1. © 2009 Pearson Education, Inc. This work is protected by United States copyright laws and is provided solely for the use of instructors in teaching their courses and assessing student learning. Dissemination or sale of any part of this work (including on the World Wide Web) will destroy the integrity of the work and is not permitted. The work and materials from it should never be made available to students except by instructors using the accompanying text in their classes. All recipients of this work are expected to abide by these restrictions and to honor the intended pedagogical purposes and the needs of other instructors who rely on these materials. ConcepTest Clicker Questions Chapter 19 Physics for Scientists & Engineers with Modern Physics, 4th edition Giancoli

2. Two objects are made of the same material, but have different masses and temperatures. If the objects are brought into thermal contact, which one will have the greater temperature change? 1) the one with the higher initial temperature 2) the one with the lower initial temperature 3) the one with the greater mass 4) the one with the smaller mass 5) the one with the higher specific heat ConcepTest 19.1aThermal Contact I

3. Two objects are made of the same material, but have different masses and temperatures. If the objects are brought into thermal contact, which one will have the greater temperature change? 1) the one with the higher initial temperature 2) the one with the lower initial temperature 3) the one with the greater mass 4) the one with the smaller mass 5) the one with the higher specific heat Because the objects are made of the same material, the only difference between them is their mass. Clearly, the object with less mass will change temperature more easily because not much material is there (compared to the more massive object). ConcepTest 19.1aThermal Contact I

4. Two different objects receive the same amount of heat. Which of the following choices is NOT a reason why the objects may have different temperature changes? 1) they have different initial temperatures 2) they have different masses 3) they have different specific heats ConcepTest 19.1bThermal Contact II

5. Two different objects receive the same amount of heat. Which of the following choices is NOT a reason why the objects may have different temperature changes? 1) they have different initial temperatures 2) they have different masses 3) they have different specific heats Q = m c  T Because Q = m c  T and the objects received the same amount of heat, the only other factors are the masses and the specific heats. Although the initial temperature is certainly relevant for finding the final temperature, it does not have any effect on the temperature change  T. ConcepTest 19.1bThermal Contact II

6. ConcepTest 19.2Two Liquids 1) the cooler one 2) the hotter one 3) both the same Two equal-mass liquids, initially at the same temperature, are heated for the same time over the same stove. You measure the temperatures and find that one liquid has a higher temperature than the other. Which liquid has a higher specific heat?

7. cooler liquid lower temperature Both liquids had the same increase in internal energy, because the same heat was added. But the cooler liquid had a lower temperature change. Q = mc  TQ m  T c Because Q = mc  T, if Q and m are both the same and  T is smaller, then c (specific heat) must be bigger. ConcepTest 19.2Two Liquids 1) the cooler one 2) the hotter one 3) both the same Two equal-mass liquids, initially at the same temperature, are heated for the same time over the same stove. You measure the temperatures and find that one liquid has a higher temperature than the other. Which liquid has a higher specific heat?

8. The specific heat of concrete is greater than that of soil. A baseball field (with real soil) and the surrounding parking lot are warmed up during a sunny day. Which would you expect to cool off faster in the evening when the sun goes down? 1) the concrete parking lot 2) the baseball field 3) both cool off equally fast ConcepTest 19.3aNight on the Field

9. The specific heat of concrete is greater than that of soil. A baseball field (with real soil) and the surrounding parking lot are warmed up during a sunny day. Which would you expect to cool off faster in the evening when the sun goes down? 1) the concrete parking lot 2) the baseball field 3) both cool off equally fast The baseball field, with the lower specific heat, will change temperature more readily, so it will cool off faster. The high specific heat of concrete allows it to “retain heat” better and so it will not cool off so quickly—it has a higher “thermal inertia.” ConcepTest 19.3aNight on the Field

10. ConcepTest 19.3bNight on the Beach Water has a higher specific heat than sand. Therefore, on the beach at night, breezes would blow: 1) from the ocean to the beach 2) from the beach to the ocean 3) either way, makes no difference

11. ConcepTest 19.3bNight on the Beach Daytime l Daytime ç sun heats both the beach and the water » beach heats up faster » warmer air above beach rises » cooler air from ocean moves in underneath » breeze blows ocean  land c sand < c water Nighttime l Nighttime ç sun has gone to sleep » beach cools down faster » warmer air is now above the ocean » cooler air from beach moves out to the ocean » breeze blows land  ocean Water has a higher specific heat than sand. Therefore, on the beach at night, breezes would blow: 1) from the ocean to the beach 2) from the beach to the ocean 3) either way, makes no difference

12. ConcepTest 19.4Calorimetry 1 kg of water at 100 ° C is poured into a bucket that contains 4 kg of water at 0°C. Find the equilibrium temperature (neglect the influence of the bucket). 1) 0°C 2) 20 ° C 3) 50 ° C 4) 80 ° C 5) 100 ° C

