# Boundary Layer Flow Describes the transport phenomena near the surface for the case of fluid flowing past a solid object.

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Boundary Layer Flow Describes the transport phenomena near the surface for the case of fluid flowing past a solid object

Drag force The surrounding fluid exerts pressure forces and viscous forces on an object. The components of the resultant force acting on the object immersed in the fluid are the drag force and the lift force. p < 0 U p > 0 tw The drag force acts in the direction of the motion of the fluid relative to the object. The lift force acts normal to the flow direction. Both are influenced by the size and shape of the object and the Reynolds number of the flow.

Drag prediction The drag force is due to the pressure and shear forces acting on the surface of the object. The tangential shear stresses acting on the object produce friction drag (or viscous drag). p < 0 U p > 0 tw

Drag prediction Friction drag is dominant in flow past a flat plate and is given by the surface shear stress times the area: Pressure or form drag results from variations in the normal pressure around the object: p < 0 U p > 0 tw In order to predict the drag on an object correctly, we need to correctly predict the pressure field and the surface shear stress. This, in turn, requires correct treatment and prediction of boundary layers and flow separation.

Viscous boundary layer
An originally laminar flow is affected by the presence of the walls. Flow over flat plate is visualized by introducing bubbles that follow the local fluid velocity. Most of the flow is unaffected by the presence of the plate.

Viscous boundary layer
However, in the region closest to the wall, the velocity decreases to zero. The flow away from the walls can be treated as inviscid, and can sometimes be approximated as potential flow.

Viscous boundary layer
The region near the wall where the viscous forces are of the same order as the inertial forces is termed the boundary layer.

Viscous boundary layer
The distance over which the viscous forces have an effect is termed the boundary layer thickness. The thickness is a function of the ratio between the inertial forces and the viscous forces- i.e., the Reynolds number. As NRe increases, the thickness decreases.

Effect of viscosity The layers closer to the wall start moving right away due to the no-slip boundary condition. The layers farther away from the wall start moving later. The distance from the wall that is affected by the motion is also called the viscous diffusion length. This distance increases as time goes on. Consider the following experiment where a viscous liquid is placed with an immiscible liquid in a container subjected to slow angular/rotational motion. The system shown on the left is performed with a higher viscosity fluid (100 mPas). On the right, a lower viscosity fluid (10 mPas) is shown. Notice the parabolic profile in the more viscous liquid as compared to the almost flat (uniform) profile in the less viscous liquid.

Moving plate boundary layer
Consider an impulsively started plate in a stagnant fluid. When the wall in contact with the still fluid suddenly starts to move, the layers of fluid close to the wall are dragged along while the layers farther away from the wall move with a lower velocity. The viscous layer develops as a result of the no-slip boundary condition at the wall.

Flow separation Flow separation occurs when (a) the velocity at the wall is zero or negative and an inflection point exists in the velocity profile, and a positive or adverse pressure gradient occurs in the direction of flow.

Boundary layer theory Consider a flow over a semi-infinite flat plate (and also for a finite flat plate), under steady state conditions: Fluid Velocity, v Away from plate, inviscid flow assumption is valid. Near the plate, viscosity effects are significant. Why not linear? --> next slide

Boundary layer theory Solid Boundary INF INF Velocity v
INF INF INVISCID FLOW ASSUMPTION OK HERE No Slip Velocity 0 FRICTION CANNOT BE NEGLECTED HERE

Boundary layer theory INF INF Solid Boundary BL thickness
INF INF BL thickness 99% Free stream velocity And a pictorial representation of what you expect to see (qualitatively). Far from surface, viscous forces are unimportant and inertial forces dominate; on the other hand, near the surface, viscous forces are comparable to inertial forces In the very beginning, only a small region of fluid is affected by the presence of the plate. Let us say that when the velocity of the fluid is 99% of the free stream (bulk) velocity, we assume that the effect of plate is practically zero (i.e., the velocity from this distance from the plate surface up to y = infinity is that of the bulk velocity). Then the boundary layer thickness, denoted by delta, will be determined this condition When you go further down the plate (to the right), the effect of plate is felt into the fluid for a larger value of delta. So, the delta increases as a function of x. Does it increase linearly? --> next slide d d What happens to d when you move in x? BL thickness increases with x x

Laminar boundary layer
The dashed line L shows the progression of the increase of delta. The layer or zone between the plate and the dash line constitutes the boundary layer. When the flow is laminar, delta increases with the square root of x (distance downstream from the leading edge of the plate).

