1. Objective
I will analyze and interpret data
So that I can show the relationship between acceleration, velocity, and time
By highlighting cause and effect

2. Acceleration

3. Acceleration is defined as the change in velocity over time.

4. Any time an object's velocity is changing, we say that the object is accelerating.
Acceleration

5. Acceleration
This brings up an important point. In common language, when things speed up, we say that they are "accelerating," and, when they slow down, we say that they are "decelerating."

6. Acceleration
However, in the language of physics, we say that both objects are accelerating, not because both objects are speeding up, but because both objects have changing velocities.

7. Acceleration
POSITIVE ACCELERATION (SPEEDING UP)

8. Acceleration
* NEGATIVE ACCELERATION (DECELERATING) SLOW DOWN

9. An object will accelerate when there is a net (or unbalanced) force acting upon it. Acceleration is a vector and is in the same direction as the net force.

10. The first car is accelerating (speeding up) to the right
The first car is accelerating (speeding up) to the right. Its velocity has increased from 30km/h to 60km/h.

11. The second car is decelerating (slowing down) to the left
The second car is decelerating (slowing down) to the left. Its velocity has decreased from 60km/h to 0km/h. The direction of the acceleration (in this case deceleration) is to the left as a net force in this direction causes the car to slow down. If the direction to the right is labeled as the positive + direction, then left is the negative - direction, then you would write this deceleration with a negative value. E.g. -2.0m/s2

12. The cyclist below is accelerating
The cyclist below is accelerating. His velocity is increasing by 1 m/s each second. Therefore we can say that he is accelerating at a rate of one meter per second per second = 1 m/s2.

13. Calculating acceleration involves dividing velocity by time — or in terms of units, dividing meters per second [m/s] by second [s]. Dividing distance by time twice is the same as dividing distance by the square of time. Thus the SI unit of acceleration is the meter per second squared.
Units

14. We can think of acceleration as doing two things at once
We can think of acceleration as doing two things at once. We are still moving across a distance over a time, but we are also increasing how fast we are doing it. We are multi-tasking to arrive sooner, so we have to multiply the time x time to calculate the correct numerical value for our acceleration.
Units

15. Units explained
V= m/s
A= v/t = m/s/s = m/s x 1/s = m / s x s =m / s2
And the result is meters per second squared

16. Acceleration is defined as the change in velocity over time.

17. Acceleration is defined as the change in velocity over time.
final velocity – initial velocity
time
acceleration =

18. Acceleration is defined as the change in velocity over time.
Vf - Vi t
a =

19. A go-cart started from the top of a hill at 5 meters per second
A go-cart started from the top of a hill at 5 meters per second. At the bottom of the hill it ended up with a speed of 35 meters per second 6 seconds later. What was the acceleration of the go-cart?
5 m/s
Step 1 Read the problem. Draw a picture.
top
Formula
Plug-in
Answer
Vf =
In 6 s
Vi=
t =
a =
bottom
35 m/s

20. A go-cart started from the top of a hill at 5 meters per second
A go-cart started from the top of a hill at 5 meters per second. At the bottom of the hill it ended up with a speed of 35 meters per second 6 seconds later. What was the acceleration of the go-cart?
Step 2 Write down what you know. What are you trying to find?
Start:
initial Velocity
final velocity – initial velocity
5 m/s
acceleration =
top
time
Vf =
35 m/s
6 s
Formula
Plug-in
Answer
Vi=
5 m/s
t =
6 s
a = ?
Finish:
final Velocity
bottom
35 m/s

21. A go-cart started from the top of a hill at 5 meters per second
A go-cart started from the top of a hill at 5 meters per second. At the bottom of the hill it ended up with a speed of 35 meters per second 6 seconds later. What was the acceleration of the go-cart?
top
Step 3 Set up the formula.
Start:
initial Velocity
5 m/s
Vf - Vi t
6 s
Vf =
35 m/s
Formula
Plug-in
Answer
Vi=
5 m/s
Vf - Vi t
t =
6 s
a = ?
Finish:
final Velocity
bottom
35 m/s

22. Step 4 Plug-in the numbers. Solve.
A go-cart started from the top of a hill at 5 meters per second. At the bottom of the hill it ended up with a speed of 35 meters per second 6 seconds later. What was the acceleration of the go-cart?
Step 4 Plug-in the numbers. Solve.
Start:
initial Velocity
5 m/s
top
Vf =
35 m/s
6 s
Formula
Plug-in
Answer
Vi=
5 m/s
Vf - Vi t
35m/s – 5 m/s
30 m/s
5 m/s2
t =
6 s = 6s
6 s
a =
5 m/s2
Finish:
final Velocity
bottom
35 m/s

23. Think Differently About Acceleration
1. Consider a car moving at a constant speed of 55 mph while turning in a circle.
Constant Speed of 55 mph
2. The car's velocity is not constant, even though the speed is constant.
3. WHY? This is because the direction of motion is constantly changing while the car is turning around the track.
4. Since the direction is changing, even though the speed is not, the velocity is changing (velocity involves both speed and direction).

24. Acceleration https://www.youtube.com/watch?v=vxFYfumAAlY