Presentation on theme: "T6. DESIGN OF REINFORCED CONCRETE BEAM Reinforced concrete framed building T6. Design of reinforced concrete beam page 1. Alaprajz Floor plan Beam: linear."— Presentation transcript:
T6. DESIGN OF REINFORCED CONCRETE BEAM Reinforced concrete framed building T6. Design of reinforced concrete beam page 1. Alaprajz Floor plan Beam: linear member subjected to flexure and shear (N=0). Example: Bending design of slab L1 and beam G1.
I. Design of slab L1 I.1. Geometry, model, loads I.1.1. Model, Geometry: two-span continuous beam b= determine l eff page 2. I.1.2. Loads: floor Dead load -Self-weight: Floor layers: 2 cm glued ceramic 7 cm concrete topping 3 cm floating layer (EPS) + foil 3 cm polystyrene (installation zone) 18 cm monolithic reinforced concrete slab Σ T6. Design of reinforced concrete beam Reinforced concrete design aids using Eurocode (SR p.12.)
page 3... Design value of the total load of 1 m wide strip of the slab: Live load -Variable load: substituting load of light partition walls: I.I.3 Cross-sectional data width: b= thickness: h= concrete cover: main reinforcement: 12/110 (SR p.9.) distribution steel: effective depth: T6. Design of reinforced concrete beam In the span Above intermediate support
I. 2. Calculation of internal forces page 4. R.C. inhomogeneous, materials of the cross-section are isotropic and perfectly plastic at limit state Two-span continuous beam (SR. p.14) Loading schemes: Above intermediate support – total load in the span + first and last supports – partial load T6. Design of reinforced concrete beamT7. Design of reinforced concrete beam 2, shear
page 5. f yk Material properties: Concrete C25/30-24 f ck Reinforcing steelB500 (SR. p.7) (SR. p.8.) Limit state: Calculation of M Rd : compressed extreme fiber fails, and tension reinforcement yields for normally reinforced cross-section N s = f yd a s Ifreinforcement yields ( SR. p.8. table) Force equilibrium : Checking of yielding of steel: T6. Design of reinforced concrete beam
page 6. Moment equilibrium: about the center of gravity of compressive stresses: Constructional rules: (SR. p.49+ p.51) Minimum quantity of tensile reinforcement ‰ : Not the end of the example: Shear, Deformations, Design of reinforcement … next practical Distribution steel: at least 20% of the main reinforcement: T6. Design of reinforced concrete beam
II. Design of beam G1 Determination of the necessary steel quantity: As=? T6. Design of reinforced concrete beam page 7.
To be continued! T6. Design of reinforced concrete beam page 8.