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Base Theory Concepts Arrhenius Concept: base produces OH- in water
Bronsted-Lowery Model: base is a H+ acceptor Strong Hydroxide Bases Alkali Metal Hydroxides: NaOH, KOH, etc… Completely Dissociated in Water NaOH Na OH- K = very large Alkaline Earth Hydroxides: Ca(OH)2, Mg(OH)2, etc… Not very soluble in water What does dissolve is completely dissociated Ca(OH) Ca OH K = very large Example: pH of 0.05 M NaOH
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Non-Hydroxide Bases (Weak Bases)
Any atom with a lone pair of electrons can accept a proton = base Ammonia in water: Other amine molecules are also bases The general base equation B H2O BH OH- Strong Base: equilibrium lies far to the right ([OH-] ≈ [B]0) Weak Base: equilibrium lies far to the left ([OH-] << [B]0) a) Calculations are similar to weak acids Kb = 1.8 x10-5 conjugate base acid conjugate acid base
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Polyprotic Acids Example: pH of 15.0 M NH3 Kb = 1.8 x 10-5
We can find [H+] from KW = [H+][OH-] = 1 x 10-14 or pH pOH = 14 Percent dissociation still means the same thing The 5% rule for approximations: x/[B] x 100% < 5% Example: pH of 1.0 M methylamine Kb = 4.38 x 10-4 Polyprotic Acids Carbonic Acid is a diprotic acid Polyprotic means there are more than one ionizable proton Carbonic acid is the acid that helps maintain body pH H2CO3 H2CO H HCO3- HCO H CO32- 3) Ka1 and Ka2 stand for the loss of the first and second protons, respectively
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Usually Ka1 >> Ka2 As (-) charge builds up, it is harder to remove the next proton H+ from the first ionization forces the second ionization to the left We can usually ignore all but the first ionization in calculations Phosphoric Acid is a triprotic acid Ionizations H3PO H H2PO4- Ka = 7.5 x 10-3 H2PO H HPO42- Ka = 6.2 x 10-8 HPO H PO Ka = 4.8 x 10-13 Ka1 >> Ka2 >> Ka3 Example: pH of 5.0 M H3PO4, and the concentrations of all of the phosphoric acid derived species Use Ka1 only to find [H+] and the pH Then, [H+] = [H2PO4-] [H3PO4] = [H3PO4]0 - [H+] Find [HPO42-] and [PO43-] from what is already calculated and Ka2, Ka3
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Sulfuric Acid is a unique diprotic acid
The first ionization of sulfuric acid is a strong acid (Ka1 = large) H2SO H HSO4- The second ionization of sulfuric acid is a weak acid HSO H SO Ka2 = 1.2 x 10-2 Example: pH of 1.0 M H2SO4 Assume complete dissociation of the first proton Use the equilibrium calculation on Ka2 [H+]0 does not = 0 because of Ka1 [H+]0 = 1.0 M Approximate 1 + x ≈ 1 in this case (5% rule says this is ok) When [H2SO4] > 1.0 M, you can ignore Ka2 Example: pH of 0.01 M H2SO4 The 5% rule tells us we can’t ignore Ka2 in this case We must use the quadratic equation to solve for x When H2SO4 < 1.0 M, we can’t ignore Ka2
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Acid-Base Properties of Salts
A) Simple Salts 1) Salt = ionic compound = one that completely ionizes in water 2) Some salts have no effect on pH Cations of strong bases have no effect on pH Na+, K+, etc… These cations have no affinity for OH- in water Anions of strong acids have no effect on on pH Cl-, NO3-, etc… These anions have no affinity for H+ in water Solutions of these combined ion salts have pH = 7.00 B) Basic Salts Salts containing the conjugate base of a weak acid produce basic solutions The conjugate base must be strong if the acid is weak, so it must have a strong affinity for H+, which will affect the pH of a solution Sodium Acetate Example NaC2H3O Na C2H3O2- C2H3O H2O HC2H3O OH-
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How do we find Kb for the conjugate base of a weak acid?
