1. Solutions Review
Play as a slideshow!

2. Calculate the molarity of a 0
Calculate the molarity of a L sugar solution that was prepared with 0.15 moles of sugar?
M = mol/L
M = 0.15 mol/0.175 L
M = 0.86 M

3. Solutions are ________________ mixtures made up of very small particles.
Homogeneous

4. Determine the volume of 0
Determine the volume of M sugar solution that can be prepared with moles of sugar.
M = mol/L
0.235 M = mol/ x L ***cross-multiply
0.235 x = 0.470
X = 2.00 L

5. Explain why solutions are classified as mixtures instead of compounds.
The two parts, solute and solvent, are only physically combined, not chemically combined. Also, you can easily separate them with a physical change, such as evaporating off the solvent. Finally, they can combine in different ratios, they do not have a fixed ratio like compounds (example, water is always 2 H and one O, but salt water can have varying percent of salt in it).

6. A salt solution is to be added to a marine aquarium
A salt solution is to be added to a marine aquarium. Calculate the molarity of a salt solution that is prepared by adding water to g of NaCl to give a final volume of ml.
M = mol/L
18.65 g x 1 mol/ g = mol
M = mol/ L
M = M

7. alloy air oxygen aqueous
Pure gold is 24 carat. 14-carat gold contains 14 parts gold and 10 parts other metals. 14-carat gold is said to be a(n) ___________, which is a type of solution. An example of a gaseous solution is ________________, which is made up mostly of ______________ and nitrogen when dry. The most common solutions are ______________ solutions.
alloy
air
oxygen
aqueous

8. Calculate the volume of a 3
Calculate the volume of a 3.15 M NaOH (aq) solution that should be used to prepare 250. ml of M NaOH (aq).
M1V1 = M2V2
3.15 M x V1 = M x 250. mL
V1 = 11.9 mL

9. Because of the _______________ _______________, you can see the light beams from car headlights in a fog.
Tyndall Effect

10. You have 3.0 L of 3.0 M HCl. What volume of 2.0 M HCl can you make?
M1V1 = M2V2
3.0 M x 3.0 L = 2.0 M x V2
V2 = 4.5 L

11. 3. 5 L of solvent was added to 2. 0 L of a 0. 88 M solution
3.5 L of solvent was added to 2.0 L of a 0.88 M solution. What is the new molarity of the solution?
M1V1 = M2V2
0.88 M x 2.0 L = M2 x 5.5 L
M2 = 0.32 M

12. Multiple choice: To increase the rate of solution of a solid in water,
a. increase the pressure over the water.
b. decrease the pressure over the water.
c. crush the particles of the solid.
d. chill the water.

13. You need 450 mL of 0. 15 M NaOH. All you have available is a 2
You need 450 mL of 0.15 M NaOH. All you have available is a 2.0 M stock solution of NaOH. What volume of solvent will you add to the volume required of the stock solution to make your dilution?
M1V1 = M2V2
0.15 M x 450 mL = 2.0 M x V2
V2 = mL stock solution
450 – = mL solvent

14. If 15 grams of iodine are dissolved in 1000 mL of alcohol, the alcohol is the (solute, solvent) and the solution is said to be a(n) _______________.
A substance that dissolves other materials is a (solute, solvent). The substance being dissolved is a (solute, solvent).
tincture

15. You have 6. 0 L of 5. 0 M NaCl stock solution
You have 6.0 L of 5.0 M NaCl stock solution. You take 800 mL of that stock solution, and add 500 mL of solvent.
-How many moles of NaCl would be present in the new solution?
-What is the molarity of new solution?
M = mol/L
5.0 M = x mol/ L
X = 4.0 mol
M1V1 = M2V2
5.0 M x 800 mL = M2 x 1300 mL
M2 = 3.08 M

16. In (solutions, suspensions) the substances separate after standing a while. The substances (can also, can not) be separated by filtration.

17. Find the volume of a 0.75 M solution if it contains 39 grams of KOH.
39 g x 1 mol/56.1 g = mol
M = mol/L
0.75 M = mol/x L ***cross-multiply***
X = L

18. Smoke is an example of a _____________ of solid dirt and dust particles in air.
colloid

19. How many grams of hydrochloric acid (HCl) are present in 3. 0 L of a 0
How many grams of hydrochloric acid (HCl) are present in 3.0 L of a M solution?
M = mol/L
0.750 M = x mol/ 3.0 L
X = 2.25 mol
2.25 mol x g/ 1 mol = 82.0 g

20. A(n) ________________’s particles are between those of a solution and a suspension.
colloid

21. 110. 0 mL of 3. 00 M sulfuric acid has 25. 0 mL of water added to it
110.0 mL of 3.00 M sulfuric acid has 25.0 mL of water added to it. What is the resulting concentration of the solution ?
M1V1 = M2V2
3.00 M x mL = M2 x mL
M2 = 2.44 M

22. How does a solution behave differently from a suspension when a beam of light is shined through it?
A beam of light will go right through a solution and you will not see it. A suspension exhibits the Tyndall Effect where you will be able to see the beam of light.

23. Acetic acid is purchased as a solution in 17. 0 M concentrations
Acetic acid is purchased as a solution in 17.0 M concentrations. Explain how you would prepare mL of a 5.00 M solution.
M1V1 = M2V2
17 M x V1 = 5.00 M x mL
V1 = mL
Put mL into a 500 mL volumetric flask. Then add water until the solution is 500 mL total (to the line).

24. What is the solute in a brass alloy containing 75% copper and 25% zinc?
Zinc (it has a smaller percentage)

25. electrolytes Non-electrolytes
Substances that conduct electricity when dissolved are said to be ______________, while substances that do NOT conduct electricity when dissolved are said to be __________________.
electrolytes
Non-electrolytes