1. Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

2. What is Organic chemistry?

3. The study of carbon and its compounds.

4. What is Organic chemistry? The study of carbon and its compounds. First we will talk about compounds just containing carbon and hydrogen, these compounds are called hydrocarbons.

5. What is Organic chemistry? The study of carbon and its compounds. First we will concentrate on compounds just containing carbon and hydrogen, these compounds are called hydrocarbons. Hydrocarbon Classification Hydrocarbons Alkanes Alkenes CycloalkanesAlkynes Cycloalkenes

6. 1.Alkanes (saturated) hydrocarbons, or aliphatic hydrocarbons) A.General formula of C n H 2n+2 B.Examples a. CH 4 b. C 2 H 6 c. C 3 H ?

7. 1.Alkanes (saturated) hydrocarbons, or aliphatic hydrocarbons) A.General formula of C n H 2n+2 B.Examples a. CH 4 b. C 2 H 6 c. C 3 H 8 d. C 4 H ?

8. 1.Alkanes (saturated) hydrocarbons, or aliphatic hydrocarbons) A.General formula of C n H 2n+2 B.Examples a.CH 4 b. C 2 H 6 c. C 3 H 8 d. C 4 H 10 C. Draw Lewis Structures

9. 1.Alkanes (saturated) hydrocarbons, or aliphatic hydrocarbons) A.General formula of C n H 2n+2 B.Examples a.CH 4 b. C 2 H 6 c. C 3 H 8 d. C 4 H 10 C. Draw Lewis Structures CH 4

10. 1.Alkanes (saturated) hydrocarbons, or aliphatic hydrocarbons) A.General formula of C n H 2n+2 B.Examples a.CH 4 b. C 2 H 6 c. C 3 H 8 d. C 4 H 10 C. Draw Lewis Structures CH 4 C 2 H 6

11. 1.Alkanes (saturated) hydrocarbons, or aliphatic hydrocarbons) A.General formula of C n H 2n+2 B.Examples a.CH 4 b. C 2 H 6 c. C 3 H 8 d. C 4 H 10 C. Draw Lewis Structures CH 4 C 2 H 6 C 3 H 8

12. 1.Alkanes (saturated) hydrocarbons, or aliphatic hydrocarbons) A.General formula of C n H 2n+2 B.Examples a.CH 4 b. C 2 H 6 c. C 3 H 8 d. C 4 H 10 C. Draw Lewis Structures CH 4 C 2 H 6 C 3 H 8 D. Polarity? Polar or nonpolar?

13. 1.Alkanes (saturated) hydrocarbons, or aliphatic hydrocarbons) A.General formula of C n H 2n+2 B.Examples a.CH 4 b. C 2 H 6 c. C 3 H 8 d. C 4 H 10 C. Draw Lewis Structures CH 4 C 2 H 6 C 3 H 8 D. Polarity? Polar or nonpolar?Nonpolar

14. E. Types of carbon 1. Primary (1 ◦ ) Carbon connected to one carbon atoms. 2. Secondary (2 ◦ ) Carbon connected to two carbon atoms. 3. Tertiary (3 ◦ ) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the two different structures of C 4 H 10

15. E. Types of carbon 1. Primary (1 ◦ ) Carbon connected to one carbon atoms. 2. Secondary (2 ◦ ) Carbon connected to two carbon atoms. 3. Tertiary (3 ◦ ) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the two different structures of C 4 H 10 Primary carbon = ? Secondary carbon = Tertiary carbon =

16. E. Types of carbon 1. Primary (1 ◦ ) Carbon connected to one carbon atoms. 2. Secondary (2 ◦ ) Carbon connected to two carbon atoms. 3. Tertiary (3 ◦ ) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the two different structures of C 4 H 10 Primary carbon = 2 Secondary carbon = ? Tertiary carbon =

17. E. Types of carbon 1. Primary (1 ◦ ) Carbon connected to one carbon atoms. 2. Secondary (2 ◦ ) Carbon connected to two carbon atoms. 3. Tertiary (3 ◦ ) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the two different structures of C 4 H 10 Primary carbon = 2 Secondary carbon = 2 Tertiary carbon =

18. E. Types of carbon 1. Primary (1 ◦ ) Carbon connected to one carbon atoms. 2. Secondary (2 ◦ ) Carbon connected to two carbon atoms. 3. Tertiary (3 ◦ ) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the two different structures of C 4 H 10 Primary carbon = 2 Secondary carbon = 2 Tertiary carbon = ?

