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Chapter 15: Chemical Equilibria. Manipulating Equilibrium Expressions : N 2 (g) + 3 H 2 (g)  2 NH 3 (g) K = =5.5 x 10 5 Reversing Reactions Multiplying.

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Presentation on theme: "Chapter 15: Chemical Equilibria. Manipulating Equilibrium Expressions : N 2 (g) + 3 H 2 (g)  2 NH 3 (g) K = =5.5 x 10 5 Reversing Reactions Multiplying."— Presentation transcript:

1 Chapter 15: Chemical Equilibria

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6 Manipulating Equilibrium Expressions : N 2 (g) + 3 H 2 (g)  2 NH 3 (g) K = =5.5 x 10 5 Reversing Reactions Multiplying by a Factor

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9 Equilibrium Calculations: Your Pathway to Happiness 1.Write the equilibrium expression 2.Determine Q 1.if Q = K, it’s at equilibrium 2.if Q < K, reactants go to form products 3.if Q > K, products go to form reactants 3.Call the amount reacting “x” 4.Solve for x in the equilibrium expression 5.Use x to determine equilibrium concentrations

10 Given these initial concentrations, what will the final concentrations be when equilibrium is reached?

11 K in terms of pressure: K p vs. K c K p = K c (RT)  n  n = change in numbers of moles of gas 2 NH 3 (g) ==== N 2 (g) + 3 H 2 (g) K c = 5.8 x 10 5 K p = ------------- =

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16 LeChatelier’s Principle: Doing the math 1-Liter flask contains 0.50 mol butane and 1.25 mol isobutane (at equilibrium). 0.50 mol butane are added. What happens, and what is the result?

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