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Punnett Practice A cross between 2 heterozygous plants yields 1252 offspring. How many are dominant and how many are recessive?

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Presentation on theme: "Punnett Practice A cross between 2 heterozygous plants yields 1252 offspring. How many are dominant and how many are recessive?"— Presentation transcript:

1 Punnett Practice A cross between 2 heterozygous plants yields 1252 offspring. How many are dominant and how many are recessive?

2 Answer 313 recessive 939 dominant

3 Punnett Practice #2 A cross between a homozygous recessive parent and a heterozygous parent yields 350 dominant offspring. How many recessive would you expect? What is the total number of offspring?

4 Answer 350 recessive 700 total

5 Punnett Practice #3 Two unknown parents cross and produce 36 offspring. 9 of them are homozygous dominant, 18 of them are heterozygous dominant, 9 of them are homozygous recessive. What is the genotype of the parents?

6 Both parents are heterozygous
Answer Both parents are heterozygous

7 Punnett Practice #4 If a pea plant that is heterozygous for 2 traits (tall and purple) is crossed with a plant that is homozygous recessive (short and white), what portion of the 9,822 peas that are produced would yield plants that are tall and white?

8 Tall and white is T_pp That’s 1/4 of 9822 Which is 2,455.5
Answer Tall and white is T_pp That’s 1/4 of 9822 Which is 2,455.5 or about 2456

9 Punnett Practice #5 If a pea plant that is heterozygous for 2 traits (Tall and purple) is self pollinated, what portion of the 9822 offspring would be tall and white?

10 Answer Tall and white is T_pp. That’s 3/16 of 9822 Which is 1,841.6
or about 1842.


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