# Chapter 7 Algebra II Review JEOPARDY Jeopardy Review.

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Chapter 7 Algebra II Review JEOPARDY Jeopardy Review

Logarithms Exponential Growth and Decay Exponential Functions Solving Logarithmic Equations Solving Exponential Equations 200 200 200 200 200 400 400 400 400 400 600 600 600 600 600 800 800 800 800 800 1000 1000 1000 1000 1000

Logarithms 200 log3 (1/9) = A: -2 Jeopardy Review

Logarithms 400 log .001 A: -3 Jeopardy Review

Use the change of base formula to evaluate: log6 21
Logarithms 600 Use the change of base formula to evaluate: log6 21 A: Jeopardy Review

Daily Double Jeopardy Review

Using the properties of logarithms, expand log (x2y/z)
A: 2 log x + log y – log z Jeopardy Review

Write as a single logarithm:
Logarithms 1000 Write as a single logarithm: y = 4 log m + 2 log n – 3 log k A: log (m4n2/k3) S2C13 Jeopardy Review

Exponential Growth & Decay 200
Identify the percent of decay in the equation: y = 6000 (.48)x A: 52% S2C13 Jeopardy Review

Exponential Growth & Decay 400
Write the equation that models exponential growth of 6% per year with a starting population of 22,000. A: y = 22,000 (1.06)x S2C13 Jeopardy Review

Exponential Growth & Decay 600
Predict the population in the year 2006 if a countries population (in millions) is growing by 4% each year, and is modeled by the equation y = 1.4 (1.04)x where x represents the years after 1990. A: million S2C13 Jeopardy Review

Exponential Growth & Decay 800
A city’s population is modeled by the equation y = 14,000 (.98)x, where x represents the number of years after the year Predict during which year the population will decrease to 8,900. A: 2022 S2C13 Jeopardy Review

Exponential Growth & Decay 1000
In the equation: y = 13 (2.58)x, Identify Growth or decay Growth or decay factor Percent of growth or decay A: a) growth b) c) 158% S2C13 Jeopardy Review

Exponential Functions 200
Evaluate y = 2x for x = -1, 0, and 2. A: y = ½, 1, and 4 S2C13 Jeopardy Review

Exponential Functions 400
Write the equation to describe the exponential function with a base of 2, passing through the point (4,7). A: y = (7/16)(2)x S2C13 Jeopardy Review

Exponential Functions 600
Find the amount of money you have if you invest \$20,000 for 5 years at 6% compounded continuously. A: 20,000 e^(.06*5) = \$26,977.18 S2C13 Jeopardy Review

Exponential Functions 800
Find the amount of money you have if you invest \$3000 for 3 years at 5% compounded continuously. A: 3000 e (.05)(3) = \$ S2C13 Jeopardy Review

Exponential Functions 1000
You invest \$2000 in an account earning 3% interest compounded continuously. How long will it be until you have \$2500? A: = 2000 e (.03t) t = 7.44 years S2C13 Jeopardy Review

Solving Logarithmic Equations 200
2 log24 – log22 = A: log28 = 3 S2C13 Jeopardy Review

Solving Logarithmic Equations 400
S2C13 Jeopardy Review

Solving Logarithmic Equations 600
Solve for x. log 5x = 2 A: 102 = 5x x = 20 S2C13 Jeopardy Review

Solving Logarithmic Equations 800
Solve for x. ln 3 + ln x – ln 2 = 6 A: ln (3x/2) = x = S2C13 Jeopardy Review

Solving Logarithmic Equations 1000
ln x + ln (x + 3) = 2 A: ln (x2 + 3x) = x = 1.6, using quadratic formula S2C13 Jeopardy Review

Solving Exponential Equations 200
A: 7 or -7 S2C13 Jeopardy Review

Solving Exponential Equations 400
A: x = S2C13 Jeopardy Review

Solving Exponential Equations 600
A: x = 2.096 S2C13 Jeopardy Review

Daily Double

Solving Exponential Equations 800
4√m = 10 A: m = 16 S2C13 Jeopardy Review

Solving Exponential Equations 1000
A: 4x = ln 10 x = .576 S2C13 Jeopardy Review

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