Laminar boundary layer
BL Reynolds number: Blasius approximation of d: For laminar flow: NRe < 2  105 For transition flow: 2  105 < NRe < 3  106

Turbulent boundary layer

Turbulent boundary layer
At high enough fluid velocity, inertial forces dominate Viscous forces cannot prevent a wayward particle from motion Chaotic flow ensues Turbulence near the wall For wall-bounded flows, turbulence initiates near the wall

Turbulent boundary layer
In turbulent flow, the velocity component normal to the surface is much smaller than the velocity parallel to the surface The gradients of the flow across the layer are much greater than the gradients in the flow direction.

Turbulent boundary layer

Turbulent boundary layer
Eddies and Vorticity An eddy is a particle of vorticity that typically forms within regions of velocity gradient An eddy begins as a disturbance near the wall, followed by the formation of a vortex filament that later stretches into a horseshoe or hairpin vortex

Turbulent boundary layer
Turbulence is comprised of irregular, chaotic, three-dimensional fluid motion, but containing coherent structures. Turbulence occurs at high Reynolds numbers, where instabilities give way to chaotic motion. Turbulence is comprised of many scales of eddies, which dissipate energy and momentum through a series of scale ranges. The largest eddies contain the bulk of the kinetic energy, and break up by inertial forces. The smallest eddies contain the bulk of the vorticity, and dissipate by viscosity into heat. Turbulent flows are not only dissipative, but also dispersive through the advection mechanism.

Dimensional Analysis

Buckingham Pi Theorem Tells how many dimensionless groups (p) may define a system. Theorem: If n variables are involved in a problem and these are expressed using k base dimensions, then (n – k) dimensionless groups are required to characterize the system/problem.

Buckingham Pi Theorem Example:
In describing the motion of a pendulum, the variables are time [T], length [L], gravity [L/T2], mass [M]. Therefore, n = 4 k = 3. So, only one (4 – 3) dimensionless group is required to describe the system. But how do we derive this?

Buckingham Pi Theorem How to find the dimensional groups: For the pendulum example: let a, b, c and d be the coefficients of t, L, g and m in the group, respectively. In terms of dimensions:

Buckingham Pi Theorem How to find the dimensional groups: For the pendulum example: let a, b, c and d be the coefficients of t, L, g and m in the group, respectively. Since the group is dimensionless: Therefore:

Buckingham Pi Theorem How to find the dimensional groups: For the pendulum example: let a, b, c and d be the coefficients of t, L, g and m in the group, respectively. Arbitrarily choosing a = 1: Therefore:

Buckingham Pi Theorem Example: Drag on a sphere
Drag depends on FOUR parameters: sphere size (D); fluid speed (v); fluid density (r); fluid viscosity (m) Difficult to know how to set up experiments to determine dependencies and how to present results (four graphs?)

Buckingham Pi Theorem Step 1: List all the parameters involved Let n be the number of parameters Example: For drag on a sphere: F, v, D, r, and m (n = 5) Step 2: Select a set of primary dimensions Let k be the number of primary dimensions For this example: M (kg), L (m), t (sec); thus k = 3

Buckingham Pi Theorem Step 3: Determine the number of dimensionless groups required to define the system Step 4: Select a set of k dimensional parameters that includes all the primary dimensions For example: select r, v, D

Buckingham Pi Theorem Step 4: Select a set of k dimensional parameters that includes all the primary dimensions For example: select r, v, D AND F

Buckingham Pi Theorem Step 4: Select a set of k dimensional parameters that includes all the primary dimensions For example: select r, v, D AND F Let d = 1: Therefore: The exponent of drag force F must be 1 since it must always appear in this group.

Buckingham Pi Theorem Step 4: Select a set of k dimensional parameters that includes all the primary dimensions Next group: select r, v, D and m

Buckingham Pi Theorem Step 4: Select a set of k dimensional parameters that includes all the primary dimensions Next group: select r, v, D and m Let a = 1: Therefore:

Buckingham Pi Theorem Only one dependent and one independent variable
Easy to set up experiments to determine dependency Easy to present results (one graph)

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