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Published byCollin Rafe Jennings Modified over 9 years ago
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Periodic inventory models – single level The objective is to minimize holding and backlog costs. Unsatisfied demand is backlogged Holding and backlog costs are convex Stationary demand If there is no setup cost for ordering Base stock (S) policy is optimal If the inventory position P t <S; order S-P t If there is a positive setup cost for ordering Re-order point, order-up-to-level (s, S) policy is optimal If the inventory position P t <s; order S-P t
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Multi-echelon systems n n-1 2 1 Ordering cost is for level i is the transportation cost from level i+1 to i Ordering cost for level n is the purchasing cost All ordering costs are linear, except at level n Backlog costs for level 1 is the backlog costs for external demand Backlog cost for level i is the cost of not being able to support level i-1 when level i-1 requested material
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Multi-echelon systems n n-1 2 1 Echelon stock for level 2 = on hand at level 2 + on hand at level 1 + on order from level 2 to level 1 Echelon inventory position for level 2 = echelon stock for level 2 + on order from level 3 to level 2 Similarly for level j If there is no setup cost for ordering Base stock (S j ) policy is optimal for each level j If the echelon inventory position P j t <S j ; order S j -P j t If there is a positive setup cost for ordering Re-order point, order-up-to-level (s j, S j ) policy is optimal for each level j If the inventory position P j t <s j ; order S j -P j t
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Tree like supply chains Warehouse Retailer 1 Supplier Retailer 2 Echelon stock for warehouse = on hand at retailer 1 + on hand at retailer 2 + on hand at warehouse + on hand at warehouse to retailers 1 & 2 Echelon inventory position for warehouse = echelon stock for warehouse on order from supplier to warehouse Assumption: no transshipments Assumption: retailer 1 and retailer 2 stocks are not seriously out of balance Base stock policy (S) for no setup case and (s, S) policy for setup case are optimal for the warehouse and retailers (using the echelon stock for warehouse)
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Minimizing inventory subject to backorders No repairs Poisson demands at bases Demand at depot = 1 + 2 Re-order point at depot = S 0 Re-order point at bases S 1, S 2 Expected number of units being delayed at the depot Depot Base 1 Supplier Base 2 D 22 11 Percentage delayed
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Minimizing inventory subject to backorders Backorders at Base j Depot Base 1 Supplier Base 2 D 22 11 Problem
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Example If the fill rate at the depot is 50% Effective lead time at base 1 = 1+0.5*2=2 months Effective lead time at base 2 = 2+0.5*2=3 months If the fill rate at the depot is 75% Effective lead time at base 1 = 1+0.25*2=1.5 months Effective lead time at base 2 = 2+0.25*2=2.5 months Effective lead time at the bases is a function of the depot fill rate, which is a function of stock level at the depot. So fill rate at the base is a function of stock level at the base as well as stock level at the depot Depot Base 1 Supplier Base 2 D=2 months 2 =2 months 1 =1 month
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Managing inventory ABC approach: Classify items into A, B, C classes. Tighter management of inventory for A items Lead time reductions have major impact on inventories. Inventory turnover ratio = (annual sales)/(average inventory level) There is “economies of scale” in managing inventory. Fast moving items usually lead to larger inventory turns
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Inventory turns for different industries IndustryUpper Quartile MedianLower Quartile Electronic components and accessories9.85.73.7 Electronic computers9.45.33.5 Household audio and video equipment6.23.42.3 Household electrical appliances8.05.03.8 Industrial chemicals10.36.64.4 Dairy products34.419.39.2 Publishing and printing9.82.41.3
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