19. G.Types of carbon 1. Primary (1 ◦ ) Carbon connected to one carbon atoms. 2. Secondary (2 ◦ ) Carbon connected to two carbon atoms. 3. Tertiary (3 ◦ ) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the two different structures of C 4 H 10 Primary carbon = 2 Secondary carbon = 2 Tertiary carbon = 0

20. E. Types of carbon 1. Primary (1 ◦ ) Carbon connected to one carbon atoms. 2. Secondary (2 ◦ ) Carbon connected to two carbon atoms. 3. Tertiary (3 ◦ ) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the two different structures of C 4 H 10 Primary carbon = ? Secondary carbon = Tertiary carbon = Isobutane C 4 H 10

21. G.Types of carbon 1. Primary (1 ◦ ) Carbon connected to one carbon atoms. 2. Secondary (2 ◦ ) Carbon connected to two carbon atoms. 3. Tertiary (3 ◦ ) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the two different structures of C 4 H 10 Primary carbon = 3 Secondary carbon = ? Tertiary carbon = Isobutane C 4 H 10

22. E. Types of carbon 1. Primary (1 ◦ ) Carbon connected to one carbon atoms. 2. Secondary (2 ◦ ) Carbon connected to two carbon atoms. 3. Tertiary (3 ◦ ) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the two different structures of C 4 H 10 Primary carbon = 3 Secondary carbon = 0 Tertiary carbon = ? Isobutane C 4 H 10

23. G.Types of carbon 1. Primary (1 ◦ ) Carbon connected to one carbon atoms. 2. Secondary (2 ◦ ) Carbon connected to two carbon atoms. 3. Tertiary (3 ◦ ) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the two different structures of C 4 H 10 Primary carbon = 3 Secondary carbon = 0 Tertiary carbon = 1 Isobutane C 4 H 10

24. 1.Alkanes (Continued) F. There are two different structures for C 4 H 10 called isomers, because they contain different types of carbon. Structure 1 Structure 2

25. Constitutional Isomers (Structural Isomers) are different compounds of the same formula. The different structures from the previous slide for the formula C 4 H 10 is an example of Constitutional isomers. Isomerism

26. Constitutional Isomers (Structural Isomers) are different compounds of the same formula. The different structures from the previous slide for the formula C 4 H 10 is an example of Constitutional isomers. How many isomers are there of an alkane containing five carbons (C 5 H 12 )? Isomerism Isomer Strategy – Draw Lewis possible different length chains of carbons atoms connected with a covalent bond.

27. Constitutional Isomers (Structural Isomers) are different compounds of the same formula. The different structures from the previous slide for the formula C 4 H 10 is an example of Constitutional isomers. How many isomers are there of an alkane containing five carbons (C 5 H 12 )? Isomerism Isomer Strategy – Draw Lewis possible different length chains of carbons atoms connected with a covalent bond. C C C C C Chains of 5 carbon atoms H H H H H H H H H H H H

28. Isomerism Chains of 4 carbon atoms C C H H H H C H H H H H H H H

29. Isomerism Chains of 4 carbon atoms C H H H H C H H H H H H H H Chains of 3 carbon atoms C C C C H H H H H H CH H H H H H C C C

30. Isomerism Chains of 4 carbon atoms C C H H H H C H H H H H H H H Chains of 3 carbon atoms There are three isomers of C 5 H 12 C C C C H H H H H H CH H H H H H

31. NOMENCLATURE 1.Common system a.Works best for low molecular weight hydrocarbons b.Steps to give a hydrocarbon a common name: 1.Count the total number of carbon atoms in the molecule. 2.Use the Latin root from the following slide that corresponds to the number of carbon atoms followed by the suffix “ane”. 3.Unbranced hydrocarbons use the prefix normal, or n-, 4.Branched hydrocarbons use specific prefixes, as shown on a subsequent slide

