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Law of Cosines Ref page 417.

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Presentation on theme: "Law of Cosines Ref page 417."— Presentation transcript:

1 Law of Cosines Ref page 417

2 Definition: Oblique Triangles
An oblique triangle is a triangle that has no right angles. C B A a b c To solve an oblique triangle, you need to know the measure of at least one side and the measures of any other two parts of the triangle – two sides, two angles, or one angle and one side. Copyright © by Houghton Mifflin Company, Inc. All rights reserved. Definition: Oblique Triangles

3 Solving Oblique Triangles
The following cases are considered when solving oblique triangles. Two angles and any side (AAS or ASA) A C c A B c 2. Two sides and an angle opposite one of them (SSA) C c a 3. Three sides (SSS) a c b c a B 4. Two sides and their included angle (SAS) Copyright © by Houghton Mifflin Company, Inc. All rights reserved. Solving Oblique Triangles

4 Definition: Law of Cosines
The last two cases (SSS and SAS) can be solved using the Law of Cosines. (The first two cases can be solved using the Law of Sines.) Law of Cosines Standard Form Alternative Form Copyright © by Houghton Mifflin Company, Inc. All rights reserved. Definition: Law of Cosines

5 Example: Law of Cosines - SSS
Find the three angles of the triangle. C B A 8 6 12 117.3 26.4 36.3 Find the angle opposite the longest side first. Law of Sines: Copyright © by Houghton Mifflin Company, Inc. All rights reserved. Example: Law of Cosines - SSS

6 Example: Law of Cosines - SAS
B A 6.2 75 9.5 Solve the triangle. 67.8 9.9 Law of Cosines: 37.2 Law of Sines: Copyright © by Houghton Mifflin Company, Inc. All rights reserved. Example: Law of Cosines - SAS

7 Definition: Heron’s Area Formula
Given any triangle with sides of lengths a, b, and c, the area of the triangle is given by 5 10 8 Example: Find the area of the triangle. Copyright © by Houghton Mifflin Company, Inc. All rights reserved. Definition: Heron’s Area Formula

8 Application: Law of Cosines
Two ships leave a port at 9 A.M. One travels at a bearing of N 53 W at 12 mph, and the other travels at a bearing of S 67 W at 16 mph. How far apart will the ships be at noon? N At noon, the ships have traveled for 3 hours. 53 43 mi 36 mi Angle C = 180 – 53 – 67 = 60 c 60 C 48 mi 67 The ships will be approximately 43 miles apart. Copyright © by Houghton Mifflin Company, Inc. All rights reserved. Application: Law of Cosines


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