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Rectangular Function Impulse Function Continuous Time Systems 2.4 &2.6.

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Presentation on theme: "Rectangular Function Impulse Function Continuous Time Systems 2.4 &2.6."— Presentation transcript:

1 Rectangular Function Impulse Function Continuous Time Systems 2.4 &2.6

2 How do you represent a unit rectangular function mathematically?

3 Fundamental(1) u(t)

4 Fundamental(2) u(t-0.5) u(-t-0.5) u(t+0.5) u(-t+0.5)

5 Block Function (window) rect(t/T) Can be expressed as u(T/2-t)-u(-T/2-t) – Draw u(t+T/2) first; then reverse it! Can be expressed as u(t+T/2)-u(t-T/2) Can be expressed as u(t+T/2)u(T/2-t) -T/2T/2 1 -T/2T/2 1 -T/2T/2 1 -T/2T/2

6 Application The rectangular pulse can be used to extract part of a signal

7 A Simple Cell Phone Charger Circuit (R1 is necessary) Another Application: Signal strength indicator

8 Mathematical Modeling Modify the unit rectangular pulse: 1.Shift to the right by To/4 2.The period is To/2 V1(t)V1(t-To)V1(t-2To)

9 Application of Impulse Function The unit impulse function is used to model sampling operation, i.e. the selection of a value of function at a particular time instant using analog to digital converter.

10 Generation of an Impulse Function Ramp function epsilon approaches 0

11 Shifted Impulse Function 0 0to  (t)  (t-to)

12 The Impulse Function We use a vertical arrow to represent 1/ε because g(t) Increases dramatically as ε approaches 0.

13 Another Definition of the Impulse Function

14 Mathematica Connection

15 Property f[t] f[t-2]

16 Property

17 Shifted Unit Step Function Slope is sharp at t=2

18 Property

19 g(at), a>1, e.g. 2 area: 1/ ε ε /2=1/2 1/ ε 2ε=2 t o /2 t o /2+ ε/2 1/ ε g(2t), 1 1/2 δ(t)

20 Property g(at), a<1, e.g. 1/2 area: 1/ ε 2ε=2 2t o 2t o + 2ε 1/ ε g(2t), 1 δ(t) 2 2t o

21 Property  (t)

22 Example

23 A system is an operation for which cause-and-effect relationship exists – Can be described by block diagrams – Denoted using transformation T[.] System behavior described by mathematical model Continuous-Time Systems T [.] X(t)y(t) (meat grinder)

24 Inverting Amplifier Vout=-(R1/R2)

25 Inverting Summer Example Vout=-RF(V1/R1+V2/R2) If RF/R1=1, RF/R2=1 Vout=-(V1+V2)

26 Multiplier

27 Parallel Connection

28 Cascade Connection

29 Feedback


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