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Open Day 26 - 27 luglio 2013 IDEA Creator Experimental Creative Culture.

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Presentation on theme: "Open Day 26 - 27 luglio 2013 IDEA Creator Experimental Creative Culture."— Presentation transcript:

1 Open Day 26 - 27 luglio 2013 IDEA Creator Experimental Creative Culture

2 F3 C F2 F1 Rad/s F4 Transmission belt 1 2 3 4 Classic Situation The engine power is spread over the different-diameter pulleys F x b x Rad/s

3 D b b/i LEVA d d/ i F’ = F x i 2 P’ = Fxi 2 x b/i x rpm = P x i C D C’ F F’ LEVA F’ = F x i P = P’ TURBINA CCS     F F’ Rpm Classic lever Double lever

4 Classic situation ENGINE ALTERNATOR Here is an alternator put together directly with the engine; in this case the engine power is equal to the alternator power. This situation is the same as the CLASSIC situation C ALTERNATOR A B movement To me this situation is not the same as the previous one; here the power arm of the engine is introduced (AC), which is reduced on the alternator (A’C), obtaining on this one an improved power. SHAFT A’ B’ FULCRUM ENGINE Improved turbine CCS

5  D D/i F F’ B F M A P R P’ R’  D D/i F’ F B F M A P R P’ R’ 1 RM RM’ WO/2005/047695 EP 2489875

6  D F’ F B M A P R P’ RM RM’ EP 2489875 F Frizione (friction)

7 Turning engine Turning alternator Fixed wheel(1) C The shaft hooks the engine And the alternator, plus it pivots on C A B Engine power = Alternator power F x b x rad/s x AC = F’ x b’ x rad’/s x CB when AC=CB ……where as opposed to the “classic situation” the power moment is introduced compared to the fulcrum C D D’ The engine and the alternator are not fixed but they turn around The fixed wheel : in one second the engine goes from A to D and the alternator from B to D’

8 Engine power < Alternator power Let’s suppose that AC/A’C = 2 and let’s balance the Power moments compared to the fulcrum C Engine Power Alternator Power F x b x rad/s x AC = F’ x b’ x rad’/s x A’C F x b x rad/s x AC = F’ x b’ x rad’/s x AC/2 Reducing I obtain that the alternator power is the same as: F’ x b’ x rad’/s = 2 x F x b x rad/s On the red fixed wheel a power is discharged; this is equal to: Engine power x AC/ (AC/2) = Engine power x 2 Turning engine on Fixed wheel1) Fixed wheel on which The engine pivots (1) Turning alternator which engaged In the red fixed wheel A C B Fixed wheel on which The alternator pivots (2) A’ B’ The shaft hooks the engine And the alternator, plus it pivots on C

9 Turning engine Fixed wheel on which the engine pivots (1) and concentric wheel on which the engine is set (1’); the engine turns and Spreads the motion to the red Wheel (2) thanks to a wheel(1’’). The red wheel (2) spreads The motion to the alternator. Fixed alternator engages In the red wheel A C B The Gear wheel Turns for the wheel (1’’) P engine => Kinetic Energy Mass=> P alternator m g V / ½ m V 2 / s 2 m x g x V F F1 F2 Transferred mass because of the transformation Of the mechanical energy to kinetic energy

10 Turning engine Fixed alternator Connected with the red wheel A C B m’ m m m x i 2 x g x V/i = alternator Power > engine Power Fixed wheel on which the engine pivots (1) and concentric wheel on which the engine is set (1’); the engine turns and Spreads the motion to the red Wheel (2) thanks to a wheel(1’’). The red wheel (2) spreads The motion to the alternator. ½ m V 2 / s = ½ m’ V’ 2 / s m’ = m x i 2

11 A C B m m A C B A’ B’ CONVENIENCE DECISION If 2 g / V engine/ s > 1 the arrangement B is more convenient than A Arrangement B Arrangement A

12 1 ABM M M RM A R’ RM’ 1 AB M M M RM A RM’ RP A A R R Assetto 1

13 1 AB M M M RM R’ R R RP 1 A RM’ A Assetto 2

14 1AB RP A RM’ R RM M A M M Assetto 3

15 AB’ F F’ C C/i D D/i b b/i       AB R R’ Spostamento angolare Assetto 4 F x b x rad/s x C x D = F’ x b’ x rad’/s x C/i x D/i P alternatore = P motore x i 2

16 AB’ F F’ C C/i D D/i b b/i       AB R R’ Spostamento angolare Assetto 5 P alternatore = m x g x i 3 x V/ i

17 AB’ F F’ C D b b/i     AB R Spostamento angolare Assetto 6 P alternatore > P motore ed è funzione anche della componente C RM’ Frizione

18 Turbina perfezionata CCS

19 motore riduttore alternatore Turbina perfezionata CCS

20

21 Grazie per l’attenzione Alessandro Leghi Turbina perfezionata CCS Cultura Creativa Sperimentale Experimental Creative Culture

22 employer/work Pays the employees in € Wage € Bank CCS € are transformed in vouchers in GREEN SOCIAL virtual money Euros are moltiplied for a value equal/greater than 1 Depending on the green social usefulness for which they are spent. The vouchers have a face validity, they have a due date and an end use They have an UEI value = € x green social coefficient >= 1 Buisnessmen pay the UEI off in CCS banks Transforming them in € to pay the production. Wages,green social services are paied and the “USEFUL” investment is rewarded. green social shopping With vouchers in UEI 1 2 3 4 5 6 € circulates again Depending on the social green system HOW GREEN SOCIAL MONEY WORKS 7


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