1. Algebra II Revision

2. Convert the following Word Equation and prove how it works. Think of a number. x Add three to it. x + 3 Multiply by ten 10(x + 3) Take away five 10(x + 3) - 5 Divide by five 10(x + 3) – 5 5 Take away the first number you thought of 10(x + 3) – 5 5- x Take away the first number again 10(x + 3) – 5 5- 2x

3. The number you are left with is… 5 Using algebra, prove why the answer is always 5? 10(x + 3) – 5 5- 2x = 10(x + 3) – 5 5- 2x 21 = 2(x + 3) – 1 – 2x = 2x + 6 – 1 – 2x = 5

4. Determine the formula a gardener would need to calculate the number of sleepers required for any size enclosure. LWS 114 126 216 228 318 2(L + W) Table the above enclosures and determine the formula.

5. The gardener is asked to build an enclosure 120 sleepers long by 80 sleepers wide – How many sleepers will he need all together? 2(L + W) = 2(120 + 80) = 2 (200) = 400 Sleepers

6. Simplify by expanding and collecting like terms: 2a 2 (3a 4 + 11a) + 3a (5a 5 – 2a 2 ) = 6a 6 + 22a 3 + 15a 6 – 6a 3 = 21a 6 + 16a 3

7. Factorise the following expression: 20ab + 16b = 4b (5a + 4) Common Factors are 4 and b

8. Simplify: - 4ab ÷ - 44a = - 4 a b ÷ - 44 a = 1b ÷ 11 1 11 = b ÷ 11

9. Simplify: = 6ab × c × 11 = 66abc = 6abc × 11 6ab × c × 11

10. Simplify: = -12a 6 b 5 × -2ab 2 = 24a 7 b 7 -12a 6 b 5 × -2ab 2

11. Simplify: = 6a + 12b – 7a +11b = 23b - a 6a + 12b – 7a +11b

12. Copy the overview for the next math topic called Statistics: Strand - CHANCE AND DATATopic – STATISTICS Duration - 5 Lessons LessonContentTextReference 1,2Interpreting graphical representations 3F – Q1,2,3 3G - Q1,2 3J – Q1,4 Frequency distribution table Reading & drawing Bar graph Line graph Section graph Pie graph Picture graph 3,4,5Calculating,identifying, and interpreting mode, median, range and mean 3LInvestigate: Central tendency using student names and name length