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Chapter 1 Object Oriented Programming. OOP revolves around the concept of an objects. Objects are crated using the class definition. Programming techniques.

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Presentation on theme: "Chapter 1 Object Oriented Programming. OOP revolves around the concept of an objects. Objects are crated using the class definition. Programming techniques."— Presentation transcript:

1 Chapter 1 Object Oriented Programming

2 OOP revolves around the concept of an objects. Objects are crated using the class definition. Programming techniques may include features such as Data abstraction. Encapsulation. Polymorphism. Inheritance. Many modern programming languages now support OOP.

3 Abstract data types An outline of the program containing its requirements should precede the coding process for a project. Then, in the later stage, the implementation may start with specific data structure. First, specify each task in terms of inputs and outputs. Be concerned with what the program should do. For example, if an item is needed to accomplish some tasks, the item is specified by the operations performed on it not by its structure. When the implementation starts, it decides which data structure to use to make the execution more efficient. An item specified in terms of operations is called an abstract data type. ADT- An abstract data type can be defined by the operations that are done on the data regardless of its type. ADT- A set of data values and associated operations that are precisely specified independent of any particular implementation. ADT- Mathematical description of an object with set of operations on the object.

4 Some information before starting You already learned that addresses of variables were assigned to pointers. However, pointers can refer to unknown locations that are accessible only through their addresses not by names. These locations must be set by the memory manager dynamically during the run of the program. To dynamically allocate and de-allocate memory, two functions are used: 1. new – takes from memory as much space as needed to store an object. Ex : p = new int; 2. delete – return the space that is accessible from p and is no longer needed. Ex : delete p; Note : an address has to be assigned to a pointer, if it can’t be the address of any location, it should be a null address, which is simply 0.

5 Chapter 3 Linked Lists

6 Linked list An array is a very useful data structure in programming languages. However, it has at least two limitations that can be overcome by using linked structure. It is a collection of nodes storing data and links (using addresses) to other nodes. A linked list is a data structure that consists of a sequence of data records such that in each record there is a field that contains a reference (i.e., a link) to the next record in the sequence. The most flexible linked structure’s implementation is by using pointers. Linked lists are among the simplest and most common data structures; they provide an easy implementation for several important abstract data structures, including stacks, queues and arrays.

7 3.1 Singly Linked Lists Linked list – a data structure that composed of nodes, each node holding some information and a pointer to another node in the list. Singly linked list – a node has a link only to its successor in the sequence of nodes in the list. Note : Only one variable is used to access any node in the list. The last node on the list can be recognized by the null pointer.

8 Example : class IntSLLNode { public: IntSLLNode() { next = 0; } IntSLLNode(int i, IntSLLNode *ptr = 0) { info = i; next = ptr; } int info; IntSLLNode *next; };

9 Now, how to create the linked list 1. Create a new node by executing the declaration and assignment : IntSLLNode *p = new IntSLLNode(10); This statement create a node on the list and make p points to it. The constructor assigns the number 10 to the info member of this node. The constructor assigns null to its next member. 2. Then any new node is included in the list by making the next member of the first node a pointer to the new node. 3. The second node is created by : p -> next = new IntSLLNode (8);

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11 Problem : The longer the linked list, the longer the chain of next s to access the nodes at the end of the list when using pointers. 1. If you missed a node in the chain, then a wrong assignment is made 2. The flexibility of using linked lists is diminished. So, other ways of accessing nodes are needed. One of them is : To keep two pointers: one to the first node(Head), and one to the last(Tail).

12 3.1.1 Insertion 1. inserting a new node at the beginning of a singly linked list

13 3.1.1 Insertion (cont’) 2. inserting a new node at the end of a singly linked list

14 Insert At the beginningInsert at the end addToTail(int el) { if (tail != 0) { // if list not empty; tail->next = new IntSLLNode(el); tail = tail->next; } else head = tail = new IntSLLNode(el); } addToHead(int el) { head = new IntSLLNode(el,head); if (tail == 0) tail = head; }


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