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**Efficiency of Algorithms**

February 9th

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**Today Data cleanup algorithms Algorithm efficiency**

Copy-over Shuffle-left Converging pointers Algorithm efficiency Efficiency of data cleanup algorithms Reading: Chapter 3

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**Comparing Algorithms Algorithm There are many ways to solve a problem**

Design Correctness Efficiency Also, clarity, elegance, ease of understanding There are many ways to solve a problem Conceptually Also different ways to write pseudocode for the same conceptual idea How to compare algorithms?

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**Efficiency of Algorithms**

Efficiency: Amount of resources used by an algorithm Space (number of variables) Time (number of instructions) When design algorithm must be aware of its use of resources If there is a choice, pick the more efficient algorithm!

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**Efficiency of Algorithms**

Does efficiency matter? Computers are so fast these days… Yes, efficiency matters a lot! There are problems (actually a lot of them) for which all known algorithms are so inneficient that they are impractical Remember the shortest-path-through-all-cities problem from Lab1…

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**Data Cleanup Algorithms**

What are they? A systematic strategy for removing errors from data. Why are they important? Errors occur in all real computing situations. How are they related to the search algorithm? To remove errors from a series of values, each value must be examined to determine if it is an error. E.g., suppose we have a list d of data values, from which we want to remove all the zeroes (they mark errors), and pack the good values to the left. Legit is the number of good values remaining when we are done. d d2 d3 d4 d5 d d7 d8 Legit

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**Data Cleanup: Copy-Over algorithm**

Idea: Scan the list from left to right and copy non-zero values to a new list Copy-Over Algorithm (Fig 3.2) Get values for n and the list of n values A1, A2, …, An Set left to 1 Set newposition to 1 While left <= n do If Aleft is non-zero Copy A left into B newposition (Copy it into position newposition in new list Increase left by 1 Increase newposition by 1 Else increase left by 1 Stop

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**Data Cleanup: The Shuffle-Left Algorithm**

Idea: go over the list from left to right. Every time we see a zero, shift all subsequent elements one position to the left. Keep track of nb of legitimate (non-zero) entries How does this work? How many loops do we need?

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**Shuffle-Left Algorithm (Fig 3.1)**

Get values for n and the list of n values A1, A2, …, An Set legit to n Set left to 1 Set right to 2 Repeat steps 6-14 until left > legit 6 if Aleftt ≠ 0 7 Increase left by 1 8 Increase right by 1 9 else 10 Reduce legit by 1 Repeat until right > n Copy Aight into Aright-1 Increase right by 1 14 Set right to left + 1 15 Stop

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**Exercising the Shuffle-Left Algorithm**

d d2 d3 d4 d5 d d7 d8 legit

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**Data Cleanup: The Converging-Pointers Algorithm**

Idea: One finger moving left to right, one moving right to left Move left finger over non-zero values; If encounter a zero value then Copy element at right finger into this position Shift right finger to the left

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**Converging Pointers Algorithm (Fig 3.3)**

Get values for n and the list of n values A1, A2,…,An Set legit to n Set left to 1 Set right to n Repeat steps 6-10 until left ≥ right If the value of Aleft≠0 then increase left by 1 Else Reduce legit by 1 Copy the value of Aright to Aleft 10 Reduce right by 1 if Aleft=0 then reduce legit by 1. Stop

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**Exercising the Converging Pointers Algorithm**

d d2 d3 d4 d5 d d7 d8 legit

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**Efficiency of Algorithms**

How to measure time efficiency? Running time: let it run and see how long it takes On what machine? On what inputs? We want a measure of time efficiency which is independent of machine, speed etc Look at an algorithm pseudocode and estimate its running time Look at 2 algorithm pseudocodes and compare them

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**Time Efficiency Is this accurate? Time efficiency depends on input**

(Time) efficiency of an algorithm: the number of pseudocode instructions (steps) executed Is this accurate? Not all instructions take the same amount of time… But..Good approximation of running time in most cases Time efficiency depends on input Example: the sequential search algorithm In the best case, how fast can the algorithm halt? In the worst case, how fast can the algorithm halt?

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**Efficiency of an algorithm**

worst case efficiency is the maximum number of steps that an algorithm can take for any collection of data values. Best case efficiency is the minimum number of steps that an algorithm can take any collection of data values. Average case efficiency - the efficiency averaged on all possible inputs - must assume a distribution of the input - we normally assume uniform distribution (all keys are equally probable) If the input has size n, efficiency will be a function of n

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**Worst Case Efficiency for Sequential Search**

Get the value of target, n, and the list of n values 1 Set index to Set found to false Repeat steps 5-8 until found = true or index > n n 5 if the value of listindex = target then n Output the index Set found to true 0 8 else Increment the index by n 9 if not found then 10 Print a message that target was not found 0 Stop Total n+5

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**Analysis of Sequential Search**

Time efficiency Best-case : 1 comparison target is found immediately Worst-case: 3n + 5 comparisons Target is not found Average-case: 3n/2+4 comparisons Target is found in the middle Space efficiency How much space is used in addition to the input?

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**Order of Magnitude Worst-case of sequential search: Simplification:**

3n+5 comparisons Are these constants accurate? Can we ignore them? Simplification: ignore the constants, look only at the order of magnitude n, 0.5n, 2n, 4n, 3n+5, 2n+100, 0.1n+3 ….are all linear we say that their order of magnitude is n 3n+5 is order of magnitude n: n+5 = (n) 2n +100 is order of magnitude n: 2n+100=(n) 0.1n+3 is order of magnitude n: 0.1n+3=(n) ….

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**Efficiency of Copy-Over**

Best case: all values are zero: no copying, no extra space Worst-case: No zero value: n elements copied, n extra space Time: (n) Extra space: n

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**Efficiency of Shuffle-Left**

Space: no extra space (except few variables) Time Best-case No zero value: no copying ==> order of n = (n) Worst case All zero values: every element thus requires copying n-1 values one to the left n x (n-1) = n2 - n = order of n2 = (n2) (why?) Average case Half of the values are zero n/2 x (n-1) = (n2 - n)/2 = order of n2 = (n2)

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**Efficiency of Converging Pointers Algorithm**

Space No extra space used (except few variables) Time Best-case No zero value No copying => order of n = (n) Worst-case All values zero: One copy at each step => n-1 copies order of n = (n) Average-case Half of the values are zero: n/2 copies

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**Data Cleanup Algorithms**

Copy-Over worst-case: time (n), extra space n best case: time (n), no extra space Shuffle-left worst-case: time (n2), no extra space Best-case: time (n), no extra space Converging pointers worst-case: time (n), no extra space

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