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N  p + e   e    e   e +  Ne *  Ne +  N  C + e   e Pu  U +  20 10 20 10 13 7 13 6 236 94 232 92 Fundamental particle decays Nuclear.

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Presentation on theme: "N  p + e   e    e   e +  Ne *  Ne +  N  C + e   e Pu  U +  20 10 20 10 13 7 13 6 236 94 232 92 Fundamental particle decays Nuclear."— Presentation transcript:

1 n  p + e   e    e   e +  Ne *  Ne +  N  C + e   e Pu  U +  20 10 20 10 13 7 13 6 236 94 232 92 Fundamental particle decays Nuclear decays Some observed decays The transition rate, W (the “Golden Rule”) of initial  final is also invoked to understand a  b+c (+  ) decays How do you calculate an “overlap” between ???

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5 It almost seems a self-evident statement: Any decay that’s possible will happen! What makes it possible? What sort of conditions must be satisfied? Total charge q conserved. J conserved.

6 probability of surviving through at least time t mean lifetime  = 1/ For any free particle (separation of space-time components) Such an expression CANNOT describe an unstable particle since Instead mathematically introduce the exponential factor:

7 then a decaying probability of surviving Note:  = ħ Also notice: effectively introduces an imaginary part to E

8 Applying a Fourier transform: still complex! What’s this represent? E distribution of the unstable state

9 Breit-Wigner Resonance Curve Expect some constant

10 EoEo EE 1.0 0.5   MAX  = FWHM When SPIN of the resonant state is included:

11 130-eV neutron resonances scattering from 59 Co Transmission  -ray yield for neutron radiative capture

12  + p elastic scattering cross-section in the region of the Δ ++ resonance. The central mass is 1232 MeV with a width  =120 MeV

13 Cross-section for the reaction e + e   anything near the Z 0 resonance plotted against cms energy

14 Cross section for the reaction B 10 +   N 14 * versus energy. The resonances indicate levels in the compound nucleus N 14 *. [Talbott and Heydenburg, Physical Review, 90, 186 (1953).]

15 Spectrum of protons scattered from Na 14 indicating its energy levels. [Bockelman et al., Physical Review, 92, 665 (1953).]

16 Resonances observed in the radiative proton capture by 23 Na. [P.W.m. Glaudemans and P.M. Endt, Nucl. Phys. 30, 30 (1962).]

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18 In general: cross sections for free body decays (not resonances) are built exactly the same way as scattering cross sections. DECAYS (2-body example) (2-body) SCATTERING except for how the “flux” factor has to be defined in C.O.M. in Lab frame: enforces conservation of energy/momentum when integrating over final states Now the relativistic invariant phase space of both recoiling target and scattered projectile

19 Number scattered per unit time = (FLUX) × N ×  total (a rate) /cm 2 ·sec A concentration focused into a small spot and small time interval density of targets size of each target Notice:  is a function of flux!

20 X Y Z Rotations Y´Y´ X´X´ = Z ´   Changes in frame of reference or point of view involve transformations of coordinate axes (or, more generally, basis set)

21 X Y Z Rotations Y´Y´ X´X´ = Z ´   x y x´ y´   

22 R =R = cos  sin  0 -sin  cos  0 0 0 1 v ´ = R v

23 X Z Y r a X´ Y´ Z´ r´r´ Translations parallel translation (no rotation) of axes r´ = r  a Vectors (and functions) are translated in the “opposite direction” as the coordinate system. How can we possibly express an operator like this as a matrix?

24 The trick involves using to cast matrix operators as exponentials where H is an operator…or matrix the unit matrix 10 0 0 ··· 0 1 0 0 0 0 1 0

25 Taylor Series (in 1-dimension) and we’ll make that connection through …and this useful limit

26 For an infinitesimal translation f (x 0 +δx)  f (x 0 ) + δx fxfx  3 i=1 Ok…but how can any matrix represent this? Imagine dividing the entire translation a into δa x = δa y = δa z = axNaxN ayNayN azNazN N f (r) x=x0x=x0 and applying this little step N times

27 making this a continuous smooth translation lim N∞N∞ iħiħ (-iħ )

28 For homework you will be asked to do the same thing for rotations i.e., show you can cast in the same form. R=R= cos  sin  0 -sin  cos  0 0 0 1 You should start from: R=R= 1  0 -  1 0 0 0 1 Later we will generalize this result to:

29 Rotation of coordinate axes by  about any arbitrary axis  ^ Rotation of the physical system within fixed coordinate axes Recall, even more fundamentally, the QM relation: Time evolution of an initial state, generated by the Hamiltonian

30 “Generator”Operator Amount of transformation Nature of the transformation p J H a  t Translation: moving linearly through space rotating through space translation through time

31 The Silver Surfer, Marvel Comics Group, 1969


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