simple Example Explicitly describe the three elements of the optimization problem Goal: Profit Maximization Goal: Profit Maximization Decision Variables: Price or Quantity Decision Variables: Price or Quantity Constraints: Constraints: On Costs: It takes stuff to make stuff and stuff isn’t free.) On Costs: It takes stuff to make stuff and stuff isn’t free.) On Revenues: Nobody will pay you an infinite amount for your stuff. On Revenues: Nobody will pay you an infinite amount for your stuff.

13 Revenue Constraints: Obvious (but useful) Definitions Total Revenue (TR): PxQ, nothing more- nothing less (and not to be confused with profit, net revenue, etc.) Total Revenue (TR): PxQ, nothing more- nothing less (and not to be confused with profit, net revenue, etc.) Marginal Revenue (MR): The change in total revenue when output changes Marginal Revenue (MR): The change in total revenue when output changes Approximated as: Change in TR/ Change in Q Approximated as: Change in TR/ Change in Q Calculus: dTR/dQ) Calculus: dTR/dQ)

14 Example QuantityPriceTotal RevenueApprox. Marginal Revenue 080 1777 26125 35153 44161 5315 6212-3

15 Cost Constraints: Obvious (but useful) defintions Total Cost Function: The relationship between Q and Costs Total Cost Function: The relationship between Q and Costs Marginal Costs: The change in TC when output changes Marginal Costs: The change in TC when output changes Approximation: MC = [Change in Total Costs]/ [Change in Output] Approximation: MC = [Change in Total Costs]/ [Change in Output] Calculus: MC=dTC/dQ Calculus: MC=dTC/dQ

16 Example: (Based on the assumption that TC=1+3Q) QuantityTCMC 01 143 273 3103 4133 5163 6193

17 Finding the Optimal Q (maybe) PriceQuantityTRMRTCMCProfit 8001 7177433 62125735 531531035 441611333 3515163 2612-3193-7 Somewhere Between These Two is Optimal

18

19 Finding the Optimal Q (maybe) PriceQuantityTRMRTCMCProfit 8001 7177433 62125735 531531035 441611333 3515163 2612-3193-7 MR >MC means Produce More MR < MC means produce less

20 It would seem that the optimal Q is between 2 and 3 Of course this makes sense since if Q MC (meaning an increase in output would raise revenue by more than costs). Of course this makes sense since if Q MC (meaning an increase in output would raise revenue by more than costs). Similarly if Q>3, then MC>MR (meaning a decrease in ouput would reduce costs by more than revenues). Similarly if Q>3, then MC>MR (meaning a decrease in ouput would reduce costs by more than revenues). This is such an important conclusion, it should be stated formally as Necessary Condition for Profit Maximization: If you produce, produce the Q such that MR=MC. This is such an important conclusion, it should be stated formally as Necessary Condition for Profit Maximization: If you produce, produce the Q such that MR=MC.

21 Question for the Class How does this principle explain what we found in the Equibase problem?

22 Optimization and the role of fixed costs From the previous example, suppose fixed costs go up by 9 so that QuantityTCMC 010 1133 2163 3193 4223 5253 6283

23 If the revenue function remains as before, we get If the revenue function remains as before, we get PriceQuantityTRMRTCMCProfit 80010-10 7177133-6 62125163-4 53153193-4 44161223-6 3515253-10 2612-3283-16

24 And the optimal solution is still Q=3 and P=$5. (Which is not great surprise since MC and MR haven’t changed.) This leads to the following IMPORTANT OBSERVATION: Fixed costs don’t effect the optimal output. This leads to the following IMPORTANT OBSERVATION: Fixed costs don’t effect the optimal output. If you think about it, this makes perfect sense: if some aspect of cost can’t be influenced by output decisions, it should be ignored. If you think about it, this makes perfect sense: if some aspect of cost can’t be influenced by output decisions, it should be ignored. Sensible though this is, one of the recurring themes of this course will be how often ignoring this fact leads to bad decisions. Sensible though this is, one of the recurring themes of this course will be how often ignoring this fact leads to bad decisions.

25 Final Note: What if Fixed Costs Can Be Eliminated? PriceQTRMRTCMCProfit 8000 717713 -6 62125163-4 53153193-4 44161223-6 It now is true that the best choice is Q=0. (Which is why I described the solutions above as “maybe”—because we didn’t fully consider “shut down “ conditions.)

26 Everything you ever needed to know about calculus (to get through FINA 6202) Consider the simple function Consider the simple functiony=6x-x2 If we calculate the value of y for various values of x, we get If we calculate the value of y for various values of x, we get x12345 y58985

27 The graph of the function would look like this As you can see both from the table and the graph, if x=3, y is at its maximum value.