13. cold water mass is greater smaller temperature change Because the cold water mass is greater, it will have a smaller temperature change! The masses of cold/hot have a ratio of 4:1, so the temperature change must have a ratio of 1:4 (cold/hot). ConcepTest 19.4Calorimetry 1 kg of water at 100 ° C is poured into a bucket that contains 4 kg of water at 0 ° C. Find the equilibrium temperature (neglect the influence of the bucket). 1) 0 ° C 2) 20 ° C 3) 50 ° C 4) 80 ° C 5) 100 ° C Q 1 = Q 2 m 1 c  T 1 = m 2 c  T 2  T 1  T 2 = m 2 m 1 / /

14. ConcepTest 19.5MoreCalorimetry ConcepTest 19.5More Calorimetry A 1 kg block of silver (c = 234 J/kg°C ) is heated to 100°C, then dunked in a tub of 1 kg of water (c = 4186 J/kg°C ) at 0°C. What is the final equilibrium temperature? ° 1) 0°C ° 2) between 0°C and 50°C ° 3) 50°C 4) between 50°C and 100°C 5) 100°C

15. c water >> c silver more heat to change the temperature of the water than it does to change the temperature of the silver In other words, it is much “harder” to heat the water!! Because c water >> c silver it takes more heat to change the temperature of the water than it does to change the temperature of the silver. In other words, it is much “harder” to heat the water!! Thus, the final temperature has to be closer to the initial temperature of the water. ConcepTest 19.5MoreCalorimetry ConcepTest 19.5More Calorimetry A 1 kg block of silver (c = 234 J/kg °C ) is heated to 100°C, then dunked in a tub of 1 kg of water (c = 4186 J/kg °C ) at 0°C. What is the final equilibrium temperature? 1) 0°C 2) between 0°C and 50°C 3) 50°C 4) between 50°C and 100°C 5) 100°C Q 1 = Q 2 mc 1  T 1 = mc 2  T 2  T 1  T 2 = c 2 c 1 / /

16. If you add some heat to a substance, is it possible for the temperature of the substance to remain unchanged? 1) yes 2) no ConcepTest 19.6Adding Heat

17. If you add some heat to a substance, is it possible for the temperature of the substance to remain unchanged? 1) yes 2) no Yes, it is indeed possible for the temperature to stay the same. This is precisely what occurs during a phase change—the added heat goes into changing the state of the substance (from solid to liquid or from liquid to gas) and does not go into changing the temperature! Once the phase change has been accomplished, then the temperature of the substance will rise with more added heat. ConcepTest 19.6Adding Heat Follow-up: Follow-up: Does that depend on the substance?

18. Will potatoes cook faster if the water is boiling faster? 1) yes 2) no ConcepTest 19.7Hot Potato

19. Will potatoes cook faster if the water is boiling faster? 1) yes 2) no The water boils at 100°C and remains at that temperature until all of the water has been changed into steam. Only then will the steam increase in temperature. Because the water stays at the same temperature, regardless of how fast it is boiling, the potatoes will not cook any faster. ConcepTest 19.7Hot Potato Follow-up: Follow-up: How can you cook the potatoes faster?

20. ConcepTest 19.8Water and Ice You put 1 kg of ice at 0°C together with 1 kg of water at 50°C. What is the final temperature? çL F = 80 cal/g çc water = 1 cal/g °C 1) 0°C 2) between 0°C and 50°C 3) 50°C 4) greater than 50°C

21. Q = mL f = (1000 g)  (80 cal/g) = 80,000 cal How much heat is needed to melt the ice? Q = mL f = (1000 g)  (80 cal/g) = 80,000 cal °° Q = c water m  T = (1 cal/g °C)  (1000 g)  (50°C) = 50,000 cal How much heat can the water deliver by cooling from 50°C to 0°C? Q = c water m  T = (1 cal/g °C)  (1000 g)  (50°C) = 50,000 cal Thus, there is not enough heat available to melt all the ice!! ConcepTest 19.8Water and Ice You put 1 kg of ice at 0°C together with 1 kg of water at 50°C. What is the final temperature? çL F = 80 cal/g çc water = 1 cal/g °C 1) 0°C 2) between 0°C and 50°C 3) 50°C 4) greater than 50°C Follow-up: Follow-up: How much more water at 50 ° C would you need?

