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CHEN 4460 – Process Synthesis, Simulation and Optimization Dr. Mario Richard Eden Department of Chemical Engineering Auburn University Lab Lecture No.

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Presentation on theme: "CHEN 4460 – Process Synthesis, Simulation and Optimization Dr. Mario Richard Eden Department of Chemical Engineering Auburn University Lab Lecture No."— Presentation transcript:

1 CHEN 4460 – Process Synthesis, Simulation and Optimization Dr. Mario Richard Eden Department of Chemical Engineering Auburn University Lab Lecture No. 6 – Heat and Power Integration October 30, 2006 Heat and Power Integration

2 Example 1 Given the stream information below, design the MER network StreamTsTs TtTt Cp [kW/ o C] 1180402 2150404 3601803 4301052.6  T min = 10 o C

3 Example 1 – Solution  T min = 10 o C StreamTsTs TtTt Cp [kW/ o C] 1180402 2150404 3601803 4301052.6 Temperature Driving Force T H - Δ T

4 Example 1 – Solution  T min = 10 o C StreamTsTs TtTt Cp [kW/ o C] 1170302 2140304 3601803 4301052.6 Temperature Driving Force T H - Δ T IntervalTiTi T i -T i+1  Cp H -  Cp C ΔHiΔHi 1180 2170 3140 4105 560 630

5 Example 1 – Solution  T min = 10 o C StreamTsTs TtTt Cp [kW/ o C] 1170302 2140304 3601803 4301052.6 Temperature Driving Force T H - Δ T IntervalTiTi T i -T i+1  Cp H -  Cp C ΔHiΔHi 118010 217030 314035 410545 56030 6

6 Example 1 – Solution  T min = 10 o C StreamTsTs TtTt Cp [kW/ o C] 1170302 2140304 3601803 4301052.6 Temperature Driving Force T H - Δ T IntervalTiTi T i -T i+1  Cp H -  Cp C ΔHiΔHi 118010 -3 217030 2-3=-1 314035 2+4-3=3 410545 2+4-3-2.6=0.4 56030 2+4-2.6=3.4 630

7 Example 1 – Solution  T min = 10 o C StreamTsTs TtTt Cp [kW/ o C] 1170302 2140304 3601803 4301052.6 Temperature Driving Force T H - Δ T IntervalTiTi T i -T i+1  Cp H -  Cp C ΔHiΔHi 118010 -3-30 217030 2-3=-1-30 314035 2+4-3=3105 4 45 2+4-3-2.6=0.418 56030 2+4-2.6=3.4102 630

8 Example 1 – Solution Enthalpy Cascade Diagram T Cold pinch : 140 Q H min : 60 Q C min : 225

9 Example 1 – Solution HEN Grid Diagram 1 2 3 4 180 o C 150 o C 180 o C 105 o C30 o C 60 o C 40 o C 2 4 3 2.6 Cp 140 o C 150 o C 140 o C 150 o C T Cold pinch : 140 Q H min : 60 Q C min : 225

10 Example 1 – Solution HEN Grid Diagram T Cold pinch : 140 Q H min : 60 Q C min : 225 1 2 3 4 180 o C 150 o C 180 o C 105 o C30 o C 60 o C 40 o C 2 4 3 2.6 Cp 140 o C 150 o C 140 o C 105 o C 150 o C

11 Example 1 – Solution HEN Grid Diagram T Cold pinch : 140 Q H min : 60 Q C min : 225 1 2 3 4 180 o C 150 o C 180 o C 105 o C30 o C 60 o C 40 o C 2 4 3 2.6 Cp 140 o C 150 o C 140 o C 105 o C 150 o C 60 kW 160 o C H 60 kW

12 Example 1 – Solution HEN Grid Diagram T Cold pinch : 140 Q H min : 60 Q C min : 225 1 2 3 4 180 o C 150 o C 180 o C 105 o C30 o C 60 o C 40 o C 2 4 3 2.6 Cp 140 o C 150 o C 140 o C 105 o C 150 o C 60 kW 160 o C 60 kW 240 kW 195 kW C 200 kW H 90 o C 52.5 o C C 25 kW

13 Example 2 Given the stream information below, design the MER network StreamTsTs TtTt Cp [kW/ o C] 1180603 2150301 3 1352 4801405  T min = 10 o C

14 Example 2 – Solution  T min = 10 o C Temperature Driving Force T H - Δ T StreamTsTs TtTt Cp [kW/ o C] 1180603 2150301 3 1352 4801405

15 Example 2 – Solution StreamTsTs TtTt Cp [kW/ o C] 1170503 2140201 3301352 4801405 IntervalTiTi T i -T i+1  Cp H -  Cp C ΔHiΔHi 1170 2140 3135 480 550 630 720  T min = 10 o C Temperature Driving Force T H - Δ T

16 Example 2 – Solution StreamTsTs TtTt Cp [kW/ o C] 1170503 2140201 3301352 4801405 IntervalTiTi T i -T i+1  Cp H -  Cp C ΔHiΔHi 117030 21405 313555 48030 55020 63010 720  T min = 10 o C Temperature Driving Force T H - Δ T

17 Example 2 – Solution StreamTsTs TtTt Cp [kW/ o C] 1170503 2140201 3301352 4801405 IntervalTiTi T i -T i+1  Cp H -  Cp C ΔHiΔHi 1170303 214053+1-5=-1 3135553+1-2-5=-3 480303+1-2=2 550201-2=-1 630101 720  T min = 10 o C Temperature Driving Force T H - Δ T

18 Example 2 – Solution StreamTsTs TtTt Cp [kW/ o C] 1170503 2140201 3301352 4801405 IntervalTiTi T i -T i+1  Cp H -  Cp C ΔHiΔHi 117030390 214053+1-5=-1-5 3135553+1-2-5=-3-165 480303+1-2=260 550201-2=-1-20 630101 720  T min = 10 o C Temperature Driving Force T H - Δ T

19 Example 2 – Solution Enthalpy Cascade Diagram T Cold pinch : 80 Q H min : 80 Q C min : 50

20 Example 2 – Solution HEN Grid Diagram T Cold pinch : 80 Q H min : 80 Q C min : 50 1 2 3 4 180 o C 150 o C 135 o C 140 o C80 o C 30 o C 60 o C3 1 2 5 Cp 80 o C 90 o C 80 o C 90 o C

21 Example 2 – Solution HEN Grid Diagram T Cold pinch : 80 Q H min : 80 Q C min : 50 1 2 3 4 80 o C 90 o C 80 o C 90 o C 80 o C 30 o C 60 o C3 1 2 5 Cp 180 o C 150 o C 135 o C 140 o C

22 Example 2 – Solution HEN Grid Diagram T Cold pinch : 80 Q H min : 80 Q C min : 50 1 2 3 4 270 kW 134 o C H 30 kW 80 o C 90 o C 80 o C 90 o C 80 o C 30 o C 60 o C3 1 2 5 Cp 60 kW 110 o C H 50 kW 180 o C 150 o C 135 o C 140 o C

23 Example 2 – Solution HEN Grid Diagram T Cold pinch : 80 Q H min : 80 Q C min : 50 1 2 3 4 270 kW 134 o C H 30 kW 80 o C 90 o C 80 o C 90 o C 80 o C 30 o C 60 o C3 1 2 5 Cp 60 kW 110 o C H 50 kW 90 kW 35 o C 10 kW 80 o C C 50 kW 180 o C 150 o C 135 o C 140 o C


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