28 How Calculus Helps But drawing a graph or computing a table of numbers is tedious and unreliable. One of the many good things about calculus is that it gives us a convenient way of finding the value of X that leads to the maximum (or minimum) value of Y. But drawing a graph or computing a table of numbers is tedious and unreliable. One of the many good things about calculus is that it gives us a convenient way of finding the value of X that leads to the maximum (or minimum) value of Y. The key to the whole exercise is the fact that when a function reaches it’s maximum value, the slope of the graph changes from positive to negative. (Confirm this on the graph given above.) The key to the whole exercise is the fact that when a function reaches it’s maximum value, the slope of the graph changes from positive to negative. (Confirm this on the graph given above.) Thus, we can find the critical value of X by finding the point where the slope of the graph is zero (remember, if the graph is continuous, the slope can’t go from positive to negative without passing through zero). Thus, we can find the critical value of X by finding the point where the slope of the graph is zero (remember, if the graph is continuous, the slope can’t go from positive to negative without passing through zero).

29 Now- and here’s where the calculus comes in—the derivative of a function is nothing more than a very precise measurement of the slope of the graph of the function. Now- and here’s where the calculus comes in—the derivative of a function is nothing more than a very precise measurement of the slope of the graph of the function. Thus, if we can find the value of X at which the derivative of the function is zero, we will have identified the optimal value of the function. Thus, if we can find the value of X at which the derivative of the function is zero, we will have identified the optimal value of the function. If this were a math class, we’d spend several lectures studying exactly what is meant by a derivative of a function and we’d end up with some rules for finding a derivative. If this were a math class, we’d spend several lectures studying exactly what is meant by a derivative of a function and we’d end up with some rules for finding a derivative. But since this isn’t a math class, we’ll go straight to the rules (especially since we only need a few of them and they’re very easy to remember.) But since this isn’t a math class, we’ll go straight to the rules (especially since we only need a few of them and they’re very easy to remember.)

30 Rules for finding derivatives The derivative of a constant is zero. The derivative of a constant is zero. If Y=C for all X, then dY/dX=0 If Y=C for all X, then dY/dX=0 (Which makes sense, since the graph of Y=C is a flat line and thus has a slope of zero). (Which makes sense, since the graph of Y=C is a flat line and thus has a slope of zero). The derivative of a linear function is the coefficient (the thing multiplied by the variable) The derivative of a linear function is the coefficient (the thing multiplied by the variable) If Y=bX, then dY/dX=b If Y=bX, then dY/dX=b (Which makes sense, since the slope of this function is just the coefficient.) (Which makes sense, since the slope of this function is just the coefficient.)

31 Rules for finding derivatives The rule for a “power function” is as follows The rule for a “power function” is as follows If Y=bX n, then dY/dX=nbX n-1 For example, if Y=3x 2, then dY/dX = 6X For example, if Y=3x 2, then dY/dX = 6X Notice, by the way, the rule for linear functions can be viewed as a special case of the power function rule—since x 0 =1. Notice, by the way, the rule for linear functions can be viewed as a special case of the power function rule—since x 0 =1. Notice also that the power function rule is good for evaluating functions involving quotients. For example the function Notice also that the power function rule is good for evaluating functions involving quotients. For example the function Y = 2/X can be written as Y=2X -1 and so the derivative is dY/dX=-2X -2 =-2/X 2

32 Rules for finding derivatives The derivative of a function that is the sum of several functions is the sum of the derivatives of those functions The derivative of a function that is the sum of several functions is the sum of the derivatives of those functions If Y=f(x)+g(x), If Y=f(x)+g(x),then dY/dX=df(x)/dx+dg(x)/dx dY/dX=df(x)/dx+dg(x)/dx By combining these rules we can find the derivative of any polynomial. By combining these rules we can find the derivative of any polynomial. If Y=a + bx + cx2+…+dxn, If Y=a + bx + cx2+…+dxn, then then dY/dX=b+2cX+…+ndXn-1 dY/dX=b+2cX+…+ndXn-1

33 The derivative of the product of two functions is as follows The derivative of the product of two functions is as follows If Y = f(x )g(x), If Y = f(x )g(x),then dY/dX = f(x)[dg(x)/dx]+g(x)[df(x)/dx]

34 Formal Analysis (Calculus) Let X stand for the number of hours studying Let X stand for the number of hours studying Benefits = 12X-X2 Benefits = 12X-X2 Marginal benefit = 12 - 2X Marginal benefit = 12 - 2X Cost = X2 Cost = X2 Marginal Cost = 2X Marginal Cost = 2X Setting marginal benefit = marginal cost implies 12-2X=2X or X=3 Setting marginal benefit = marginal cost implies 12-2X=2X or X=3


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