22. ConcepTest 19.9Ice and Steam You put 1 kg of ice at 0 ° C together with 1 kg of steam at 100 ° C. What is the final temperature? çL F = 80 cal/g, L v = 540 cal/g çc water = 1 cal/g ° C 1) between 0 ° C and 50 ° C 2) 50 ° C 3) between 50 ° C and 100 ° C 4) 100 ° C 5) greater than 100 ° C

23. How much heat is needed to melt the ice? Q = mL f = (1000 g)  (80 cal/g) = 80,000 cal ° How much heat is needed to raise the water temperature to 100°C? Q = c water m  T = (1 cal/g °C)  (1000 g)  (100°C) = 100,000 cal 540,000 cal ° Q = c water m  T = (1 cal/g °C)  (1000 g)  (100°C) = 100,000 cal But if all of the steam turns into water, that would release 540,000 cal. Thus, some steam is left over, and the whole mixture stays at 100°C. ConcepTest 19.9Ice and Steam You put 1 kg of ice at 0°C together with 1 kg of steam at 100°C. What is the final temperature? çL F = 80 cal/g, L v = 540 cal/g çc water = 1 cal/g °C 1) between 0°C and 50°C 2) 50°C 3) between 50°C and 100°C 4) 100°C 5) greater than 100°C Follow-up: Follow-up: How much more ice would you need?

24. ConcepTest 19.10You’re in Hot Water! Which will cause more severe burns to your skin: 100°C water or 100°C steam? 1) water 2) steam 3) both the same 4) it depends...

25. 1 cal/g phase change540 cal/g Although the water is indeed hot, it releases only 1 cal/g of heat as it cools. The steam, however, first has to undergo a phase change into water and that process releases 540 cal/g, which is a very large amount of heat. That immense release of heat is what makes steam burns so dangerous. ConcepTest 19.10You’re in Hot Water! Which will cause more severe burns to your skin: 100°C water or 100°C steam? 1) water 2) steam 3) both the same 4) it depends...

26. ConcepTest 19.11Spring Break You step out of a swimming pool on a hot day, where the air temperature is 90°F. Where will you feel cooler, in Phoenix (dry) or in Philadelphia (humid)? 1) equally cool in both places 2) Philadelphia 3) Phoenix

27. In Phoenix, where the air is dry, more of the water will evaporate from your skin. This is a phase change, where the water must absorb the heat of vaporization, which it takes from your skin. That is why you feel cool as the water evaporates. ConcepTest 19.11Spring Break You step out of a swimming pool on a hot day, where the air temperature is 90°F. Where will you feel cooler, in Phoenix (dry) or in Philadelphia (humid)? 1) equally cool in both places 2) Philadelphia 3) Phoenix

28. ConcepTest 19.12Free Expansion A free expansion occurs when a valve is opened allowing a gas to expand into a bigger container. In such an expansion the temperature of the gas will: 1) increase 2) decrease 3) stay the same

29. ConcepTest 19.12Free Expansion A free expansion occurs when a valve is opened allowing a gas to expand into a bigger container. In such an expansion the temperature of the gas will: 1) increase 2) decrease 3) stay the same In such a process: W = 0 there is no object to move, Q = 0 there is no heat exchange, therefore  U = 0 by the First Law of Thermodynamics. Thus, there is no change in the temperature. Free expansion is neither adiabatic nor isothermal expansion, even though  T and Q are zero. Free expansion is an irreversible process—the gas molecules have virtually no chance of returning to the original state.

30. ConcepTest 19.13Work In the closed thermodynamic cycle shown in the P-V diagram, the work done by the gas is: 1) positive 2) zero 3) negative V P

31. ConcepTest 19.13Work In the closed thermodynamic cycle shown in the P-V diagram, the work done by the gas is: 1) positive 2) zero 3) negative The gas expands at a higher pressure and compresses at a lower pressure. In general, clockwise = positive work; counterclockwise = negative work. V P

32. ConcepTest 19.14Heat Conduction ConcepTest 19.14 Heat Conduction Given your experience of what feels colder when you walk on it, which of the surfaces would have the highest thermal conductivity? 1) a rug 2) a steel surface 3) a concrete floor 4) has nothing to do with thermal conductivity

33. ConcepTest 19.14Heat Conduction ConcepTest 19.14 Heat Conduction Given your experience of what feels colder when you walk on it, which of the surfaces would have the highest thermal conductivity? 1) a rug 2) a steel surface 3) a concrete floor 4) has nothing to do with thermal conductivity The heat flow rate is k A (T 1 − T 2 ) / l. All things being equal, bigger k leads to bigger heat loss. From the book: Steel = 40, Concrete = 0.84, Human tissue = 0.2, Wool = 0.04, in units of J/(s.m.C°).

34. ConcepTest 19.15Radiation If the Sun’s surface temperature falls to half the current surface temperature, by what factor will the radiant energy reaching the Earth change? 1) increase by factor of 16 2) increase by factor of 4 3) it will remain the same 4) decrease by factor of 4 5) decrease by factor of 16

35. ConcepTest 19.15Radiation If the Sun’s surface temperature falls to half the current surface temperature, by what factor will the radiant energy reaching the Earth change? 1) increase by factor of 16 2) increase by factor of 4 3) it will remain the same 4) decrease by factor of 4 5) decrease by factor of 16 Radiation energy is proportional to T 4. So if temperature is halved, radiation energy will decrease by a factor of 16.