Download presentation

Presentation is loading. Please wait.

Published byAshton Ortiz Modified over 4 years ago

1
Calculations Based on Equations Intermediate 2 Chemistry ? ?

2
Balanced Equations Allow us to calculate the quantity of product from a particular quantity of reactant C 2 H 4 + H 2 O C 2 H 6 O 1 mole From the balanced equation, 1 mole of ethene reacts with 1 mole of water, to produce 1 mole of ethanol.

3
Example 1 Suppose you want to work out how much ethanol can be produced by the hydration of 10 g ethene… C 2 H 4 + H 2 O C 2 H 6 O 1. Balanced equation 1 mole 2. Moles ratio So… 28 g46 g 3. Gram formula masses And therefore… 1 g 4. What 1 would give Which means… 46 g 28 g 5. What you actually have But we have… 10 g 10 x 46 g 28 g = 16.4 g

4
Example 2 Try the following problem: What would be the yield of ammonia obtained in the reaction between 3 kg of hydrogen with excess nitrogen? 1. Balanced equation 2. Moles ratio 3. Gram formula masses 4. What 1 would give 5. What you actually have N 2 + H 2 NH 3 32 = 17 kg 3 moles2 moles So… 3 x 2 g 2 x 17 g 6 g34 g And therefore… 1 g 34 g 6 Which means… 34 g 6 x 3 3 kg But we have…

Similar presentations

Presentation is loading. Please wait....

OK

Ch. 9 Notes -- Stoichiometry

Ch. 9 Notes -- Stoichiometry

© 2018 SlidePlayer.com Inc.

All rights reserved.

To make this website work, we log user data and share it with processors. To use this website, you must agree to our Privacy Policy, including cookie policy.

Ads by Google