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Lesson 6.7 Recursive Sequences

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1 Lesson 6.7 Recursive Sequences
Topic/Objective: To write terms in a recursive sequence. To recursive rules for sequences To write explicit rules Explicit rule: gives π‘Ž 𝑛 as a function of the term’s position number n in a sequence. For example: in the sequence 4, 6, 8, 10… the explicit rule is π‘Ž 𝑛 =2n+2 Recursive Rule: gives beginning term and a recursive equation that tells how π‘Ž 𝑛 is related to preceding terms.

2 Recursive Equation for an Arithmetic Sequence
π‘Ž 𝑛 = π‘Ž π‘›βˆ’1 +𝑑 where d is the common difference EX: Write the first 5 terms of the sequence when π‘Ž 1 = 4 with a recursive equation of π‘Ž 𝑛 = π‘Ž π‘›βˆ’1 +3 π‘Ž 1 =4 π‘Ž 2 =7 π‘Ž 3 =10 π‘Ž 4 =13 π‘Ž 5 =16 Arithmetic: You can find each term if you know the previous term

3 Recursive Equation for a geometric sequence
π‘Ž 𝑛 =π‘Ÿβˆ™ π‘Ž π‘›βˆ’1 where r is the common ratio Write the first 5 terms of the sequence where π‘Ž 1 =2 and π‘Ž 𝑛 =3 π‘Ž π‘›βˆ’1 π‘Ž 1 =2 π‘Ž 2 =6 π‘Ž 3 =18 π‘Ž 4 =54 π‘Ž 5 =162

4 Write the recursive rule for a sequence
-14, -6, 2, 10, 18 π‘Ž 1 = Common difference is 8 π‘Ž 𝑛 = π‘Ž π‘›βˆ’1 +𝑑 π‘Ž 1 =βˆ’14, π‘Ž 𝑛 = π‘Ž π‘›βˆ’1 +8

5 Write the recursive rule for a sequence
128, 64, 32, 16, 8 π‘Ž 1 = Common ratio is .5 π‘Ž 𝑛 =π‘Ÿβˆ™ π‘Ž π‘›βˆ’1 π‘Ž 1 = 128, π‘Ž 𝑛 =.5βˆ™ π‘Ž π‘›βˆ’1

6 translating between Recursive and Explicit Rules
EX: Write an explicit rule for the given recursive rule. π‘Ž 1 =3, π‘Ž π‘›βˆ’1 +5 Sequence: , 8, 13, 18 Use the sequence to write explicit rule. π‘Ž 𝑛 = π‘Ž 1 + π‘›βˆ’1 𝑑 π‘Ž 𝑛 = 3 +(n – 1)5 π‘Ž 𝑛 = 3 + 5n – 5 π‘Ž 𝑛 =5π‘›βˆ’2

7 Write a recursive rule for the explicit Rule.
π‘Ž 𝑛 =βˆ’3𝑛+1 Sequence: -2, -5, -8, -11 Use Sequence to write recursive rule. π‘Ž 1 =βˆ’ π‘Ÿ= βˆ’3 π‘Ž 1 =βˆ’2, π‘Ž 𝑛 = π‘Ž π‘›βˆ’1 βˆ’3


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