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CPSC 668Set 18: Wait-Free Simulations Beyond Registers1 CPSC 668 Distributed Algorithms and Systems Fall 2006 Prof. Jennifer Welch.

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Presentation on theme: "CPSC 668Set 18: Wait-Free Simulations Beyond Registers1 CPSC 668 Distributed Algorithms and Systems Fall 2006 Prof. Jennifer Welch."— Presentation transcript:

1 CPSC 668Set 18: Wait-Free Simulations Beyond Registers1 CPSC 668 Distributed Algorithms and Systems Fall 2006 Prof. Jennifer Welch

2 CPSC 668Set 18: Wait-Free Simulations Beyond Registers2 Data Types Beyond Registers Registers support the operations read and write We've seen wait-free simulations of one kind of register out of another kind –different numbers of values, readers, writers What about (wait-free) simulating a significantly different kind of data type out of registers? More generally, what about (wait-free) simulating an object of type X out of objects of type Y ?

3 CPSC 668Set 18: Wait-Free Simulations Beyond Registers3 Key Insight Ability of objects of type Y to be used to simulate an object of type X is related to the ability of those data types to solve consensus! We are focusing on systems that are –asynchronous –shared memory –wait-free

4 CPSC 668Set 18: Wait-Free Simulations Beyond Registers4 FIFO Queue Example Sequential specification of a FIFO queue: –operation with invocation enq(x) and response ack –operation with invocation deq and response return(x) –a sequence of operations is allowable iff each deq returns the oldest enqueued value that has not yet been dequeued (returns  if queue is empty)

5 CPSC 668Set 18: Wait-Free Simulations Beyond Registers5 Consensus Algorithm for n = 2 Using FIFO Queue Initially Q = [0] and Prefer[i] =  Prefer[i] := p i 's input val := deq(Q) if val = 0 then decide on p i 's input else temp := Prefer[1 - i] decide temp one shared FIFO queue two shared registers write my input into my register use shared queue to arbitrate between the 2 procs: first one to dequeue the initial 0 wins, decision value is its input loser obtains decision value from other proc's register

6 CPSC 668Set 18: Wait-Free Simulations Beyond Registers6 Implications of Consensus Algorithm Using FIFO Queue Suppose we want to wait-free simulate a FIFO queue using read/write registers. Is this possible? No! If it were possible, we could solve consensus: –simulate a FIFO queue using registers –use simulated queue and previous algorithm to solve consensus

7 CPSC 668Set 18: Wait-Free Simulations Beyond Registers7 Extend Algorithm to More Procs? Can we use FIFO queues to solve consensus with more than 2 procs? The ability to atomically dequeue a value was key to the 2-proc alg: –one proc. learns it is the winner –the other learns it is the loser, therefore the id of the winner is obvious Not clear how to handle 3 procs. Suppose we have a different data type:

8 CPSC 668Set 18: Wait-Free Simulations Beyond Registers8 Initially First =  val := compare&swap(First, , p i 's input) if val =  then decide on p i 's input else decide val one shared C&S object simultaneously indicate the winner and the value to be decided by all the losers Consensus Algorithm Using Compare-and-Swap

9 CPSC 668Set 18: Wait-Free Simulations Beyond Registers9 Impossibility of 3-Proc Consensus with FIFO Queue Theorem (15.3): Wait-free consensus is impossible using FIFO queues and registers if n > 2. Proof: Same structure as for registers. Key difference is when considering situation when C is bivalent p 0 (C) is 0-valent and p 1 (C) is 1-valent.

10 CPSC 668Set 18: Wait-Free Simulations Beyond Registers10 Impossibility of 3-Proc Consensus with FIFO Queues p 0 and p 1 must be accessing the same FIFO queue. Case 1: Both steps are deq's. p 0 deq'sp 1 deq's C 0/101 p 1 deq's p 0 deq's 01 look same to p 2

11 CPSC 668Set 18: Wait-Free Simulations Beyond Registers11 Impossibility Proof Case 2: p 0 deq's and p 1 enq's. Case 2.1: The queue is not empty in C p 0 deq'sp 1 enq's C 0/101 p 1 enq'sp 0 deq's ?

12 CPSC 668Set 18: Wait-Free Simulations Beyond Registers12 Impossibility Proof Case 2: p 0 deq's and p 1 enq's. Case 2.2: The queue is empty in C p 0 deq's  p 1 enq's C 0/101 look the same to p 2 p 0 deq's 1 queue is empty again queue is empty queue is still empty

13 CPSC 668Set 18: Wait-Free Simulations Beyond Registers13 Impossibility Proof Case 3: Both p 0 and p 1 enq (on same queue). p 0 enq's Ap 1 enq's B C 0/101 p 1 enq's Bp 0 enq's A  : p 0 takes steps until deq'ing A  : p 1 takes steps until deq'ing B  : p 0 takes steps until deq'ing B  : p 1 takes steps until deq'ing A 01 look the same to p 2 why do  and  exist?

14 CPSC 668Set 18: Wait-Free Simulations Beyond Registers14 Impossibility Proof Case 3 cont'd: Suppose  does not exist: p 0 enq's Ap 1 enq's B C 0/101 p 1 enq's Bp 0 enq's A p 0 takes steps until deciding but never deq's A; decides 0 p 0 takes same number of steps as on the left; never deq's B; also decides 0 01

15 CPSC 668Set 18: Wait-Free Simulations Beyond Registers15 Impossibility Proof Case 3 cont'd: Prove existence of  similarly. Thus there is no wait-free algorithm for consensus with 3 procs using FIFO queues and registers.

