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MgO has more lattice energy than NaF
the energy needed to completely separate an ionic solid into gaseous ions proportional to ionic charges and inversely proportional to ionic radii. MgO has more lattice energy than NaF Mg2+ O Na+ F- stronger bond NaF has more lattice energy than KCl smaller atoms larger atoms Multiple Bonds In many covalent bonding situations, multiple chemical bonds exist — more than one pair of electrons shared electron
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In general, the more polar the bond, the stronger it is
Electronegativity and Bond Polarity the difference in electronegativities between the two atoms bonded indicates the polarity of the bond The more electroneagtive of the two atoms is always the atom that possesses the slightly negative charge In general, the more polar the bond, the stronger it is
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P = 5 Cl = 7 X 1 = X 3 = + This is your special number 26 .. .. Cl .. .. .. .. .. Cl .. P Cl .. .. PCl3
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H = 1 C = 4 X 1 = N = 5 X 1 = + X 1 = This is your special number 10 .. .. H C N .. HCN
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Br = 7 O = 6 X 1 = 7 This is your special number X 3 = + 25 + 1 = 26 Ion has a negative 1 charge .. - .. O .. .. .. .. .. O Br O .. .. .. BrO3-
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Br = 7 O = 6 This is your special number X 3 = 18 .. .. .. .. O O O .. .. .. .. .. .. .. O O O .. .. .. O3
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C = 4 O = 6 X 1 = 4 This is your special number 2- .. O .. X 3 = + .. .. .. .. O C O 22 .. + 2 = 24 .. Ion has a negative 2 charge .. 2- .. .. 2- O .. .. O .. .. .. .. .. .. .. O C O .. .. .. O C O .. .. CO32-
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Cl = 7 O = 6 X 1 = 7 This is your special number X 2 = + That’s odd!! 19 double check your math .. .. .. .. .. O Cl O .. .. . ClO2
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.. .. .. .. . NO N O N = 5 O = 6 X 1 = 5 This is your special number
+ That’s odd!! 11 double check your math .. .. .. N O .. . NO
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N = 5 O = 6 X 1 = 5 This is your special number X 2 = + That’s odd!! 17 double check your math .. . .. .. .. O N O .. .. NO2
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Typically you’d rectify this with . . . . . .
B = 3 F = 7 X 1 = X 3 = + This is your special number 24 .. .. F .. .. .. .. .. F .. B F .. Typically you’d rectify this with a double bond But Double bonds won’t form with hydrogen or halogens BF3
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P = 5 Cl = 7 X 1 = X 5 = + This is your special number 40 .. .. .. Cl .. .. .. Cl .. Cl .. .. P .. .. .. .. Cl Cl .. .. PCl5
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S = 6 F = 7 X 1 = X 4 = + This is your special number 34 .. .. F .. .. .. .. .. .. F .. S F .. .. .. .. F SF4
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As = 5 F = 7 X 1 = 5 This is your special number X 6 = + 47 + 1 = 48 Ion has a negative 1 charge .. - .. .. .. F .. .. F .. .. F .. As .. .. .. .. .. F F .. .. F .. .. AsF6-
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I = 7 Cl = 7 X 1 = This is your special number X 4 = + 35 + 1 = 36 .. .. - Cl .. .. .. .. .. .. .. Cl .. I Cl .. .. .. Cl .. ICl4-
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To expand the octet requires d-orbitals . . . . . . . .
There are no 1d or 2 d orbitals!
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