1. 1 Press Ctrl-A ©G Dear2009 – Not to be sold/Free to use Surface Area of Cylinders Stage 6 - Year 12 General Mathematic (HSC)

2. 2 Surface Area Closed Cylinder Top A 1 =  r 2 Bottom A 2 =  r 2 Middle Curved Surface A 3 = 2  r x h Circumference Surface Area = 2 r22 r2 + 2  rh closeda Nb. A closed cylinder has a lid. h End of Slide

3. 3 Surface Area Cylinder 5cm 4cm SA = 2  r 2 + 2  rh = 2 x  x 4 2 + 2 x  x 4 x 5 ≈ 226.19 cm 2 End of Slide

4. 4 Surface Area Open Cylinder No Top Bottom A 2 =  r 2 Middle Curved Surface A 3 = 2  r x h h Surface Area =  r2 r2 + 2  rh openno Nb. An open cylinder has no lid. End of Slide

5. 5 Surface Area Cylinder 5cm 4cm SA =  r 2 + 2  rh =  x 4 2 + 2 x  x 4 x 5 ≈ 175.93 cm 2 End of Show