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The Energy Storage Elements
CHAPTER 5 The Energy Storage Elements
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Q = CV The capacitor is a device that stores charge
The charge and the applied voltage are related by the capacitance of the capacitor as Q = CV For a time varying source v(t) we have q(t) =C v(t) The unit of capacitance is coulomb/volt or Farad For plates if size A (m2) separated by distance d(m) with air in between the capacitance is: C = 8.84×10¹²ֿ A/d F Figure 5.1 A parallel-plate capacitor.
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Passive sign convention
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Capacitor Energy The instantaneous power delivered to the capacitor is: The energy stored in a capacitor at a particular time can be found by: Assuming capacitor voltage is zero at
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Example 5.1 A voltage source is applied to a 5-F capacitor as shown.
Sketch the capacitor current and the stored energy as a function of time.
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Example 5.2 A current source is applied to a 5-F capacitor.
Sketch the capacitor voltage as a function of time.
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The capacitor voltage is related to area Under current source.
For example area at t = 1 s is Area of Triangle is (1)(10)=10 V(1s)=10/5= 2V. For example area at t=3 s is = 25 hence V(3s)=25/5= 5V.
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5.1.1 Capacitors in Parallel
The terminal voltage is equal to the voltage of each capacitors v(t) = v1(t) = v2(t)=….=vn(t) The current entering the combination is the sum of currents of each capacitor i(t) = i1(t)+i2(t)+…+in(t) From relation
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5.1.1 Capacitors in Series v(t) = v1(t) + v2(t) + …. + vn(t)
i(t) = i1(t) = i2(t) = … = in(t)
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The Inductor A device that stores energy in its magnetic field
The current produces a magnetic field round the wire
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The relation between the voltage and current of inductor is
This relation can be inverted to yield
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The energy stored in an inductor
The instantaneous power of an inductor Thus the energy stored in an inductor is
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Example 5.3 A current source is applied to a 5-H inductor as shown. Sketch the voltage across the inductor versus time.
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Example 5.4 A voltage source is applied to a 5-H inductor as shown. Sketch the inductor current versus time.
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Inductors in Series
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Inductors in Parallel
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v(t)=2t <t<1 V(t)= -2t <t<2 iL=t2/ <t<1 iL= -t2/2+2t <t<2
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