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Entry task Socractive Multiple Choice

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Presentation on theme: "Entry task Socractive Multiple Choice"— Presentation transcript:

1 Entry task Socractive Multiple Choice
A – Yes, continue to make the assignments online as much as possible B – No, I don’t want any more online assignments C – A even mix is good

2 4.6 Congruence in Right Triangles
Learning Target I can prove triangles congruent by using Hypotenuse – Leg Theorem. (HL) Success Criteria: I understand HL and can use it correctly in a proof

3 Conditions for HL Theorem:
There are two right triangles The triangles have congruent hypotenuse There is one pair of congruent legs

4 Example 4A: Applying HL Congruence
Determine if you can use the HL Congruence Theorem to prove the triangles congruent. If not, tell what else you need to know. According to the diagram, the triangles are right triangles that share one leg. It is given that the hypotenuses are congruent, therefore the triangles are congruent by HL.

5 Example 4B: Applying HL Congruence
This conclusion cannot be proved by HL. According to the diagram, the triangles are right triangles and one pair of legs is congruent. You do not know that one hypotenuse is congruent to the other.

6 Check It Out! Example 4 Determine if you can use the HL Congruence Theorem to prove ABC  DCB. If not, tell what else you need to know. Yes; it is given that AC  DB. BC  CB by the Reflexive Property of Congruence. Since ABC and DCB are right angles, ABC and DCB are right triangles. ABC  DCB by HL.

7 At your tables Proof Statements | Reasons PS = QR 1)Given
PR = PR ) reflexive <QPR and <PRS are rt 3) Given PRS = PRQ 4) HL

8

9 Assignment Homework – p. 261 #1-13 odds, 16-18, Challenge - # 28

10 Exit Slip Identify the postulate or theorem that proves the triangles congruent. HL ASA SAS or SSS

11 Do Now: Discuss a Plan with your group!
4. Given: FAB  GED, ABC   EDC, AC  EC Prove: ABC  EDC

12 Lesson Quiz: Part II Continued
5. ASA Steps 3,4 5. ABC  EDC 4. Given 4. ACB  EDC; AC  EC 3.  Supp. Thm. 3. BAC  DEC 2. Def. of supp. s 2. BAC is a supp. of FAB; DEC is a supp. of GED. 1. Given 1. FAB  GED Reasons Statements


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