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CS110 Programming Language I Lab 10: Arrays I Computer Science Department Spring 2014
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Find Errors (If Any): char[] array = new char[5]; for (int i=0 ; i <= 4 ; i++) array = ‘M’;
![Find Errors (If Any): char[] array = new char[5]; for (int i=0 ; i <= 4 ; i++) array = ‘M’;](http://images.slideplayer.com/13/4035670/slides/slide_2.jpg "Find Errors (If Any): char[] array = new char[5]; for (int i=0 ; i <= 4 ; i++) array = ‘M’;")
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Find Errors (If Any): int[] array = new int[5]; for(int i=0 ; i < array.length() ; i++) array(i) = i;
![Find Errors (If Any): int[] array = new int[5]; for(int i=0 ; i < array.length() ; i++) array(i) = i;](http://images.slideplayer.com/13/4035670/slides/slide_3.jpg "Find Errors (If Any): int[] array = new int[5]; for(int i=0 ; i < array.length() ; i++) array(i) = i;")
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Problem Description What is output by the following programs?
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Sample Output: Problem Description (Odd/Even Index) Write a program that prompts the user to enter ten numbers and print the content of the odd index, then print the even index.
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Code Skelton import java.util.Scanner; public class OddEvenIndex { public static void main(String[] args) { Scanner input = new Scanner(System.in); int[] numbers = new int[10]; System.out.print("Enter ten numbers: "); for (int i = 0; i < numbers.length; i++) numbers[i] = input.nextInt();
![Code Skelton import java.util.Scanner; public class OddEvenIndex { public static void main(String[] args) { Scanner input = new Scanner(System.in); int[] numbers = new int[10]; System.out.print( Enter ten numbers: ); for (int i = 0; i < numbers.length; i++) numbers[i] = input.nextInt();](http://images.slideplayer.com/13/4035670/slides/slide_6.jpg "Code Skelton import java.util.Scanner; public class OddEvenIndex { public static void main(String[] args) { Scanner input = new Scanner(System.in); int[] numbers = new int[10]; System.out.print( Enter ten numbers: ); for (int i = 0; i < numbers.length; i++) numbers[i] = input.nextInt();")
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System.out.print("Odd index elements are: "); for (int i = 1; i < numbers.length; i += 2) System.out.print(numbers[i] + " "); System.out.println(); // new line System.out.print("Even index elements are: "); for (int i = 0; i < numbers.length; i += 2) System.out.print(numbers[i] + " "); System.out.println(); // new line } // end of main }
![System.out.print( Odd index elements are: ); for (int i = 1; i < numbers.length; i += 2) System.out.print(numbers[i] + ); System.out.println(); // new line System.out.print( Even index elements are: ); for (int i = 0; i < numbers.length; i += 2) System.out.print(numbers[i] + ); System.out.println(); // new line } // end of main }](http://images.slideplayer.com/13/4035670/slides/slide_7.jpg "System.out.print( Odd index elements are: ); for (int i = 1; i < numbers.length; i += 2) System.out.print(numbers[i] + ); System.out.println(); // new line System.out.print( Even index elements are: ); for (int i = 0; i < numbers.length; i += 2) System.out.print(numbers[i] + ); System.out.println(); // new line } // end of main }")
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Follow-up Questions and Activities (Analyze scores) Write a program that reads an unspecified number of scores and determines how many scores are above or equal to the average and how many scores are below the average. Enter a negative number to signify the end of the input. Assume that the maximum number of scores is 100. Sample Output:
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Code Skelton import java.util.Scanner ; public class Analyze { public static void main(String[] args) { Scanner input = new Scanner(System.in); double[] scores = new double[100]; int count = 0; do { System.out.print("Enter a new score: "); scores[count] = input.nextDouble(); } while (scores[count++] != -1);
![Code Skelton import java.util.Scanner ; public class Analyze { public static void main(String[] args) { Scanner input = new Scanner(System.in); double[] scores = new double[100]; int count = 0; do { System.out.print( Enter a new score: ); scores[count] = input.nextDouble(); } while (scores[count++] != -1);](http://images.slideplayer.com/13/4035670/slides/slide_9.jpg "Code Skelton import java.util.Scanner ; public class Analyze { public static void main(String[] args) { Scanner input = new Scanner(System.in); double[] scores = new double[100]; int count = 0; do { System.out.print( Enter a new score: ); scores[count] = input.nextDouble(); } while (scores[count++] != -1);")
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int numOfAbove = 0; int numOfBelow = 0; for (int i = 0; i < count - 1; i++) if (scores[i] >= 60) numOfAbove++; else numOfBelow++; System.out.println("Number of scores above or equal to the pass marks " + numOfAbove); System.out.println("Number of scores below the pass marks “ + numOfBelow); } // end of Main }
![int numOfAbove = 0; int numOfBelow = 0; for (int i = 0; i < count - 1; i++) if (scores[i] >= 60) numOfAbove++; else numOfBelow++; System.out.println( Number of scores above or equal to the pass marks + numOfAbove); System.out.println( Number of scores below the pass marks + numOfBelow); } // end of Main }](http://images.slideplayer.com/13/4035670/slides/slide_10.jpg "int numOfAbove = 0; int numOfBelow = 0; for (int i = 0; i < count - 1; i++) if (scores[i] >= 60) numOfAbove++; else numOfBelow++; System.out.println( Number of scores above or equal to the pass marks + numOfAbove); System.out.println( Number of scores below the pass marks + numOfBelow); } // end of Main }")
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Evaluation (Linear Search) Write a program that prompts the user to enter the size of the array and let the user to enter the content of that array, then ask the user to enter a value to search in the array using linear search. Check if the value is found or not. In case if the values founded print the position. Sample Output:
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