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 rozwnw jIvn iv`c kMm Awaux vwlIAW vsqUAW ijvyN sMdUk,ie`t,AlmwrI,islMfr,kIp,gyNd Awid AsIN dyKdy hW [hryk vsqU dI smweI huMdI hY[iehnW nUM Tos AwikRqIAW.

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Presentation on theme: " rozwnw jIvn iv`c kMm Awaux vwlIAW vsqUAW ijvyN sMdUk,ie`t,AlmwrI,islMfr,kIp,gyNd Awid AsIN dyKdy hW [hryk vsqU dI smweI huMdI hY[iehnW nUM Tos AwikRqIAW."— Presentation transcript:

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2  rozwnw jIvn iv`c kMm Awaux vwlIAW vsqUAW ijvyN sMdUk,ie`t,AlmwrI,islMfr,kIp,gyNd Awid AsIN dyKdy hW [hryk vsqU dI smweI huMdI hY[iehnW nUM Tos AwikRqIAW kihMdy hn[  Tos AwikRqIAW keI Akwr dIAW huMdIAW hn[ijvyN Gxwv,Gx,islMfr,SMkU(kon),golw,ArD golw Awid[

3  Gxwv dy Awieqwkwr Plk huMdy hn Aqy hr do snm`K Plk smwn huMdy hn[ijvyN ie`k AlmwrI,bUtW dw f`bw Awid[  Gxwv dI ku`l sqHw dw Ky.=(2 lb+2bh+2hl) =2(lb+bh+hl)  Gxwv dI pwsvIN sqHw dw Ky.= 2hl+2bh =2(l+b)h  Gxwv dw Awieqn= lbh

4  Gx dy Cy smwn vrgwkwr Plk huMdy hn[ijvyN cwh p`qI dw f`bw,k`pVy Dox vwlw swbx Awid[  Gx dI ku`l sqHw dw Ky.= 6 a ¿ 1vrg dw Ky. = 6 ¿ a 2 =6a 2  Gx dI pwsvIN sqHw dw Ky.= 4 a 2  Gx dw Awieqn= a 3 ij`Qy ( a ) Gx dw iknwrw hY[

5  rozwnw jIvn iv`c AsIN gol QMmH,pwxI dI pweIp,gYs islMfr Awid vylxwkwr cIzw dyKdy hW[iehnW dy dovyN isry c`krwkwr huMdy hn,dovyN c`kr brwbr huMdy hn[  vylx dI sqHw dw Ky.=Awieq dw KyqrPl =lMbweI ¿cOVweI =2 Π rh  ku`l sqHw dw Ky.= Awieq dw KyqrPl+do c`krw dw KyqrPl =2 Π rh=2 r 2 =2 Π r(h+r)  islMfr dw Awieqn= Π r 2 h

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7  Gx dI pwsvIN sqHw dw KyqrPl= 4a 2 6a 2 (TIk jW glq)  Gxwv dw Awieqn=(lM:+cO:+au:) jW (lM:¿cO:¿au:)

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