1. How an 85 mph pitcher can throw 93 mph using math

2. Using ratios Convert mph to ft/sec 1 mph= 5280 f f f ft/sec 3600 Measure the distance the ball travels 60 ft 6 inches (60.5 ft) Determine how many seconds it takes the ball to reach home plate distance = seconds to home plate ft./sec

3. Calculations How many seconds does it take an 85mph pitch to get to home plate? How many seconds does it take an 85mph pitch to get to home plate? 85mph= (85)(5280/3600)ft/sec 85mph= (85)(5280/3600)ft/sec 124.67 ft/sec Time to home plate=60.5/124.67 Time to home plate=60.5/124.67.485 seconds 60.5 feet

4. The Flaws Height of the mound, pitcher, and release point Height of strike zone 10 inches 74 inches 6 inches 24 inches

5. The Trigonometry of pitching Use the Pythagorean theorem to solve for x 60.5 ft. x ft. 5.5 ft. 222 a b c

6. The Trigonometry of pitching Use the Pythagorean theorem to solve for x 60.5 ft. x ft. b c 5.5 ft. a 30.25 + 3660.25 = x 2 x =60.75 60.75 ft

7. Calculations Actual time to home plate 60.75/124.67 =.487 seconds Appears as an 84 mph fastball to the batter

8. 60 90 inches x inches 90(cos60) = xx = 45 inches or 3.75 ft. 3.75 ft. 56.75 ft 7.5 ft. 6.5 ft 6.5 – 2 = 4.5 ft. 4.5 ft. 56.9 ft.

9. Calculations Actual time to home Plate 56.9/124.67 =.4564 Appears as an 90 mph fastball to the batter

10. 45 7.5 ft. 7.5cos(45) = x x 5.5 ft = x5.5 ft. 60.5 – 5.5 = 55 ft 55 ft. 5.5 – 2 = 3.5 ft. 3.5 ft. 45 55.1 ft.

11. Calculations Actual time to home plate 55.1/124.67 =.4419 60.5/.4419 = 136.91 ft/sec 136.91 * 3600 5280 = 93.3 mph 93.3 mph