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Lecture 6 Capacitance and Capacitors Electrostatic Potential Energy Prof. Viviana Vladutescu.

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Presentation on theme: "Lecture 6 Capacitance and Capacitors Electrostatic Potential Energy Prof. Viviana Vladutescu."— Presentation transcript:

1 Lecture 6 Capacitance and Capacitors Electrostatic Potential Energy Prof. Viviana Vladutescu

2 Capacitance A conductor in electrostatic field is equipotential and charges distribute themselves on the surface such way that E=0 inside the conductor Q on the surface is producing V

3 linear dependence k=C

4 Depends on –the geometry of the conductors -the dielectric constant of the medium between conductors Capacitance (of the isolated conducting body) - is the electric charge that is added to the body per unit increase in its electric potential (is a constant of proportionality)

5 Capacitors

6

7

8 Electrolytic capacitors

9 Determine capacitance 1- assume V ab Q (in terms of V ab ) use boundary conditions 2- assume Q V ab (in terms of Q)

10 Q V ab Step 1Chose coordinate system for given geometry Step 2 Assume +Q and –Q on the conductors Step 3 Q E from D=εE=ρ s or Step 4 E Step 5 C=Q/V ab

11 Example Step 1 Step 2 Step 3

12 Step 4 Step 5

13 V ab Q Step 1Chose coordinate system for given geometry Step 2 Assume V ab between plates Step 3 V ab E D (from Laplace’s equation) Step 4 Boundary conditions at each plate conductor –dielectric boundary: ρ s Q. Step 5 C=Q/V ab

14 Example z Step 1 Step 2 V ab Step 3 Laplace’s equation to find the potential everywhere in the dielectric

15 There is no φ and z variation

16

17 Step 4

18 Q on the inner conductor Step 5

19 Series Connected Capacitors Parallel Connected Capacitors

20 Electrostatic Potential Energy

21 Electric potential at a point in an electric field is the work required to bring a unit positive charge from infinity (at reference zero potential) to that point.

22 Now suppose we want to bring Q 3 at R 13 from Q 1 and R 23 from Q 2

23 -can be negative -represents only interaction energy

24 For a group of N discrete charges at rest For a continuous charge distribution of density ρ

25 Electrostatic energy in terms of field quantities Substitute ρ And by using

26 Electrostatic Energy Density

27 Equipotential surfaces are at right angles to the electric field. Otherwise a force would act and work would be done on the path A to B.For a uniform electric field, equipotentials form planes perpendicular to the field. Along AB, W = -q∆V = zero! Example


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