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PHY 231 1 PHYSICS 231 Lecture 13: Keeping momentum Remco Zegers Walk-in hour: Tue 4-5 pm helproom BPS1248.

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Presentation on theme: "PHY 231 1 PHYSICS 231 Lecture 13: Keeping momentum Remco Zegers Walk-in hour: Tue 4-5 pm helproom BPS1248."— Presentation transcript:

1 PHY 231 1 PHYSICS 231 Lecture 13: Keeping momentum Remco Zegers Walk-in hour: Tue 4-5 pm helproom BPS1248

2 PHY 231 2 Chapter 6 Momentum & Collisions When a bullet hits the wall, its velocity is very much reduced. The wall does not move, although the force on the ball is the same as the force on the wall (Newton’s 3rd law: F wall-bullet =-F bullet-wall ). F wall-bullet =m bullet a bullet F bullet-wall =m wall a wall M bullet << M wall |a bullet |>> a wall

3 PHY 231 3 Is it only the mass??? V bullet =100 m/s V bullet =200 m/s When the bullet gets stopped in the wall, it deaccelerates from its initial velocity to 0. So, its acceleration is v bullet /  t, with  t some small time (independent of v). Second law: F wall-bullet =m bullet a bullet =m bullet v bullet /  t The force also depends on the velocity of the bullet!

4 PHY 231 4 More general…and formal. F=maNewton’s 2nd law F=m  v/  t a=  v/  t F=m(v final -v inital )/  t Define p=mv p: momentum (kgm/s) F=(p final -p initial )/  t F=  p/  t The net force acting on an object equals the change in momentum (  p) in a certain time period (  t). Since velocity is a vector, momentum is also a vector, pointing in the same direction as v.

5 PHY 231 5 Impulse F=  p/  tForce=change in (mv) per time period (  t).  p=F  tThe change in momentum equals the force acting on the object times how long you apply the force. Definition:  p=Impulse What if the force is not constant within the time period  t? tt ss ss ss F1F1 F2F2 F3F3  p=F  t=(F 1  s+F 2  s+F 3  s)= =  t(F 1  s+F 2  s+F 3  s)/  t =  tF average  p=F average  t

6 PHY 231 6 car hitting haystack car hitting wall The change in momentum (impulse) is the same, but the force reaches a much higher value when the car hits a wall!

7 PHY 231 7 Some examples A tennis player receives a shot approaching him (horizontally) with 50m/s and returns the ball in the opposite direction with 40m/s. The mass of the ball is 0.060 kg. A) What is the impulse delivered by the ball to the racket? B) What is the work done by the racket on the ball?

8 PHY 231 8 Child safety A friend claims that it is safe to go on a car trip with your child without a child seat since he can hold onto your 12kg child even if the car makes a frontal collision (lasting 0.05s and causing the vehicle to stop completely) at v=50 km/h (about 30 miles/h). Is he to be trusted?

9 PHY 231 9 question The velocity change is largest in case: AB The acceleration is largest in case:AB The momentum change is largest in case:AB The impulse is largest in case:AB

10 PHY 231 10 accident Consider the cases A and B in which a car crashes into a wall. In which case is the likelihood that the passengers are severely hurt greater?

11 PHY 231 11 Momentum p=mv F=  p/  t Impulse (the change in momentum)  p= F  t Demo: the ‘safe’ bungee jumper

12 PHY 231 12 Conservation of Momentum F 21  t = m 1 v 1f -m 1 v 1i F 12  t = m 2 v 2f -m 2 v 2i Newton’s 3rd law: F 12 =-F 21 (m 1 v 1f -m 1 v 1i )=-(m 2 v 2f -m 2 v 2i ) Rewrite: m 1 v 1i +m 2 v 2i =m 1 v 1f +m 2 v 2f p 1i +p 2i =p 1f +p 2f CONSERVATION OF MOMENTUM CLOSED SYSTEM!

13 PHY 231 13 momentum conservation

14 PHY 231 14 Moving in space An astronaut (100 kg) is drifting away from the spaceship with v=0.2 m/s. To get back he throws a wrench (2 kg) in the direction away from the ship. With what velocity does he need to throw the wrench to move with v=0.1 m/s towards the ship? a)0.1 m/s b) 0.2 m/s c) 5 m/s d) 16 m/s e) this will never work?

15 PHY 231 15 Types of collisions Inelastic collisionsElastic collisions Momentum is conserved Some energy is lost in the collision: KE not conserved Perfectly inelastic: the objects stick together. Momentum is conserved No energy is lost in the collision: KE conserved next quiz about this


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