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Applications of Inverse Functions Lesson 2.11. Example #1 – Part A In words: The total cost is 7 dollars plus 4 dollars for every thousand gallons used.

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Presentation on theme: "Applications of Inverse Functions Lesson 2.11. Example #1 – Part A In words: The total cost is 7 dollars plus 4 dollars for every thousand gallons used."— Presentation transcript:

1 Applications of Inverse Functions Lesson 2.11

2 Example #1 – Part A In words: The total cost is 7 dollars plus 4 dollars for every thousand gallons used. Number of gallons used (in thousands) Monthly cost (in dollars)

3 Example #1 – Part B Number of gallons used (in thousands) Monthly cost (in dollars)

4 Summary of Part A and Part B Part APart B Independent Variable Dependent Variable inverse functions independent dependent

5 An easier way- Using Inverses Since these functions are inverses, use one to find the other: Monthly cost, depending on gallons used: Gallons used, depending on monthly cost: SADMEG

6 Check for Understanding  What was the first step we took to solving part a?  How did we identify the independent and dependent variables?  How did we know that c(x) and g(x) were inverses?  How did we find c(x)?

7 Check for Understanding  Turn and talk with your partner: Describe the steps to solve this kind of problem.

8 Summary In the summary box, write a summary in your notes of the steps to solve this kind of problem.

9 Practice # of months watering Current height of flower

10 Practice # of months watering Current height of flower

11 Examples with specific variables.

12  Stop and jot: In your summary box, write a summary of the steps we took  Turn and talk – share your summary

13 Independent Practice

14 Reminders  Preview HW  Why is it important to pack up quickly?


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