1. weight mass Fg = 98 N m = 10 kg Fg = 11N m = 1.12 kg Fg = 2500 N1)
weight
mass
Fg = 98 N
m = 10 kg
Fg = 11N
m = 1.12 kg
Fg = 2500 N
m = kg
Fg = 58.8 N
m = 6 kg
m = 1500 kg 2)
Fg on earth = 1.47 x 104 N
Fg on moon = 2.4 x 103 N
Fg in space = 0 N

2. Given: m = 600 kg g = 9.8 m/s2 Fg = 5880 N vi = 30 m/s vf = 0 m/s3)
Given:
m = 600 kg
g = 9.8 m/s2
Fg = 5880 N FN
vi = 30 m/s
vf = 0 m/s
Δd = 70 m
Fbrakes Fg
vf2 = vi2 + 2ad
F = Fbrakes
F = ma
ma = Fbrakes
(600) (6.4) = Fbrakes a
(0)2 = (30)2 + 2a(70)
a = m/s2
Fbrakes = 3840 Newtons

3. Given: g = 32 ft/s2 Fg = 50 lbs m = 1.56 slug (a) (b) Fscale Fscale a4)
m = 1.56 slug
(a)
(b)
Fscale
Fscale a
(e)
a = 0 Fg Fg
Fscale a
(c)
(d) Fg
Fscale
Fscale a
a = 0 Fg Fg

4. Fscale = 50 lbs Fscale = 56.2 lbs Fscale = 0.0 lbs Fscale = 43.8 lbs
F = Fscale - Fg
F = ma
ma = Fscale - Fg
(1.56) (0) = Fscale - 50
F = Fscale- Fg
F = ma
ma = Fscale - Fg
(1.56) (4) = Fscale - 50
(b)
(a)
Fscale = 50 lbs
Fscale = 56.2 lbs
F = Fg - Fscale
F = ma
ma = Fg - Fscale
(1.56) (4) = 50 - Fscale
(c)
(d)
same as (a)
F = Fg- Fscale
F = ma
ma = Fg - Fscale
(1.56) (32) = 50 - Fscale
(e)
Fscale = 0.0 lbs
Fscale = 43.8 lbs

5. vi = 0 m/s a = - 9.8 m/s2 vf2 = vi2 + 2ad Given: Δd = - 5.0 m5)
vi = 0 m/s
a = m/s2
Δd = m
vf = ?
(a)
vf2 = vi2 + 2ad
Given:
m = 10.21kg
g = 9.8 m/s2
(vf)2 = (0)2 + 2(-9.8)(-5)
vf = m/s
Fg = 100 N
(b)
Fground
vi = m/s
vf = 0 m/s
Δd = -7.0 cm = m
a = ? a Fg
F = Fground - Fg
F = ma
ma = Fground - Fg
(10.21) (700) = Fground - 100
vf2 = vi2 + 2ad
(0)2 = (- 9.9)2 + 2(a)(-0.07)
a = 700 m/s2
Fground = N

6. Use kinematics to solve for acc draw the free body diagram solve for f
F = Fengine - f
F = ma
ma = Fengine -f
(714.3) (60) = 4.8 x f
Use kinematics to solve for acc draw the free body diagram solve for f 6)
Given:
Fg = 7000 N
g = 9.8 m/s2
Fengine = 4.8 x 104 N
m = kg a FN
vi = 0 m/s
t = 2 s
Δd = 120 m
Fengine f Fg
d = vit +½at2
120 = ½a(2)2
f = 5142 Newtons
a = 60 m/s2