Download presentation

1
Chapter 12 Chemical Kinetics

2
**Kinetics Study of Speed at which reactions take place**

Effect of each reactant Effect of concentration Mechanisms Reaction process Energy requirements for reactions

3
Reaction Rate Change in concentration of reactant or product per unit of time Rate = Δ[A]/ Δt Rates decrease as time increases Rates are given positive values If you know the rate of one species in a reaction you can calculate the others

4
**2NO2 2NO + O2 Page 558 Based on the graph What do you notice?**

Calculate the rate of NO2 0s to 50.s NO2 50.s to 100.s O2 0s to 50.s 2NO2 2NO + O2

5
**Rate Laws Only depends on the forward reaction**

An expression that shows how the rate depends on the concentrations of reactants A way of determining rate or concentration Depends on what you know.

6
**Form of the Rate Law Assuming the reaction A B + C Rate = k[A]n**

k and n are both experimentally determined k is a constant called the rate constant Units vary depending on n n is the order Does NOT depend on balanced equation Whole numbers including zero and fractions

7
**Units of k Depends on what number n is**

k has units that gives the rate units of mol/L*s Consider - Rate = k[A]n What are the units of k if n is 1? 2? 0?

8
**Multiple Reactants Consider the reaction A + B C**

What is the rate law? Rate = k[A]n[B]m What are the units for k when n is 1 & m is 1

9
**Specifically These types of rate laws are differential rate laws**

Just called rate laws There are also integrated rate laws The form you use depends on the data you have

10
Homework P. 598 #’s 17,18,19,20

11
**Method of Initial Rates**

12
Integrated Rate Laws A way of determining the order and rate constant of a reaction when time and concentration data is known. Must be for a single reactant. Or have one in excess Equations for 0th, 1st, and 2nd order Use equations as tests for order

13
**1st Order ln[A] = -kt + ln[A]o [A] concentration of reactant at time t**

[A]o concentration of reactant at time t=0 k is the rate constant This is the equation of a ________? LINE Y axis is ln[A], X axis is t The slope is the rate constant

14
1st Order If a graph of ln[A] vs t is a straight line then the reaction is 1st order A straight line is the check for all of these

15
**2N2O5 4NO2 + O2 Example Use the data to determine the rate law.**

Determine the rate constant. Determine the [N2O5] at 2000.s Time (s) [N2O5] .100 100. .0614 300. .0233 600. .00541 900. .00126

16
1st Order Half Life The half life is the time required for a reactant to reach half of its previous concentration Meaning [A] = [A]o/2 Derive Half Life Equation t1/2=ln2/k Half life is always the same for first order kinetics

18
**2N2O5 4NO2 + O2 Example Use the data to determine the rate law.**

Determine the rate constant. Determine the [N2O5] at 2000.s Determine the half life Time (s) [N2O5] .100 100. .0614 300. .0233 600. .00541 900. .00126

19
**2nd Order Integrated Rate Law 1/[A] = kt + 1/[A]o**

This is the equation of a ________? LINE Y axis is 1/[A], X axis is t The slope is the rate constant Half Life t1/2 = 1/(k[A]o) Each half life is double the previous

20
**2C4H6 C8H8 Example #33 p. 600 Determine the rate law**

Determine the rate constant. Determine the half-life Time (s) [C4H8] .017 195 .016 604 .015 1246 .013 2180 .011 6210 .0068

22
**0th Order Integrated Rate Law [A] = -kt + [A]o**

This is the equation of a ________? LINE Y axis is [A], X axis is t The slope is the rate constant Half Life t1/2 = [A]o/2k Each half life is the same

23
**2N2O 2N2 + O2 Determine the rate law. Determine the rate constant.**

Determine the half-life Time (s) [C4H8] .44 10. .33 20. .22 30. .11 40.

24
Page 578

25
Homework Page 599 #’s 27,29,30,32

26
Reaction Mechanism A series of elementary steps that must satisfy two requirements The sum of the steps must equal the overall balanced equation Must agree with the rate law Elementary Step – Steps in the mechanism. (Think back to organic)

27
Cont. Intermediates – Species that are produced in one elementary step and consumed in another Not part of the overall balanced equation Rate-determining step – Slowest step in a reaction that determines the rate Molecularity – Number of species that must collide to produce an elementary step

28
**Molecularity Table Elementary Step Molecularity Rate Law A Products**

Unimolecular Rate=k[A] 2 A Products Bimolecular Rate=k[A]2 A + B Products Rate=k[A][B]2 2A + B Products Termolecular Rate=k[A]2[B] A+B+C Products Rate=k[A][B][C]

29
NO2 + CO NO + CO2 The reaction above has an experimentally determined rate law of Rate=k[NO2]2 Is the proposed mechanism possible? Explain Step 1 = NO2 + NO2 NO3 + NO Step 2 = NO3 + CO NO2 + CO2

30
**Collision Model for Kinetics**

For a reaction to occur particles must collide to react. Must collide in the proper orientation Must collide with enough energy Activation Energy

31
Proper Orientation + Images from:

32
**Improper Orientation + **

Images from:

33
**Activation Energy (Ea)**

The energy required to convert atoms or molecules into their transition state Minimum energy required for effective collisions Can be found by running the same reaction at different temps. Use Arrhenius Equation

34
**Arrhenius Equation K = rate constant Ea = Activation Energy**

R = Energy Gas Constant J/mol*K T = Temp in K A = Frequency Factor Equation of a line Y is ln k X is 1/T Slope is –Ea/R

35
**Find the activation energy**

2N2O5 4NO2 + O2 Rate Constant Temp (ºC) 2.0x10-5 20 7.3x10-5 30 2.7x10-4 40 9.1x10-4 50 2.9x10-3 60

36
2 Temp. Ea Equation You can manipulate the Arrhenius Equ if you only have to temps and rate constants by subtracting the lower temp equation from the higher temp equation

37
Catalysts Chemical that speeds up a chemical reaction but is not consumed in the reaction Do this by Lowering activation energy Provide alternate reaction pathways Increase effective collisions

38
Cont. Below are two steps in the destruction of ozone. What is the overall rxn? What is the catalyst? What is the intermediate? Cl + O3 ClO + O2 O + ClO Cl + O2

39
Homework Page 602 #’s 45,48,49,54

Similar presentations

OK

A.P. Exam Review Regular Review Day 4. Big Idea #4 Rates of chemical reactions are determined by details of the molecular collisions.

A.P. Exam Review Regular Review Day 4. Big Idea #4 Rates of chemical reactions are determined by details of the molecular collisions.

© 2018 SlidePlayer.com Inc.

All rights reserved.

To make this website work, we log user data and share it with processors. To use this website, you must agree to our Privacy Policy, including cookie policy.

Ads by Google

Ppt on different types of dance forms productions Ppt on microcontroller based home security system Ppt on earth and universe Ppt on hdfc bank Ppt on insurance companies in india Ppt on astronomy and astrophysics major Ppt on conference call etiquette tips Download ppt on reaching the age of adolescence for class 8 Ppt on population census 2011 Ppt on accounting standard 13