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TEAM X Steady State Data Analysis Distillation Column By: Dr. Jim Henry 7 Oct 2003.

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Presentation on theme: "TEAM X Steady State Data Analysis Distillation Column By: Dr. Jim Henry 7 Oct 2003."— Presentation transcript:

1 TEAM X Steady State Data Analysis Distillation Column By: Dr. Jim Henry 7 Oct 2003

2 Objectives Energy Equation Analysis Steady-state analysis

3 Distillation Column

4 Heat IN

5 Distillation Column Heat IN Heat Loss, reboiler

6 Distillation Column Heat IN Heat Loss, reboiler Vacuum insulated, NO Heat loss

7 Distillation Column Heat IN Heat Loss, reboiler Heat Loss, feed area Vacuum insulated, NO Heat loss

8 Distillation Column Heat IN Heat Loss, reboiler Heat Loss, feed area Vacuum insulated, NO Heat loss Vacuum insulated, NO Heat loss

9 Distillation Column Heat IN Heat Loss, reboiler Heat Loss, feed area Heat Loss, reflux area Vacuum insulated, NO Heat loss Vacuum insulated, NO Heat loss

10 Distillation Column Heat IN Heat Loss, reboiler Heat Loss, feed area Heat Loss, reflux area Heat out, condenser Vacuum insulated, NO Heat loss Vacuum insulated, NO Heat loss

11 Some Data

12 Power readings taken to be correct

13 Energy Equation Data Q in is measured Now we can determine Q loss

14 Some Data Reboiler, at 75 o C has heat loss Trays 12 & higher, insulated and cool, have no heat loss. So Q in = Q loss 200 W = U A  T

15 Heat Loss A = 2*  *r*l + 2*  *r 2 Surface Area (A) = 0.44 m 2 found by measuring Reboiler Measure T boiler and T room (23 o C) Determine U… the heat transfer coefficient

16 Heat Loss A = 2*  *r*l + 2*  *r 2 Surface Area (A) = 0.44 m 2 found by measuring Reboiler Measure T boiler and T room (23 o C) Determine U… the heat transfer coefficient 200 W = U* 0.44 *(75-23)

17 Some Calcs So Q in = Q loss 200 W = U* 0.44 *52 = U *22.9 U = 400/22.9 = 17 W/m 2 o C

18 Some Data

19 Reboiler, at 75 o C has heat loss Trays 12 & higher, insulated and cool, have no heat loss. So same as before

20 Some Data Zoom In

21 Some Data

22 Reboiler, at 85 o C has heat loss Feed area, at 68 o C has heat loss Trays higher, insulated, have no heat loss. So Q in = Q loss 400 W = U B A B  T B + U F A F  T F

23 Some Calcs So Q in = Q loss 400 W = U *0.44 *62 + U *.1 *45 = U 31.7 U = 400/31.7 = 13 W/m 2 o C

24 Conclusions U in the range 13 - 17 W/m 2 o C

25 Conclusions U in the range 13 - 17 W/m 2 o C Power readings taken to be correct


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