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Fault Tree Analysis Part 12 – Redundant Structure and Standby Units
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Active Redundancy The redundancy obtained by replacing the important unit with two or more units operating in parallel.
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Passive Redundancy The reserve units can also be kept in standby in such a way that the first of them is activated when the original unit fails, the second is activated when the first reserve unit fails, and so on. If the reserve units carry no load in the waiting period before activation, the redundancy is called passive. In the waiting period, such a unit is said to be in cold standby.
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Partly-Loaded Redundancy The standby units carry a weak load.
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Cold Standby, Perfect Switching, No Repairs
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Life Time of Standby System The mean time to system failure
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Exact Distribution of Lifetime If the lifetimes of the n components are independent and exponentially distributed with the same failure rate λ. It can be shown that T is gamma distributed with parameters n and λ. The survivor function is
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Approximate Distribution of Lifetime Assume that the lifetimes are independent and identically distributed with mean time to failure μ and standard deviation σ. According to Lindeberg-Levy’s central limit theorem, T will be asymptotically normally distributed with mean nμ and variance nσ^2.
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Cold Standby, Imperfect Switching, No Repairs
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2-Unit System A standby system with an active unit (unit 1) and a unit in cold standby. The active unit is under surveillance by a switch, which activates the standby unit when the active unit fails. Let be the failure rate of unit 1 and unit 2 respectively; Let (1-p) be the probability that the switching is successful.
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Two Disjoint Ways of Survival 1.Unit 1 does not fail in (0, t], i.e. 2.Unit 1 fails in the time interval (τ, τ+dτ], where 0<τ<t. The switch is able to activate unit 2. Unit 2 is activated at time τ and does not fail in the time interval (τ,t].
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Probabilities of Two Disjoint Events Event 1: Event 2: Unit 1 fails Switching successful Unit 2 working afterwards
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System Reliability
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Mean Time to Failure
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Partly-Loaded Redundancy, Imperfect Switching, No Repairs
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Two-Unit System Same as before except unit 2 carries a certain load before it is activated. Let denote the failure rate of unit 2 while in partly- loaded standby.
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Two Disjoint Ways of Survival 1.Unit 1 does not fail in (0, t], i.e. 2.Unit 1 fails in the time interval (τ, τ+dτ], where 0<τ<t. The switch is able to activate unit 2. Unit 2 does not fail in (0, τ], is activated at time τ and does not fail in the time interval (τ,t].
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Probabilities of Two Disjoint Events Event 1: Event 2: Unit 1 fails at τ Switching successful Unit 2 still working after τ Unit 2 working in (0, τ]
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System Reliability
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Mean Time to Failure
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Cold Standby, Perfect Switching, With Repairs
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Possible States of a 2-Unit System with Cold Standby and Perfect Switching System Unit AUnit B 4OS 3FO 2SO 1OF 0FF
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State Space Diagram 0 1 2 3 4
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State Equations
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Eliminating the Failed State
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Laplace Transform Substitute s=0 Note that
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Solution
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Mean Time to Failure
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Take Laplace transform of R(t) Substitute s=0
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Mean Time to Failure
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Cold Standby, Perfect Switching, With Repairs, A Main Operating Unit
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Possible States System Unit A (Main Unit) Unit B 4OS 3FO 2SO 1OF 0FF
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State Space Diagram 0 3 4
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State Equations Where
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Steady State Probabilities
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Availability and Unavailability
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Eliminate Failed State from State Equations Where
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Treating State 0 as An Absorbing State Take Laplace transform and let s=0 Solution
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Mean Times to Failure and to Repair Mean time to failure Mean time to repair
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Cold Standby, Imperfect Switching, With Repairs, A Main Operating Unit
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State Space Diagram 0 3 4
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Steady State Probabilities
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Availability and Unavailability
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Mean Time to Failure
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Partly-Loaded Standby, Perfect Switching, With Repairs, A Main Operating Unit
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Possible States of a 2-Unit System with Partly-Loaded Standby and Perfect Switching System Unit AUnit B 4OS 3FO 2SO 1OF 0FF
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State Space Diagram 0 1 3 4
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Steady State Probabilities
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L Spares, With Replacements and Repairs
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State Space Diagram 0 1 2 2j2L
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Notation State 2j (j = 0, 1, …,L): A total of j spare units are in a repair queue, and (L-j) spares are normal. A failed unit in the system is being replaced by a normal spared unit, the system is working. State 2j+1 (j = 0, 1, …, L-1): A total of j spare units are in a repair queue, and (L-j) spares are normal. A failed unit in the system is being replaced by a normal spared unit, the system does not work. State 2L+1: All spares are in a repair queue. A failed unit in the system is under priority repair. This is a type of quasi-replacement.
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Notation λ: Constant failure rate μ: Constant repair rate ε: Constant replacement rate
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Steady-State State Equations
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Steady-State Availability
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