32. NOMENCLATURE Common system Examples 1. Give a name for the following compound Step #1, count the number of carbons and write down the memorized Latin name for that number (next slide) Step #2, since this structure fits the alkane general formula, use the “ane” suffix propane Three carbon Latin root Alkane suffix

33. Latin Hydrocarbon Roots Number of Carbons Latin Root 1meth 2eth 3prop 4but 5pent 6hex 7hept 8oct 9non 10dec 11undec Latin Hydrocarbon Roots Number of Carbons Latin Root 12dodec 13tridec 14tetradec 15pentadec 16hexadec 17heptadec 18octadec 19nonadec 20eicos 21unicos 22doicos H H n-butane isobutane H C C C H H C H H C H H H H H H H Examples neopentane

34. 2. Systematic System of Nomenclature (IUPAC) Find the longest continuous chain of carbon atoms. Use a Latin root corresponding to the number of carbons in the longest chain of carbons. Follow the root with the suffix of “ane” for alkanes Carbon atoms not included in the chain are named as substituents preceding the root name with Latin root followed by “yl” suffix. Number the carbons, starting closest to the first branch. Name the substituent's attached to the chain, using the carbon number as the locator in alphabetical order. Use di-, tri-, etc., for multiples of same substituent. If there are two possible chains with the same number of carbons, use the chain with the most substituent's.

35. Substituent Names (Alkyl groups)

36. Which one? Systematic Nomenclature continued.

37. Which one? Systematic Nomenclature continued. The one with the most number of substituent's

38. Which one? Systematic Nomenclature continued. The one with the least number of substituent's The top structure has four substituent's and the bottom has three substituent's.

39. Which one? Systematic Nomenclature continued. The one with the least number of substituent's The top structure has four substituent's and the bottom has three substituent's. Name = ?

40. Which one? Systematic Nomenclature continued. The one with the most number of substituent's The top structure has four substituent's and the bottom has three substituent's. Name = ? heptane

41. Which one? Systematic Nomenclature continued. The one with the least number of substituent's The top structure has four substituent's and the bottom has three substituent's. Name = 3,3,5-trimethyl-4-propylheptane

42. Another Example: Name = 3-ethyl-2,6-dimethylheptane

43. Another Example: Name = 3-ethyl-2,6-dimethylheptane Notice substituent's are in alphabetical order; di, tri, etc. do not participate in the alphabetical order

44. Line Structures A quicker way to write structures' (Condensed Structure) (A line structure of the above condensed structure) ethyl methyl

45. Complex Substituent's If the branch has a branch, number the carbons from the point of attachment. Name the branch off the branch using a locator number. Parentheses are used around the complex branch name. 1-methyl-3-(1,2-dimethylpropyl)cyclohexane 1 2 1 3

46. Alkane Physical Properties Solubility: hydrophobic (not water soluble) Density: less than 1 g/mL (floats on water) Boiling points increase with increasing carbons (little less for branched chains) due to dispersion forces being larger. Melting points increase with increasing carbons (less for odd-number of carbons).

47. Boiling Points of Alkanes Branched alkanes have less surface area contact, so weaker intermolecular forces.

48. Melting Points of Alkanes Branched alkanes pack more efficiently into a crystalline structure, so have higher m.p.

49. Reactions of Alkanes I. Combustion reaction II. Cracking reaction III. Halogenation reaction (substitution reaction)

50. Sample problem: Which isomer of C 5 H 12 has the most monochloro isomers? Problem solving process: Step 1 draw the isomers of C 5 H 12 Step 2 react each isomer with chlorine Step 3 count the products

51. Sample problem: Which isomer of C 5 H 12 has the most monochloro isomers? Problem solving process: Step 1 draw the isomers of C 5 H 10 Step 2 react each isomer with chlorine Step 3 count the products

52. Sample problem: Which isomer of C 5 H 12 has the most monochloro isomers? Problem solving process: Step 1 draw the isomers of C 5 H 10 Step 2 react each isomer with chlorine Step 3 count the products

