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Lecture 8. Discrete Probability Distributions David R. Merrell 90-786 Intermediate Empirical Methods for Public Policy and Management.

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Presentation on theme: "Lecture 8. Discrete Probability Distributions David R. Merrell 90-786 Intermediate Empirical Methods for Public Policy and Management."— Presentation transcript:

1 Lecture 8. Discrete Probability Distributions David R. Merrell 90-786 Intermediate Empirical Methods for Public Policy and Management

2 AGENDA Review Random Variables Binomial Process Binomial Distribution Poisson Process Poisson Distribution

3 Example 1. Flip Three Coins Sample space is HHH, HHT, HTH, THH, HTT, THT, TTH, TTT X = the number of heads, X = 0, 1, 2, 3 Probability Distribution: x0123x0123 P(x) 1/8 3/8 1/8 P(x) 0 1 2 3 1/8 2/8 3/8

4 Probability Tree Form H H H H H H H T T T T T T T 1/8

5 P(X=1) = 3/8 H H H H H H H T T T T T T T 1/8

6 Expected Value The expected value (mean) of a probability distribution is a weighted average: weights are the probabilities Expected Value: E(X) =  =  x i P(x i )

7 Calculating Expected Value E(X) = 0(1/8) + 1(3/8) + 2(3/8) + 3(1/8) = 1.5

8 Variance V(X) =    E(X-  ) 2

9 Calculating Variance:   

10 Example 2. Program Pilot--Bayes Rule Success Failure.3.7 Good Bad Good Bad.9.1.9.1.27.03.63.07

11 X = 1010 P(X = 1) = P(A) inherits probabilities Bernoulli RV

12 Application: Survey of Employment Discrimination Wall Street Journal, 1991 May 15 Pairs of equally qualified white and black applicants for entry-level positions Dichotomy: job offer or not Results: 28% of whites offered jobs 18% of blacks offered jobs

13 Bernoulli Probabilities

14 p 1-p 0 1 note long-run relative frequency interpretation Expected Value

15 Variance of a Bernoulli RV V(X) = p - p 2 = p(1-p)

16 Bernoulli Process 1 2 3 4 5 6 A sequence of independent Bernoulli trials each with probability p of taking on the value 1 Application: Examine “abandoned” buildings to see if they are in fact occupied

17 Binomial Distribution P(Y = k) =p k (1-p) n-k ; k = 0,1,..., n Count occurrences in n trials Survey 1200 buildings. How many are actually occupied?

18 Parameters Mean:  = n p Variance:   = n p q Standard Deviation: 

19 Example 3. Racial Discrimination Stermerville Public Works Department charged with racial discrimination in hiring practices 40% of the persons who passed the department’s civil service exam were minorities From this group, the Department hired 10 individuals; 2 of them were minorities. What is the probability that, if the Department did not discriminate, it would have hired 2 or fewer minorities?

20 Example 3. Solution Success: a minority is hired Probability of success: p = 0.4, if the department shows no preferences in regard to hiring minorities Number of trials, n = 10 Number of successes, x = 2 P(x  2) = 0.12 + 0.04 + 0.006 = 0.166.

21 Example 4. Probability Distribution xP(x) 00.006047 10.040311 20.120932 30.214991 40.250823 50.200658 60.111477 70.042467 80.010617 90.001573 100.000105

22 Poisson Process time homogeneity independence no clumping rate xxx 0 time Assumptions

23 Application: Toll Booth Arrival times of cars Mean arrival rate, cars per minute Busy:  cars per minute Slow:  = 0.5 cars per minute

24 Poisson Distribution Count in time period t

25 Probability Calculation

26 Poisson Mean and Variance

27 Next Time... Continuous Probability Distributions Normal Distribution


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