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Geometric Random Variables N ~ Geometric(p) # Bernoulli trials until the first success pmf: f(k) = (1-p) k-1 p memoryless: P(N=n+k | N>n) = P(N=k) –probability.

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Presentation on theme: "Geometric Random Variables N ~ Geometric(p) # Bernoulli trials until the first success pmf: f(k) = (1-p) k-1 p memoryless: P(N=n+k | N>n) = P(N=k) –probability."— Presentation transcript:

1 Geometric Random Variables N ~ Geometric(p) # Bernoulli trials until the first success pmf: f(k) = (1-p) k-1 p memoryless: P(N=n+k | N>n) = P(N=k) –probability that we must wait k more coin flips for the first success is independent of n, the number of trials that have occurred so far

2 Previously… Conditional Probability Independence Probability Trees Discrete Random Variables –Bernoulli –Binomial –Geometric

3 Agenda Poisson Continuous random variables: –Uniform, Exponential E, Var Central Limit Theorem, Normal

4 Poisson N ~ Poisson( ) N = # events in a certain time period average rate is Ex. cars arrivals at a stop sign –average rate is 20/hr –Poisson(5) = #arrivals in a 15 min period

5 Poisson pmf: P(N=k) = e - k /k! Excel: POISSON(k,,TRUE/FALSE) =12.5 =3

6 Poisson N 1 ~Poisson( 1 ), N 2 ~Poisson( 2 ) N 1 +N 2 ~ Poisson( 1 + 2 ) Splitting: –Poisson( ) people arrive at L-stop –probability p person is south bound –Poisson(p ) people arrive at L-stop south bound

7 other slides… from Prof. Daskin’s slides

8 E and Var X random variable E[g(X)]=∑ k g(k) P(X=k) E[a X+b] = aE[X] +b Var[a X + b] = a 2 Var[X] –always X 1,…,X n random variables E[X 1 +…+ X n ] = E[X 1 ]+…+E[X n ] –always Var[X 1 +…+ X n ] = Var[X 1 ]+…+Var[X n ] –when independent E[X 1 ·X 2 ·…· X n ] = E[X 1 ]·E[X 2 ] ·…·E[X n ] –when independent

9 E, Var X~Bernoulli(p) E[X]=p, Var[X]=p(1-p) X~Binomial(N,p) E[X]=Np, Var[X]=Np(1-p) N~Geometric(p) E[N]=1/p, Var[N]=(1-p)/p 2 N~Poisson( ) E[N]=, Var[N]= X~U[a,b] E[X]=(a+b)/2, Var[X]=(b-a) 2 /12 X~Exponential( ) E[X]=1/, Var[X]=1/ 2

10 Central Limit Theorem X 1,…,X n i.i.d, µ=E[X 1 ],  2 =Var[X 1 ] independent, identically distributed S n = X 1,…,X n E[S n ]=nµ, Var[S n ] = n  2 distribution approaches shape of Normal –Normal(nµ,n  2 )

11 Normal Distribution mean=0  =1  =2  =4

12 Normal Distribution X 1 ~ N(µ 1,  1 2 ), X 2 ~ N(µ 2,  2 2 ) X 1 +X 2 ~ N(µ 1 +µ 2,  1 2 +  2 2 ) pdf, cdf NORMALDIST(x,µ, , TRUE/FALSE ) fractile / inverse cdf –p=P(X≤z) –NORMINV(p,µ,  )

13 Newsvendor Problem must decide how many newspapers to buy before you know the day’s demand q = #of newspapers to buy b = contribution per newspaper sold c = loss per unsold newspaper random variable D demand


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