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THERMAL PHYSICS. Temperature and the zeroth Law of Thermodynamics 2 objects are in thermal contact if energy can be exchange between them 2 objects are.

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Presentation on theme: "THERMAL PHYSICS. Temperature and the zeroth Law of Thermodynamics 2 objects are in thermal contact if energy can be exchange between them 2 objects are."— Presentation transcript:

1 THERMAL PHYSICS

2 Temperature and the zeroth Law of Thermodynamics 2 objects are in thermal contact if energy can be exchange between them 2 objects are in thermal equilibrium if they are in thermal contact and there is no net exchange of energy (ex: in fig) Zeroth law of thermodynamics (law of equilibrium) If objects A and B are separately in thermal equilibrium with a third object C, then A and B are in thermal equilibrium with each other. Two objects in thermal equilibrium with each other are the same temperature

3 Thermometers and temperature scale Review: - thermometers -Celsius temperature scale( freezing point, boiling point) The ct. Volume gas thermometer and the Kelvin scale In a gas thermometer, the temperature reading are independent of the substance used in the thermometer The behavior observed in this device is variation of pressure with temperature of a fixed volume of gas

4 If the temperatures are measured with various gas thermometers containing different gases, the readings are nearly independent of the type of gas used The pressure extrapolates to zero when temperature is -273.16 o C P=0, T= -273.16 o C –absolute zero

5 Absolute zero is used for the Kelvin temperature scale Tc =T-273.15 The triple point of water, which is the single temperature and pressure at which water, water vapor and ice can coexist in equilibrium SI unit T = K Kelvin- define as 1/273.16 of the temperature of the triple point of water

6 The Celsius, Kelvin and Fahrenheit Temperature Scale 0 o C=32oF; 100 o C= 212 o F T F =9/5 T C +32 T C =5/9(T F -32) ΔT F =9/5ΔT C

7 Thermal Expansion of solids and liquids Thermal expansion: as temperature of the substance increase its volume increase If the thermal expansion of an object is sufficiently small compared with the object s initial dimensions, then the change in any dimenΔsion is proportional with the first power of the temperature change: ΔL =α L 0 ΔT; L 0 - initial length α- the coefficient of linear expansion for a given material SI unit ( o C) -1

8 Area: A 0 =L 0 2 L=L 0 +α L 0 ΔT A= L 2 =(L 0 +α L 0 ΔT)(L 0 +α L 0 ΔT)= =L 0 2 +2α L 0 2 ΔT+ (α L 0 ΔT )2 αΔT<< 1, squaring it makes much smaller A = L 0 2 +2α L 0 2 ΔT A=A 0 +2α A 0 ΔT ΔA =γ A 0 ΔT; γ =2α- coefficient of area expansion ΔV =β V 0 ΔT; β =3α – coefficient of volume expansion

9 Macroscopic description of an ideal gas Ideal gas – is a collection of atoms or molecules that move randomly and exert no long range forces on each other Each particle of the ideal gas is individually point- like, occupying a negligible volume (gas maintained at a low pressure or a low density) n-nr of moles- the amount of gas in a given volume N A =6.02x10 23 particle/mole- Avogadros number

10 The number of moles: n= m /molar mass, m-mass, molar mass- the mass of one mole of that substance One mole of any substance is that amount of the substance that contains as many particles as there are atoms in 12g of the isotope carbon-12 m atom = molar mass/NA

11 Supposed an ideal gas is confined to a cylinder container I Boyles law: when the gas is kept at a constant T, its P is inversely proportional to its V (T=ct., P~V) II Charles Law: P = ct., V~T III Gay Lussac's Law: V =ct, P~T Ideal gas Law: PV=nRT R-universal gas constant R = 8.31 J/mol K (in P=Pa and V=cm 3 ) R=0.0821 L atm /mol K(1L = 10 3 cm 3 )

12 n = N / N A, n- nr. of molecules, N-nr. of the molecules in the gas PV = (N / N A )RT PV = N k B T k B - Boltzmann's constant k B = R / NA= 1.38 x 10 -23 J/K

13 The kinetic theory of gases 1. The number of molecules in the gas is large, and the average separtion between them is large compared with their dimensions 2. The molecules obey Newtons lows of motion, but as a whole they move randomly 3. The molecules interact only through short- range forces during elasstic collisions 4. The molecules make elastic collision with the walls 5. All molecules in the gas are identical

14 Molecular model for the pressure of an ideal Gas Δp x = m v x -(- mv x ) =2 mv x F1= Δp x /Δt = 2m v x / Δt Δt = 2d/v x F1= 2m v x / 2d/v x = m v x 2 /d For N molecules: v x 2 = (v 1x 2 + v 2x 2 +…+ v Nx 2 )/N F= (Nm/d) v x 2 v x 2 = 1/3 v 2 F= N/3(mv 2 /d) P = F/A =F/d 2 = 2/3(N/V)(1/2 mv 2 ) =P

15 P=2/3(N/V)(1/2 mv 2 ) – the pressure is proportional to the number of molecules per unit volume and to the average transitional kinetic energy of a molecule Molecular interpretation of Temperature PV= 2/3 N(1/2 mv 2 ) PV = N k B T T= 2/(3k B ) (1/2 mv 2 )- the temperature of gas is a direct measure of the average molecular kinetic energy of gas

16 1/2 mv 2 =3/2 k B T KE total = N(1/2 mv 2 ) =3/2 Nk B T k B = R / NA; n = N / N A KE total = 3/2 n RT –the total transitional KE of the system of molecules is proportional to the absolute temperature of the system The Internal energy U for a monatomic gas: U= 3/2 n RT The root-mean-square (rms) speed of the molecule v rms = v 2 = 3k B T/m= 3RT/M (M- molar mass)

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18 Ex: if a gas in a vessel consists of a mixture of hydrogen and oxygen, the hydrogen molecules with a molar mass of 2.0x10 -2 kg/mol, move four time faster than oxygen molecules, with molar mass 32x10 -3 kg/mol. IF we calculate the rms speed for Hydrogen at room temperature(300K): v rms =3RT/M =3(8.31 j/mol K)(300K) /(2.0x10 -2 kg/mol)= 1.9 x 10 3 m/s This is 17% of escape speed for Earth


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