2. “I am like that,” does not help anything. “I can be different,” does.

3. Basick English The bandage was wound around the wound. The farm was used to produce produce. The dump was so full that it had to refuse more refuse. The bandage was wound around the wound. The farm was used to produce produce. The dump was so full that it had to refuse more refuse.

4. A chemistry teacher was berating the students for not learning the Periodic Table of the Elements. She said, "Why when I was your age I knew both their names and weights." One kid popped up, "Yeah, but teach, there were so few of them back then.

5. Crush the can

6. Gas Laws Lesson 4

7. Scuba

8. Invented in 1943 By Jacques - Ives Cousteau and Emile Gagnan. Invented in 1943 By Jacques - Ives Cousteau and Emile Gagnan.

9. Pressure and water depth At the surface of the water the air pressure equals 1 atm. For every 10m of water you add 1 atm. At the surface of the water the air pressure equals 1 atm. For every 10m of water you add 1 atm.

10. Problem If a diver dives 40m, how much pressure is on him? 5 atm If a diver dives 40m, how much pressure is on him? 5 atm

11. Absolute zero Substance has zero kinetic energy. All movement would stop.

12. Diffusion Process by which particles of matter fill a space because of random motion. (Ex: smells in the air, food coloring in liquid) Process by which particles of matter fill a space because of random motion. (Ex: smells in the air, food coloring in liquid)

13. Evaporation Process by which particles of a liquid form a gas by escaping from the surface.

14. 3 Things that affect evaporation Temperature Surface area Humidity Temperature Surface area Humidity

15. Energy The ability to do work.

16. Heat of vaporization Energy absorbed when 1 kg of a liquid vaporizes at its normal boiling point. (The heat of vaporization of water is 2.26 x 10 6 J / kg) Energy absorbed when 1 kg of a liquid vaporizes at its normal boiling point. (The heat of vaporization of water is 2.26 x 10 6 J / kg)

17. Heat of fusion Energy released as 1 kg of a substance solidifies at its freezing point. Heat of fusion of water is 3.34 x 10 5 J/kg Energy released as 1 kg of a substance solidifies at its freezing point. Heat of fusion of water is 3.34 x 10 5 J/kg

18. Elastic collisions When a gas particle rebounds without losing speed or no K.E. is lost.

19. Fractional distillation When mixtures of air are separated into components and these components are separated by differences in their B.P. (Used in production of N 2 and O 2 and other gases.) When mixtures of air are separated into components and these components are separated by differences in their B.P. (Used in production of N 2 and O 2 and other gases.)

20. Factor Label Method Method used to convert measurements in one unit to their equivalent in a second unit.

21. Problem 1 Determine the number of moles of unknown gas if a sample occupies a volume of 148 mL at 13°C and a pressure of 107.0 kPa.

22. Work Convert ml to L 148 ml =.148 L = V 13 o C = 286 K = T P = 107.0 kPa Plug into the formula PV=nRT Convert ml to L 148 ml =.148 L = V 13 o C = 286 K = T P = 107.0 kPa Plug into the formula PV=nRT

23. Answer.0067 mol or.007 mol

24. Question What is it called when dry ice (solid carbon dioxide) changes to carbon dioxide gas? Answer: Sublimation What is it called when dry ice (solid carbon dioxide) changes to carbon dioxide gas? Answer: Sublimation

25. P 1 V 1 = P 2 V 2 What is the name of the above formula? Boyle’s Law What is the name of the above formula? Boyle’s Law

26. Problem 2 The gas left in a used aerosol can is at a pressure of 1 atm at 27 o C (room temp). If this can is thrown onto a fire, what is the internal pressure of the gas when its temperature reaches 927 o C?

27. Work Convert temp to Kelvin 27 + 273 = 300 K 927 + 273 = 1200 K 1 atm = P 2 300 K 1200K 1 atm x 1200 K 300 K Answer = 4 atm Convert temp to Kelvin 27 + 273 = 300 K 927 + 273 = 1200 K 1 atm = P 2 300 K 1200K 1 atm x 1200 K 300 K Answer = 4 atm

28. Problem 3 How many moles of helium are contained in a 5.00 L canister at 101 kPa and 30 o C?

29. Work PV = nR T 5 L x 101 kPa = n x 8.31 L x kPa x 303K mol x K Answer =.201 mol PV = nR T 5 L x 101 kPa = n x 8.31 L x kPa x 303K mol x K Answer =.201 mol