For any weak acid and its conjugate base, Ka x Kb = KW Kb = KW / Ka = 1 x / 1.8 x 10-5 = 5.6 x for acetate Example: pH of 0.30 M NaF Ka for HF = 7.2 x 10-4 Base Strength in Water Any base in water must compete with the hydroxide anion for protons Hydrocyanic acid example: HCN H2O H3O CN- Ka = 6.2 x 10-10 weak acid strong base (compared to H2O) CN H2O HCN OH- Kb = KW / Ka = 1.6 x 10-5 weak base strong acid (compared to OH-) OH- > CN- > H2O
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Acidic Salts Salts having the conjugate acid of a weak base produce acidic solutions Ammonium chloride = NH4Cl NH Cl- NH NH H+ Since ammonia is a weak base, ammonium is “strong” acid and will effect pH Example: pH of 0.1 M NH4Cl Kb = 1.8 x 10-5 Find Ka from KW Make sure the conjugate acid is stronger than water or it will have no effect Highly charged metal ions can also be acidic AlCl H2O Al(H2O) Cl- Al(H2O) H2O Al(H2O)5(OH) H3O+ The higher the metal’s charge the more acidic Example: pH of 0.01 M AlCl3 Ka = 1.4 x 10-5
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Salts containing both acidic and basic components
NH4C2H3O NH C2H3O2- The calculations for these compounds are complex We can, however, at least decide if the solution is acidic or basic If Ka > Kb, the solution will be acidic If Kb > Ka, the solution will be basic If Ka = Kb, the solution will be neutral Example: Will the following solutions be acidic or basic? NH4C2H3O NH4CN Al2(SO4)3
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Acid-Base Properties and Molecular Structure
Polarity Not all H containing molecules are acidic CHCl H CCl3- Strong, nonpolar bonds don’t dissociate easily Polar X—H bonds are easily dissociated (acidic) H—Cl is a polar bond H—OH is a polar bond Bond strength also plays a part in acidity Hydrohalide Polarity: H—F > H—Cl > H—Br > H—I Bond Strength (kJ.mol) Acidity weak strong strong strong Oxyacids: the more O on the central atom, the stronger the acid in a series Electronegative Oxygens remove electrons from the center atom This polarizes and weakens the O—H bond even more HClO4 > HClO3 > HClO2 > HClO H2SO4 > H2SO3
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H—O—X Molecules The more electronegative X is, the more acidic the molecule is Electronegative X removes electrons from the H—O bond Acidity: H—O—Cl > H—O—Br > H—O—I > H—O—CH3 Electronegativity: Acid-Base Properties of Oxides A generic oxide can be represented as X—O If X—O is a strong and covalent bond, the oxide will be acidic in water H—O—X H O—X If X is electronegative, like O, it should form a strong covalent O—X bond If X—O is weak and ionic, the oxide will be basic in water H—O—X X OH- NaOH Na OH- The X atom in these oxides is usually not electronegative (Na+) Examples of Acidic Oxides SO H2O H2SO H HSO3- CO H2O H2CO H HCO3-
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Lewis Acid-Base Definition
Examples of Basic Oxides CaO H2O Ca(OH) Ca OH- K2O H2O KOH K OH- Lewis Acid-Base Definition Definitions Lewis Acid = an electron pair acceptor Lewis Base = an electron pair donor Example: H :NH NH4+ This model includes the other acid-base concepts This model accounts for many other chemical reactions that the others don’t BF :NH H3N:BF3 Lewis acid Lewis Base Lewis Acid-Base complex Lewis acid Lewis Base Lewis Acid-Base complex
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AlCl H2O Al(H2O) Cl- Example: Identify Lewis Acid and Lewis Base Ni NH Ni(NH3)62+ H H2O H3O+ Summary of Acid-Base Problem Solving 1. List major species in solution 2. Look for reactions that go to completion a. concentration of product b. major species left 3. Identify acids and bases 4. Solve the equilibrium problem, check the approximation, find pH
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