1. Scan conversion of Line , circle & ellipse
Computer graphics
Scan conversion of Line , circle & ellipse

2. Scan conversion
is the process of converting basic, low level objects in to
their corresponding pixel map representations. This is often
an approximation to the object, since the frame buffer is a discrete grid.

3. Line Drawing algorithms
Direct or floating or simple algorithm
Digital Differential Analyzer algorithm (DDA)
Bresenham's algorithm or midpoint algorithm
General Bresenham's algorithm
Description:
Given the specification for a straight line (parameters).
find the collection of addressable pixels which most closely approximates this line (mathematical equations) .
Draw the scan conversion of lines (frame buffer map).
Goals
Straight lines should appear straight.
Lines should start and end accurately.
Lines should be drawn as rapidly as possible.
matching endpoints with connecting lines.
Lines should have constant brightness.

4. Direct method Description:
1. A straight line may be defined by two endpoints and an equation
If the two endpoints used to specify a line are (X1,Y1) and (X2,Y2) ,then the equation of the line is used to describe the X , Y coordinates of all the pointes that lie between these two endpoints. x1 y1 x2 Y2
2. The line equation depend on octant which contain line
Dx = x2 - x1
Octant covering in 2D space
Dy = y2 - y1
dy > dx
negative
VIII
dy < dx
VII
positive VI V IV
III II I
ratio
Slope (m)
Octant

5. x go from x1 to x2 with values (+1) or (-1)
3. The equation of straight line in octants Dx > Dy
Y= M * X + B
Where: M is the slope of the line.
B is the Y intercept. B= Y – M * X
Note : The slope between any point (X1,Y1) on the line and (X2,Y2)
M = DY/ DX
x go from x1 to x2 with values (+1) or (-1)
EX1:- draw line between(0,1) and ( 5,4)
Sol:- M= 4 -1 / 5-0 = 3/5 = 0.6 , B=1 , y= (0.6)*X+1
x go from x1 to x2 with integer values (+1) in each step x 1 2 3 4 5 y
1.6
2.2
2.8
3.4
draw
(0,1)
(1,2)
(2,2)
(3,3)
(4,3)
(5,4)

6. y go from y1 to y2 with values (+1) or (-1)
4. The equation of straight line in octants Dy > Dx
X= Y – B / M
y go from y1 to y2 with values (+1) or (-1)
Ex: draw line between(1,2) and ( 3,6)
sol: m= 2 , B= 0 X Y
draw 1 2
(1,2)
1.5 3
(2.3) 4
(2,4)
2.5 5
(3,4) 6
(3,6)

7. Ex: draw line between(2,-2) and ( 6,-6) Sol:-
m= -4 / 4 = -1 , B= -2 – (-1*2) = 0 X Y
draw 2 -2
(2,-2) 3 -3
(3,-3) 4 -4
(4,-4) 5 -5
(5,-5) 6 -6
(6,-6)

8. features:
The algorithm performs a floating-point multiplication for every step in x. This method therefore requires an enormous number of floating-point multiplications, and is therefore expensive.
Round functions are needed
not general for all octants
Can get gaps in the line.
example:
y = 10.x + 2
x=1, y=12;
x=2, y=22.

9. Algorithm for octant with x1<x2
Dim img As New Bitmap(1, 1)
img.SetPixel(0, 0, Color.Blue)
dx = x2 - x1
dy = y2 - y1
m = dy / dx
b = y1 - m * x1
For x = x1 To x2
e.Graphics.DrawImage(img, x, Int(y))
y = m * x + b
Next
HW: develop direct method to draw lines in octants(( Dx >Dy), slope( positive , negative))

10. length=max( Abs(y2-y1) , Abs(x2-x1)
Digital Differential Analyzer (DDA)
Description:
1. We calculate the length of the line in the X direction ( number of pointes) by the equation
Abs(x2-x1)
2. calculate the length of the line in the Y direction
( number of pointes) by the Equation
Abs(y2-y1)
Where ABS is a function takes the positive of the arguments.
3. The Length estimates is equal to the larger of the
above two equations.
length=max( Abs(y2-y1) , Abs(x2-x1)

11. 4. The increment steps ( dX and dY ) are used to
increment the X and Y coordinates for the next
pointes to be plotted.
Dx= (x2-x1) / length
Dy= (y2-y1) / length
5. each point will calculate as equation
x = x + Dx
y = y + Dy
6. Integer function works as follow( round down)
Ex. Integer (8.5) = 8
Integer (-8.5) = -9
7. first point we add 0.5
x = x
y = y

12. Ex1: Consider the line from (-8,-4) to (0,0)Use DDA to
scan conversion of line.
Sol 1 :
X1=-8 ; Y1= ; X2= ; Y2=0 ;
Length= 8
dX= 1; dY=0.5 ; X= ; Y=-3.5 I X Y
draw
-7.5
-3.5
(-8,-4) 1
-6.5 -3
(-7,-3) 2
-5.5
-2.5
(-6,-3) 3
-4.5 -2
(-5,-2) 4
-1.5
(-4,-2) 5 -1
(-3,-1) 6
-0.5
(-2,-1) 7
(-1,0) 8
0.5
(0,0)

13. Algorithm DDA
Start
Length=ABS (X2-X1)
If length < ABS (Y2-Y1) Then Length=ABS (Y2-Y1)
dX = (X2 - X1) / Length
dY = (Y2 - Y1) / Length
X=X
Y=Y
Plot (Integer (X) , Integer (Y))
For I=1 to Length
Begin
X=X + dX
Y=Y + dY
End
Finish

14. Features of DDA 1- The algorithm is orientation dependent
2- The end point accuracy deteriorates
3- The algorithm suffer from the fact that it
must be performed using floating point arithmetic
HW1: Consider the line from (0,0) to (-8,-4)
evaluate the DDA algorithm