16 CPSC 668Set 18: Wait-Free Simulations Beyond Registers16 Implications Suppose we want to wait-free simulate a compare&swap object using FIFO queues (and registers). Is this possible? Not if n > 2! If it were possible, we could solve consensus using FIFO queues (and registers): –simulate a compare&swap object using FIFO queues (and registers) –use simulated compare&swap object and c&s algorithm to solve consensus

17 CPSC 668Set 18: Wait-Free Simulations Beyond Registers17 Generalize these Arguments Previous results concerning FIFO queues and compare&swap suggest a criterion for determining if wait-free simulations exist: based on ability of the data types to solve consensus for a certain number of procs.

18 CPSC 668Set 18: Wait-Free Simulations Beyond Registers18 Consensus Number Data type X has consensus number n if n is the largest number of procs. for which consensus can be solved using only objects of type X and read/write registers. data typeconsensus number read/write register1 FIFO queue2 compare&swap∞

19 CPSC 668Set 18: Wait-Free Simulations Beyond Registers19 Using Consensus Numbers Theorem (15.5): If data type X has consensus number m and data type Y has consensus number n with n > m, then there is no wait- free simulation of an object of type Y using objects of type X and read/write registers in a system with more than m procs. XXX … reg … Y

20 CPSC 668Set 18: Wait-Free Simulations Beyond Registers20 Using Consensus Numbers Proof: Suppose in contradiction there is a wait- free simulation S of Y using X and registers in a system with k procs, where m < k ≤ n. Construct consensus algorithm for k > m procs using objects of type X (and registers): –Use S to simulate some objects of type Y using objects of type X (and registers) –Use the (simulated) type Y objects (and registers) in the k-proc consensus algorithm that exists since CN(Y) = n.

21 CPSC 668Set 18: Wait-Free Simulations Beyond Registers21 Corollaries There is no wait-free simulation of any object with consensus number > 1 using just read/write registers. There is no wait-free simulation of any object with consensus number > 2 using just FIFO queues and read/write registers.

22 CPSC 668Set 18: Wait-Free Simulations Beyond Registers22 Universality Let's now consider positive results relating to consensus number. A data type is universal if objects of that type (together with read/write registers) can wait-free simulate any data type. Theorem: If data type X has consensus number n, then it is universal in a system with at most n procs.

23 CPSC 668Set 18: Wait-Free Simulations Beyond Registers23 Proving Universality Result 1.Describe an algorithm that simulates any data type –uses compare&swap (instead of any object with consensus number n) –simulation is only non-blocking, weaker than wait-free 2.Modify to use any object with consensus number n 3.Modify to be wait-free 4.Modify to bound shared memory used

24 CPSC 668Set 18: Wait-Free Simulations Beyond Registers24 Non-Blocking Non-blocking vs. wait-free is analogous to no- deadlock vs. no-lockout for mutual exclusion. Non-blocking simulation: at any point in an execution, if at least one operation is pending (response is not yet ready to be done), then there is a finite sequence of steps by a single proc that completes one of the pending operations. Does not ensure that every pending operation is eventually completed.

25 CPSC 668Set 18: Wait-Free Simulations Beyond Registers25 Universal Construction Keep history of operations that have been applied to the simulated object as a shared linked list. To apply an operation on the simulated object, the invoking proc. must insert an appropriate "node" into the linked list: –it is convenient to put the newest node at the head of the list A compare&swap object is used to keep track of the head of the list

26 CPSC 668Set 18: Wait-Free Simulations Beyond Registers26 Details on Linked List Each linked list node has operation invocation new state of the simulated object operation response pointer to previous node (previous op) invocation state response before invocation state response before  initial state   anchor Head

27 CPSC 668Set 18: Wait-Free Simulations Beyond Registers27 Simulation Initially Head points to anchor node –represents initial state of simulated object When inv is invoked: allocate a new linked list node in shared memory, pointed to by local var point point.inv := inv repeat h := Head // h is a local var point.state, point.response := apply(inv,h.state) point.before := h until compare&swap(Head,h,point) = h do the output indicated by point.response depends on simulated data type if Head still points to same node h points to, then make Head point to new node.

28 CPSC 668Set 18: Wait-Free Simulations Beyond Registers28 Strengthenings of Algorithm To use replace compare&swap object with any object with consensus number n (the number of procs): –define a consensus object (data type version of consensus problem) –get around the difficulty that a consensus object can only be used once by adding a consensus object to each linked list node that points to next node in the list

29 CPSC 668Set 18: Wait-Free Simulations Beyond Registers29 Strengthenings of Algorithm To get a wait-free implementation, use idea of helping: procs help each other to finish pending operations (not just their own) To reduce the size of the linked list (so it doesn't grow without bound), need to keep track of which list nodes can be recycled.

30 CPSC 668Set 18: Wait-Free Simulations Beyond Registers30 Effect of Randomization Suppose we relax the liveness condition for linearizable shared memory: –operations must terminate with high probability Now a randomized consensus algorithm can be used to simulate any data type out of any other data type, including read/write registers I.e., hierarchy collapses.


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