Presentation is loading. Please wait.

Presentation is loading. Please wait.

Introduction to C-13 NMR The 13C nucleus is present in only 1.08% natural abundance. Therefore, acquisition of a spectrum usually takes much longer than.

Similar presentations


Presentation on theme: "Introduction to C-13 NMR The 13C nucleus is present in only 1.08% natural abundance. Therefore, acquisition of a spectrum usually takes much longer than."— Presentation transcript:

1 Introduction to C-13 NMR The 13C nucleus is present in only 1.08% natural abundance. Therefore, acquisition of a spectrum usually takes much longer than in 1H NMR. The magnetogyric ratio of the 13C nucleus is about 1/4 that of the 1H nucleus. Therefore, the resonance frequency in 13C NMR is much lower than in 1H NMR. (75 MHz for 13C as opposed to 300 MHz for 1H in a 7.04 Tesla field). At these lower frequencies, the excess population of nuclei in the lower spin state is reduced, which, in turn, reduces the sensitivity of NMR detection. Unlike 1H NMR, the area of a peak is not proportional to the number of carbons giving rise to the signal. Therefore, integrations are usually not done. Each unique carbon in a molecule gives rise to a 13C NMR signal. Therefore, if there are fewer signals in the spectrum than carbon atoms in the compound, the molecule must possess symmetry. When running a spectrum, the protons are usually decoupled from their respective carbons to give a singlet for each carbon atom. This is called a proton-decoupled spectrum.

2 Carbon-13 Chemical Shift Table
CC triple bonds

3 Alkane: 2-methylpentane

4 Alcohol: 2-hexanol

5 Alkyl Halide: 3-bromopentane

6 Alkene: 1-hexene

7 Aromatic Ring: eugenol

8 Carboxylic Acid: pentanoic acid

9 Ester: ethyl valerate

10 Amide: pentanamide

11 Ketone: 3-methyl-2-pentanone

12 Aldehyde: 2-methylpentanal

13 Symmetry in C-13 NMR Each unique carbon in a molecule gives rise to a 13C NMR signal. Therefore, if there are fewer signals in the spectrum than carbon atoms in the compound, the molecule must possess symmetry. Examples:

14 Enantiotopic vs Diastereotopic CH3’s
* * * * *

15 Determine the number of signals in the proton-decoupled
C-13 NMR spectrum of each of the following compounds:

16 Carbon-13 NMR Spectrum of Geraniol
ppm Carbon # 8 9

17 T1 and NOE Effects in C-13 NMR
Because of unequal T1 and NOE effects, peaks heights vary widely in C-13 NMR. This is why C-13 spectra are normally not integrated. 3 2 4 Carbon T1 (sec) NOE CH3 16 0.61 1 89 0.56 2 24 1.6 3 1.7 4 17 1 CH3

18 Carbon-13 Proton-Coupled Patterns

19 Carbon-13 Proton-Coupled Spectrum of Ethyl Phenylacetate
Difficult to interpret C=O Typical coupling constants for 13C-1H one- bond couplings are between 100 to 250 Hz.

20 DEPT Spectra Quaternary carbons (C) do not show up in DEPT.

21 Simulated DEPT Spectra of Ethyl Phenylacetate
Normal C-13 spectrum

22 DEPT Spectra of Codeine

23 Predict the normal C-13, DEPT-90, and DEPT-135
spectra of ipsenol, whose structure appears below.

24 DEPT Spectra of Ipsenol
CDCl3 Normal C-13 spectrum

25 Determine the number and appearance of the signals in the DEPT-45, DEPT 90,
and DEPT 135 NMR spectrum of each of the following compounds:


Download ppt "Introduction to C-13 NMR The 13C nucleus is present in only 1.08% natural abundance. Therefore, acquisition of a spectrum usually takes much longer than."

Similar presentations


Ads by Google