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DO NOW: Find where the function f(x) = 3x4 – 4x3 – 12x2 + 5

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Presentation on theme: "DO NOW: Find where the function f(x) = 3x4 – 4x3 – 12x2 + 5"— Presentation transcript:

1 DO NOW: Find where the function f(x) = 3x4 – 4x3 – 12x2 + 5
is increasing and decreasing.

2 4.3 – Connecting f’ and f’’ with the Graph of f
HW: Pg.

3 First Derivative Test Recall that at a critical point, a function can have: A local maximum, A local minimum, or Neither. We can look at whether f’ changes sign at the critical point to decide which of the above possibilities is the case:

4 First Derivative Test (cont’d)
The First Derivative Test Suppose that c is a critical number of a continuous function f. If f’ changes from positive to negative at c, then f has a local _____________ at c. If f’ changes from negative to positive at c, then f has a local _____________ at c. If f’ does not change sign at c (that is, f’ is positive on both sides of c or negative on both sides), then f has no local maximum or minimum at c.

5 Concavity In the figure on the next slide, the
Slopes of the tangent lines increase from left to right on the interval (a,b), and so A function (or its graph) is called concave upward on an interval I if i is an increasing function on I. It is called concave downward on I if f’ is decreasing on I.

6 Concavity Concave ___________: F’ is decreasing  f’’ < 0
F’ is increasing  f’’ > 0

7 Inflection Point A point where a curve changes its direction of concavity is called an inflection point. Thus there is a point of inflection at any point where the second derivative changes sign. Concavity Test If f’’(x) > 0 for all x in I, then the graph of f is concave upward on I. If f’’(x) < 0 for all x in I, then the graph of f is concave downward on I.

8 Determining Local Max/Min
The Second Derivative Test Suppose f’’ is continuous near c. If f’(c) = 0 and f’’(c) > 0, then f has a local minimum at c. If f’(c) = 0 and f’’(c) < 0, then f has a local maximum at c.

9 Example 1 Discuss y = x4 – 4x3 with respect to Concavity,
Points of inflection, and Local maxima and minima.

10 Example 1 (solution)

11 Example 2 Discuss f(x) = x2/3(6 – x)1/3 with respect to: Concavity
Points of inflection, and Local maxima and minima.

12 Example 2 (solution)


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