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Graphs of Rational Functions

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1 Graphs of Rational Functions
2.7 Copyright © Cengage Learning. All rights reserved.

2 What You Should Learn Analyze and sketch graphs of rational functions.
Sketch graphs of rational functions that have slant asymptotes.

3 The Graph of a Rational Functions

4 The Graph of a Rational Functions
To sketch the graph of a rational function, use the following guidelines.

5 The Graph of a Rational Function

6 Example 2 – Sketching the Graph of a Rational Function
Sketch the graph of by hand. Solution: y-intercept: because g(0) = x-intercepts: None because 3  0. Vertical asymptote: x = 2, zero of denominator Horizontal asymptote: y = 0, because degree of N (x) < degree of D (x)

7 Example 2 – Solution Additional points:
cont’d Additional points: By plotting the intercept, asymptotes, and a few additional points, you can obtain the graph shown in Figure Confirm this with a graphing utility. Figure 2.46

8 Slant Asymptotes

9 Slant Asymptotes Consider a rational function whose denominator is of degree 1 or greater. If the degree of the numerator is exactly one more than the degree of the denominator, then the graph of the function has a slant (or oblique) asymptote.

10 Slant Asymptotes For example, the graph of
has a slant asymptote, as shown in Figure To find the equation of a slant asymptote, use long division. Figure 2.50

11 Slant Asymptotes For instance, by dividing x + 1 into x2 – x, you have
f (x) = x – 2 + As x increases or decreases without bound, the remainder term approaches 0, so the graph of approaches the line y = x – 2, as shown in Figure 2.50 Slant asymptote ( y = x  2)

12 Example 6 – A Rational Function with a Slant Asymptote
Sketch the graph of Solution: First write f (x) in two different ways. Factoring the numerator enables you to recognize the x-intercepts.

13 Example 6 – A Rational Function with a Slant Asymptote
Long division enables you to recognize that the line y = x is a slant asymptote of the graph.

14 Example 6 – Solution y-intercept: (0, 2), because f (0) = 2
cont’d y-intercept: (0, 2), because f (0) = 2 x-intercepts: (–1, 0) and (2, 0) Vertical asymptote: x = 1, zero of denominator Horizontal asymptote: None, because degree of N (x) > degree of D (x) Additional points:

15 Example 6 – Solution The graph is shown in Figure 2.51. cont’d


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