53. Sample problem: Which isomer of C 5 H 12 has the most monochloro isomers? Problem solving process: Step 1 draw the isomers of C 5 H 10 Step 2 react each isomer with chlorine Step 3 count the products

54. Sample problem: Which isomer of C 5 H 12 has the most monochloro isomers? Problem solving process: Step 1 draw the isomers of C 5 H 10 Step 2 react each isomer with chlorine Step 3 count the products

55. Sample problem: Which isomer of C 5 H 12 has the most monochloro isomers? Problem solving process: Step 1 draw the isomers of C 5 H 10 Step 2 react each isomer with chlorine Step 3 count the products Winner!

56. Conformers of Alkanes Structures resulting from the free rotation of a C-C single bond May differ in energy. The lowest-energy conformer is most prevalent. Molecules constantly rotate through all the possible conformations.

57. Ethane Conformers Staggered conformer has lowest energy. Dihedral angle = 60 degrees model H H H H HH Newman projection sawhorse Dihedral angle

58. Ethane Conformers (2) Eclipsed conformer has highest energy Dihedral angle = 0 degrees =>

59. Conformational Analysis Torsional strain: resistance to rotation. For ethane, only 12.6 kJ/mol =>

60. Propane Conformers Note slight increase in torsional strain due to the more bulky methyl group.

61. Butane Conformers C2-C3 Highest energy has methyl groups eclipsed. Steric hindrance Dihedral angle = 0 degrees => totally eclipsed (methyl groups)

62. Butane Conformers (2) Lowest energy has methyl groups anti. Dihedral angle = 180 degrees => Staggered-anti

63. Butane Conformers (3) Methyl groups eclipsed with hydrogens Higher energy than staggered conformer Dihedral angle = 120 degrees => Eclipsed (hydrogen and methyl)

64. Butane Conformers (4) Gauche, staggered conformer Methyls closer than in anti conformer Dihedral angle = 60 degrees => Staggered-gauche

65. Conformational Analysis

66. Cycloalkanes Rings of carbon atoms (-CH 2 - groups) Formula: C n H 2n Nonpolar, insoluble in water Compact shape Melting and boiling points similar to branched alkanes with same number of carbons Slightly unsaturated compared to alkanes

67. Naming Cycloalkanes Count the number of carbons in the cycle If the bonds are single then use the suffix “ane” First substituent in alphabet gets lowest number. May be cycloalkyl attachment to chain.

68. Cis-Trans Isomerism (a type of stereoisomerism) Cis: like groups on same side of ring Trans: like groups on opposite sides of ring

69. Cycloalkane Stability 6-membered rings most stable Bond angle closest to 109.5  Angle (Baeyer) strain Measured by heats of combustion per -CH 2 -

70. Heats of Combustion/CH 2 Alkane + O 2  CO 2 + H 2 O 658.6 697.1 686.1 664.0663.6 kJ/mol 662.4658.6 kJ Long-chain

71. Cyclopropane Large ring strain due to angle compression Very reactive, weak bonds =>

72. Cyclopropane (2) Torsional strain because of eclipsed hydrogens

73. Cyclobutane Angle strain due to compression Torsional strain partially relieved by ring puckering =>

74. Cyclopentane If planar, angles would be 108 , but all hydrogens would be eclipsed. Puckered conformer reduces torsional strain.

75. Cyclohexane Combustion data shows it’s unstrained. Angles would be 120 , if planar. The chair conformer has 109.5  bond angles and all hydrogen's are staggered. No angle strain and no torsional strain.

76. Chair Conformer

77. Boat Conformer

78. Conformational Energy

79. Axial and Equatorial Positions

80. Monosubstituted Cyclohexanes

81. 1,3-Diaxial Interactions

82. Disubstituted Cyclohexanes

83. Cis-Trans Isomers Bonds that are cis, alternate axial-equatorial around the ring. => One axial, one equatorial

84. Bulky Groups Groups like t-butyl cause a large energy difference between the axial and equatoria l conformer. Most stable conformer puts t-butyl equatorial regardless of other substituents. =>

85. End of Chapter 2